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Chi squared test In an examination, this is likely to be presented to you in one of three different ways: 1. Results of an investigation that have to be worked through using the formula and a table set out for completion. 2. Judging the significance of results given the figure for 2. 3. Selecting the chi squared test as the appropriate way to assess results from an investigation. Here is an example to show how the chi squared test is used. Pure bred tomato plants with cut leaves and purple stems were crossed with pure bred plants with potato leaves and green stems. All the F1 generation had cut leaves and purple stems. These F1 plants were testcrossed against tomato plants showing the recessive phenotype – potato leaves and green stems. The F2 offspring showed the following numbers of plants in each of four phenotypes purple, cut 70 purple, potato green, cut 91 86 green, potato 77 The ratio of phenotypes expected in the testcross offspring of a dihybrid cross such as this is 1:1:1:1. Use the chi squared test (2), and the test of probabilities shown in the table, to find out if these results are significantly different from the expected results. 2 = E E categories sum of…. observed value E = expected value O E O-E (O-E)2 (O-E)2 / E purple cut purple potato green cut green potato 2 = totals degrees of Distribution of 2 1 freedom 1 2 3 4 0.10 2.71 4.61 6.25 7.78 0.05 3.84 5.99 7.82 9.49 probability, p 0.02 5.41 7.82 9.84 11.67 0.01 6.64 9.21 11.35 13.28 0.001 10.83 13.82 16.27 18.47 What is the probability for the value of 2 that you have calculated? (Hint: better to give the range of probabilities for 2) State what conclusions can be drawn from the probability. That was a typical question. It would be good to be given the null hypothesis in these questions. But the null hypothesis can be derived from the information given. What is the null hypothesis for this investigation involving inheritance in tomatoes? What is the underlying reason for this expectation? Here is a more detailed table of probabilities that you can use while revising the chi squared test. distribution of 2 degrees of freedom increasing values of p decreasing values of p probability, p 1 2 3 4 0.99 0.90 0.00016 0.016 0.02 0.10 0.12 0.58 0.30 1.06 p > 0.90 result is ‘dodgy’ = too good! 0.50 0.46 1.39 2.37 3.36 0.10 2.71 4.61 6.25 7.78 p > 0.05 result is not significantly different from expected outcome 0.05 3.84 5.99 7.82 9.49 0.02 5.41 7.82 9.84 11.67 p < 0.05 result is significantly different from expected outcome 0.01 6.64 9.21 11.35 13.28 p < 0.01 highly significant 0.001 10.83 13.82 16.27 18.47 p < 0.001 very highly significant Ruling lines at p = 0.05 helps to find out if the 2 value is significant or not. 2 Some results have been analysed using the chi squared test. What can be concluded from the results? 1. The F1 generation of tomato plants described earlier were interbred. The total number of plants in each class was as follows: purple, cut 972 purple, potato 325 green, cut 334 green, potato 93 2 = 2.39 what are the degrees of freedom? tick the appropriate box 1 2 3 4 where does the 2 value fit in the range of probabilities? tick the appropriate box p > 0.90 p < 0.90, but > 0.50 p < 0.50, but > 0.10 p < 0.10, but > 0.05 p < 0.05, but > 0.01 p < 0.01, but > 0.001 p < 0.001 What can you conclude from the result? Tick and/or complete the appropriate box. either The results are significant at the …………….. level The null hypothesis can be rejected or The results are not significant The null hypothesis can be accepted 2. A choice chamber was divided into two compartments – light and dark. 50 woodlice were put into the choice chamber and left for 15 minutes. After 15 minutes the number in each compartment were counted. There were 34 in the dark side and 16 in the light side. If the woodlice showed no preference for light or dark, there should be equal numbers in each compartment. The 2 value for these results is 6.48 what are the degrees of freedom? Tick the appropriate box 1 2 3 4 where does the 2 value fit in the range of probabilities? tick the appropriate box 3 p > 0.90 p < 0.90, but > 0.50 p < 0.50, but > 0.10 p < 0.10, but > 0.05 p < 0.05, but > 0.01 p < 0.01, but > 0.001 p < 0.001 What can you conclude from the result? Tick and/or complete the appropriate box. either The results are significant at the …………….. level The null hypothesis can be rejected or The results are not significant The null hypothesis can be accepted 3. A student crossed some vestigial winged fruit flies with some wild type (long winged) fruit flies. All the F1 fruit flies were long winged. The results of the F2 generation were as follows: long winged vestigial winged 65 21 2 = 0.015504 what are the degrees of freedom? tick the appropriate box 1 2 3 4 where does the 2 value fit in the range of probabilities? tick the appropriate box p > 0.90 p < 0.90, but > 0.50 p < 0.50, but > 0.10 p < 0.10, but > 0.05 p < 0.05, but > 0.01 p < 0.01, but > 0.001 p < 0.001 4 What can you conclude from the result? Tick and/or complete the appropriate box. either The results are significant at the …………….. level The null hypothesis can be rejected or The results are not significant The null hypothesis can be accepted 5 Reinforcement 1 The results of certain types of experiments can be analysed with the 2 test – what do these experiments have in common? 2 What type of data can be analysed using the 2 test? 3 Given the formula: 2 = E E what are the row and column headings in the table for calculating 2? 4 How do you calculate degrees of freedom? 5 What does the 2 value mean? 6 What is the importance of the 5% level (or 0.05)? 7 What does p stand for? 8 What do you conclude if the value for p is greater than (>) 0.05 (5%)? 9 What do you conclude if the value of p is less than (<) 0.05 (5%)? 10 What do you conclude if the value of p is greater than (>) 0.9 (90%)? 6