Download Problem 4.24 Find the value of υo in the circuit in Fig. P4.24

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Problem 4.24 Find the value of υo in the circuit in Fig. P4.24.
4 kΩ
6 kΩ
6 kΩ
2A
_
+
υ0
2 kΩ
5V
+
_
Figure P4.24: Circuit for Problem 4.24.
Solution: Converting the input current source into a voltage source leads to
4 kΩ
6 kΩ
2 kΩ
4V
+
_
6 kΩ
υ1
υn
5V
_
+
υo
+
_
Fig. P4.24(a)
Apply nodal analysis:
@ υn :
@ υ1 :
υp = υn = 5 V.
υn − υ1 υn − υo
+
= 0,
6 kΩ
6 kΩ
υ1 − 4 υ1 − υo υ1 − υn
+
+
= 0.
2 kΩ
4 kΩ
6 kΩ
Simplify:
1
10
(υ1 + υo ) =
,
6k
6 kΩ
1
1
1
17
1
υ1 −
υo =
+ +
,
2k 4k 6k
4k
6000
" 10 #
" 1
1 #" #
υ1
6k
6k
6k
=
,
17
1
11
− 4k υo
6k
12k
" # " 32 #
υ1
7
=
.
38
υo
7
υo = 5.429 V.
c
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National Technology and Science Press
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