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Chapter 2 Introduction to Quantum Mechanics W.K. Chen Electrophysics, NCTU 1 Outline Principles of quantum mechanics Schrodinger’s wave equation Application of Schrodinger’s wave equation Extensions of the wave theory to atoms W.K. Chen Electrophysics, NCTU 2 2.1.1 Energy quanta Photoelectric effect Classical physics: if the intensity of monochromatic light is large enough, the work function of the material will be overcome and an electron will be emitted from the surface, independent of the incident frequency. W.K. Chen Electrophysics, NCTU 3 Experimental results: The lowest frequency of incident light is vo., below which no photoelectric effect is produced At a constant incident intensity, the maximum kinetic energy of the photoelectron varies linearly with frequency for v>vo. If the incident intensity varies at a constant frequency, the rate of photoemission changes, but the maximum kinetic energy remains the same maximum kinetic energy the maximum kinetic energy that can be obtained for the emitted photoelectrons W.K. Chen Electrophysics, NCTU 4 Energy quanta: In 1900, Planck postulated that thermal radiation emitted from a heated surface is in a form of discrete packets of energy called quanta E = hv h=6.625x10-34 J.s Einstein’s interpretation for photoelectric effect: In 1905, Einstein suggested the energy in a light wave is also contained in discrete packets or bundles. The particle-like packet of energy is called photon, whose energy is given by E=hv The minimum energy required to remove an electron is called the work function of the material and any excess photon energy goes into kinetic energy of the photoelectron Tmax = 1 mυ 2 = hv − hvo 2 work function = hvo W.K. Chen Electrophysics, NCTU 5 Example 2.1 photon energy Photon energy of x-ray with a wavelength of λ=0.708x10-8cm (6.625 ×10 −34 )(3 ×1010 ) = 2.81×10 −15 J E = hv = h = −8 0.708 ×10 λ 2.81×10 −15 4 = = 1 . 75 × 10 eV 1.6 ×10 −19 c W.K. Chen Electrophysics, NCTU 6 2.1.2 Wave-particle duality The light waves in the photoelectric effect behave as if they are particle In 1924, de Brogle postulated the existence of matter wave. Since wave exhibit particle-like behavior, then particle should be expected to show particle-like properties. Energy E = hv = hω c wavelength λ = v 1 ∂2 ∂2 wave equation 2 Ψ ( x, t ) = 2 2 Ψ ( x, t ) ∂x c ∂t 1 mυ 2 2 r r momentum p = mυ Energy E = p2 E − p relation E = 2m d 2x Force F = ma = m 2 dt W.K. Chen 7 Electrophysics, NCTU Wave-particle duality principle particle: momentum ⇒ wavelength wave: wavelength ⇒ momentum the momentum of photon p = the wavelength of particle λ = λ= p= W.K. Chen h λ h λ h p = hk (h = h 2π , k= ) λ 2π (de Broglie wavelength) h p = hk Electrophysics, NCTU 8 Davisson-Germer experiment (1927) The wave nature of particles (electrons) can be tested by the existence of interference pattern produced by electron beam diffracted from a grating Nickel crystal (grating) Diffraction pattern 2d sin θ = mλ W.K. Chen Electrophysics, NCTU 9 Electromagnetic frequency spectrum W.K. Chen Electrophysics, NCTU 10 Example 2.2 de Broglie wavelength An electron travel at a velocity of 107 cm/sec the momentum of electron p = mυ = (9.11×10 −31 )(105 ) = 9.11×10 −26 h 6.625 ×10 −34 = 7.27 ×10 −9 m the de Broglie wavelength λ = = − 26 p 9.11×10 o = 72.7 A Typical de Broglie wavelength of electron≈ 100 Å W.K. Chen 11 Electrophysics, NCTU 2.1.3 Uncertainty Principle (1927) Uncertainty principle (Heisenberg) It is impossible to simultaneously describe the absolute accuracy position and momentum of a particle It is impossible to simultaneously describe the absolute accuracy energy of particle and the instant time the particle has this ΔpΔx ≥ h ΔEΔt ≥ h h= h = 1.054 ×10 −34 J ⋅ s 2π exp(kx) exp(ωt ) The Uncertainty principle is only significant for subatomic particles W.K. Chen Electrophysics, NCTU 12 2.2 Schodinger’s wave equation Wave equation (Traveling wave) r ∂2 r 1 ∂2E E= 2 υ ∂t2 ∂x 2 r ∂2 r 1 ∂2H H= 2 υ ∂t2 ∂x 2 υ= Wave function 1 με Sinusiodal form : r r r r r E (r , t ) = Eo cos(k ⋅ r m ω t + φ ) Exponential form ⇔ sin/cos form r r r r 1 j ( kr⋅rr mωt ) − j ( kr⋅rr mωt ) Eo sin( k ⋅ r m ωt ) = Eo [e −e ] 2j rr rr r r r r 1 Eo cos(k ⋅ r m ωt ) = Eo [e j ( k ⋅r mωt ) + e − j ( k ⋅r mωt ) ] 2 Exponential form : r r r − j ( kr⋅rr mωt +φ ) E (r , t ) = Eo ⋅ e W.K. Chen 13 Electrophysics, NCTU 2.2 Schodinger’s wave equation Schrodinger in 1926 provided a formulation called wave mechanics, which incorporated The principle of quanta (Planck) Wave-particle duality (de Broglie) Based on the wave-particle duality principle, we will describe the motion of electrons in a crystal by wave Classical physics p2 + V ( x) = E 2m Wave mechanics p → − jh ∂ ∂x E → jh Schodinger wave equation − h ∂ Ψ ( x, t ) ∂Ψ ( x, t ) ⋅ + V ( x ) Ψ ( x , t ) = j h 2m ∂x 2 ∂t 2 W.K. Chen 2 Electrophysics, NCTU ∂ ∂t Ψ ( x, t ) : wave function V ( x) : potential function m : mass of the particle 14 Assume the position and time parameters in wave function is separable Ψ ( x, t ) = ψ ( x)φ (t ) − h2 ∂ 2ψ ( x) ∂φ (t ) V ( x ) ψ ( x ) φ ( t ) j ψ ( x ) ⋅ φ (t ) + = h 2m ∂x 2 ∂t devide by ψ ( x)φ (t ) − h 2 1 ∂ 2ψ ( x) 1 ∂φ (t ) + V ( x ) = jh ⋅ 2 φ (t ) ∂t 2m ψ ( x) ∂x The left side of equation is a function of position x only and the right side is a function of time t only, which implies each side of this equation must be equal to a same constant. − h 2 1 ∂ 2ψ ( x) 1 ∂φ (t ) ⋅ + V ( x ) = jh = η (constant ) 2 2m ψ ( x) ∂x φ (t ) ∂t W.K. Chen Electrophysics, NCTU 15 Physical meaning of η jh 1 ∂φ (t ) = η (constant ) φ (t ) ∂t ⇒ φ (t ) = e − j (η / h )t = e − jω t ⇒ η h The position-independent wave function is always in a form of exponential term e -jωt =ω Q E = hω ⇒ η = E The separation constant is the total energy E of the particle Wave eq can be written as Ψ ( x, t ) = ψ ( x)φ (t ) = ψ ( x)e − jω t ⇒ Time-independent Schrodinger wave equation W.K. Chen − h 2 1 ∂ 2ψ ( x) ⋅ + V ( x) = η = E 2m ψ ( x) ∂x 2 Electrophysics, NCTU 16 Time-independent Schrodinger wave equation − h 2 1 ∂ 2ψ ( x) ⋅ + V ( x) = E 2m ψ ( x) ∂x 2 − h 2 ∂ 2ψ ( x) + (V ( x) − E )ψ ( x) = 0 ⋅ 2m ∂x 2 Time-independent Schrodinger’s wave equation ∂ 2ψ ( x) + k 2ψ ( x) = 0 2 ∂x k= 2m[ E − V ( x)] >0 h2 if E > V ( x) ⇒ ψ ( x) = A exp(± jkx) γ= 2m[V ( x) − E ] >0 h2 if E < V ( x) ⇒ ψ ( x) = A exp(±γx) W.K. Chen 17 Electrophysics, NCTU 2.2.2 Physical meaning of the wave equation 2 Max Born postulated in 1926 that the wave function Ψ ( x, t ) dx is the probability of finding the particle between x and x+dx at a given 2 Ψ ( x , t ) = Ψ ( x, t ) ⋅ Ψ * ( x , t ) = ψ ( x)e − j ( E / h )t ⋅ψ * ( x)e + j ( E / h )t = ψ ( x) ⋅ψ * ( x) 2 probability Ψ ( x, t ) = ψ ( x) ⋅ψ * ( x) The probability density function is independent of time In classical mechanics, the position of a particle can be determined precisely In quantum mechanics, the position of a particle is found in term of a probability W.K. Chen Electrophysics, NCTU 18 2.2.3 Boundary condition for wave function The probability of finding the particle over the entire space must be equal to 1 ∫ +∞ −∞ +∞ Ψ ( x, t ) dx = ∫ ψ ( x) ⋅ψ * ( x)dx = 1 2 −∞ ψ(x) must be finite, single-valued and continuous ∂ ψ(x) /∂ x must be finite, single-valued and continuous If the probability were to become infinite at some point in space, then the probability of finding the particle at the position would be certain, that violate the uncertainty principle The second derivative must finite which implies that the first derivative must be continuous The first derivative is related to the particle momentum, which must be finite and single-valued The finite first derivative implies that the function itself must be continuous W.K. Chen Electrophysics, NCTU 19 2.3 Applications of Schrodinger’s wave equation Electron in free space Electron in infinite potential well Step potential function Potential barrier W.K. Chen Electrophysics, NCTU 20 2.3.1 Electron in free space Electron in free space means no force acting on the electron ⇒ V(x) is constant We must have E>V(x) to assure the motion of electron − h 2 ∂ 2ψ ( x) ⋅ + (V ( x) − E )ψ ( x) = 0 2m ∂x 2 Time-independent Schrodinger’s wave equation For simplicity, let V(x)=0 ∂ 2ψ ( x) 2mE + 2 ψ ( x) = 0 (free space) ∂x 2 h k= 2mE h2 ψ ( x) = A exp(+ jkx) + B exp(− jkx) W.K. Chen 21 Electrophysics, NCTU Qφ (t ) = e − jωt ⇒ Ψ ( x, t ) = ψ ( x) ⋅ φ (t ) = A exp[ j (kx − ωt ] + B exp[− j (kx + ωt )] Right-going wave Left-going wave Next time, when we see the time-independent wave function, we can know its traveling direction immediately ψ ( x) = A exp( jkx) + B exp(− jkx) k= 2mE h2 Compared to a particle traveling function in classical mechanics Ψ ( x, t ) = A exp[ j (kx − ωt ) + B exp[− j (kx + ωt )] Where W.K. Chen k= 2π λ ⇒λ = Electrophysics, NCTU h 2mE 22 Remember the postulate of de Broglie’s wave-particle principle λ= h p We also have p = 2mE p2 ⇒E= 2m Which implies the consistency of wave-particle principle and wave mechanics in free space ( wave mechanics is based on energy quanta and wave-particle duaility W.K. Chen Electrophysics, NCTU 23 2.3.2 Infinite potential well (bound particle) V ( x) = ∞ for x ≤ 0, x ≥ a Region I & III (V(x)=∞) ⇒ decaying wave For V(x)=∞ (>>E), the wave function in region I & III must be zero − h ∂ ψ ( x) ⋅ + (V ( x) − E )ψ ( x) = 0 ∂x 2 2m 2 2 E>V(x): traveling wave V(x)>E: decaying wave W.K. Chen Region II (V(x)=0) ⇒ traveling wave ∂ 2ψ ( x) 2mE + 2 ψ ( x) = 0 h ∂x 2 Electrophysics, NCTU 24 The solution is the same what we have learned in “Fundamental Physics” ψ ( x) = A1 cos Kx + A2 sin Kx K= 2mE h2 Boundary conditions: ψ(x) must continuous ( at boundaries) ψ ( x = 0 + ) = ψ ( x = 0 − ) = 0 = A1 cos( Ka ) ⇒ A1 = 0 ψ ( x = a − ) = ψ ( x = a + ) = 0 = A2 sin( Ka ) ⇒ sin( Ka ) = 0 ( or A2 = 0) ⇒ K= nπ a W.K. Chen Electrophysics, NCTU 25 Boundary conditions: Total probability is one ∫ a 0 ( A2 sin Kx) 2 dx = 1 ∫ sin ∫ a 0 2 ( Kx)dx = x sin 2 Kx − 2 4K 0 a ⎛ x sin 2 Kx ⎞ ( A2 sin Kx) dx = 1 =A ⎜ − ⎟ 4K ⎠ 0 ⎝2 ⇒ A2 = 2 2 a ⇒ ψ ( x) = W.K. Chen 2 2 2 ⎛ nπ ⎞ ⋅ sin ⎜ x⎟ a ⎝ a ⎠ where n = 1,2,3L Electrophysics, NCTU 26 Quantization of energy levels: QK = discrete wavevector K= nπ a 2mE h2 discrete energy h 2 n 2π 2 E = En = 2ma 2 (infinite well) En ∝ n 2 Quantization of particle energy in infinite well Since the constant K must have discrete values. This results mean the energy of particle in finite well only have particular discrete values, contrary to results from classical physics, which would allow the particle to have continuous energy levels. W.K. Chen Electrophysics, NCTU 27 Example 2.3 infinite potential well Infinite potential well with width of 5Å n 2 (1.054 × 10 −34 ) 2 π 2 h 2 n 2π 2 E = En = = n 2 (2.41×10 −19 )J = 2 −34 −10 2 2ma 2(9.11×10 )(5 ×10 ) n 2 (2.41×10 −19 ) = n 2 (1.51) eV = −19 1.6 ×10 E1 = 1.51 eV E2 = 6.04 eV = 4 E1 E3 = 13.59 eV = 9 E1 For Infinite potential well, En ∝ n 2 W.K. Chen Electrophysics, NCTU 28 2.3.3 The step potential function Time-independent Schrodinger’s wave equation ∂ 2ψ ( x) 2m( E − V ( x)) + ψ ( x) = 0 h2 ∂x 2 (ii) E>Vo (i) E<Vo Vo Vo Incident wave: traveling wave Reflective wave: traveling wave Transmitted wave: decaying wave W.K. Chen Incident wave: traveling wave Reflective wave: traveling wave Transmitted wave: traveling wave 29 Electrophysics, NCTU Case: E<Vo Time-independent Schrodinger’s wave equation E ∂ 2ψ ( x) 2m( E − V ( x)) + ψ ( x) = 0 h2 ∂x 2 Region I (V(x)=0, E>V) ⇒ traveling wave ∂ 2ψ 1 ( x) 2mE + 2 ψ 1 ( x) = 0 ∂x 2 h ψ 1 ( x) = A1e jk x + B1e − jk x ( x ≤ 0) (eq(1)) 1 W.K. Chen 1 Electrophysics, NCTU k1 = 2mE h2 30 Region II (E<Vo) ⇒ decaying wave ∂ 2ψ 2 ( x) 2m(Vo − E ) + ψ 2 ( x) = 0 h2 ∂x 2 ψ 2 ( x) = A2 e −γ x + B2 e +γ 2 2x γ2 = ( x ≥ 0) eq(2) ⎧ jk1 x − jk1 x ( x ≤ 0) L eq(1) ⎪ψ 1 ( x) = A1e + B1e ⎪ ⎨ ⎪ψ ( x) = A e −γ 2 x + B e +γ 2 x ( x ≥ 0) L eq(2) 2 2 ⎪⎩ 2 2m(Vo − E ) >0 h2 k1 = 2mE >0 h2 γ2 = 2m(Vo − E ) >0 h2 4 unknowns (A1, B1, A2 and B2) ⇒ 3 B.C. (boundary conditions) W.K. Chen 31 Electrophysics, NCTU ⎧⎪ψ 1 ( x) = A1e jk1x + B1e − jk1x ( x ≤ 0) L eq(1) ⎨ ⎪⎩ψ 2 ( x) = A2 e −γ 2 x + B2 e +γ 2 x ( x ≥ 0) L eq(2) B.C.1: ψ2(x) must remain finite ⇒ B2=0 ψ 2 ( x) = A2e −γ 2x B.C.2: ψ (x) must be continuous at x=0 ψ 1 (0 − ) = ψ 2 (0 + ) ⎧ jK1 x − jK1 x ( x ≤ 0) ⎪ψ 1 ( x) = A1e + B1e ⎨ ⎪ψ ( x) = A e −γ 2 x ( x ≥ 0) 2 ⎩ 2 ⇒ A1 + B1 = A2 eq(i ) B.C.3: first derivative dψ (x)/dx must be continuous at x=0 ∂ψ 1 ∂x W.K. Chen = 0− ∂ψ 2 ∂x 0+ jk1 A1 − jk1 B1 = −γ 2 A2 Electrophysics, NCTU eq(ii ) 32 Using eq(i) and (ii), we obtain − (γ 22 + 2 jk1γ 2 − k12 ) A1 B1 = (γ 22 + k12 ) A2 = 2k1 (k1 − jγ 2 ) A1 (γ 22 + k12 ) Wave functions for step potential barrier ⎧ − jK1 x jK1 x ( x ≤ 0) ⎪ψ 1 ( x) = A1e + B1e ⎨ ⎪ψ ( x) = A e −γ 2 x ( x ≥ 0) 2 ⎩ 2 (i) E<Vo Vo Incident wave: traveling wave Reflective wave: traveling wave Transmitted wave: decaying wave W.K. Chen 33 Electrophysics, NCTU Reflectivity at interface of step barrier The reflective probability density function (i.e., intensity) Vo (γ 22 − k12 + 2 jk1γ 2 )(γ 22 − k12 − 2 jk1γ 2 ) B1 ⋅ B = A1 A1* 2 2 2 (γ 2 + k1 ) * 1 Reflective coefficient R, defined as the ratio of reflected flux to the incident flux R= υr I r υi I i Flux = n ⋅υ υr B1 B1* ⇒R= ⋅ υi A1 A1* Q p = mυ = hk W.K. Chen Electrophysics, NCTU 34 υi = h k1 = υ r m B1 B1* (γ 22 − k12 ) 2 + 4k12γ 22 ⇒R= = = 1.0 A1 A1* (γ 22 + k12 ) 2 The results of R=1 implies that all of the particles incident on the potential barrier for E<Eo are eventually reflected, entirely consistent with classical physics Because A2 is not zero, the particle being found in barrier is not equal to zero, which is called quantum mechanical penetration. The quantum mechanical penetration is classically not allowed, which is the difference between classical and quantum mechanics W.K. Chen 35 Electrophysics, NCTU Example 2.4 penetration depth ψ 2 ( x) = A2 e −γ 2x γ2 = 2m(Vo − E ) >0 h2 Vo The penetration depth is defined as γ2d=1 h2 d= = 2m(Vo − E ) γ2 1 1.054 ×10 −34 h2 = = = 11.6 ×10 −10 m 2 m ( 2 Eo − E ) 2(9.11×10 −31 )(4.56 ×10 −31 ) o d = 11.6 A The penetration depth is typically much less than the de Broglie wavelength of electron in free space ( 73 Å). W.K. Chen Electrophysics, NCTU 36 2.3.4 The potential barrier ⎧0 for x < 0 & x > a V ( x) = ⎨ ⎩Vo for 0 ≤ x ≤ a E < Vo ⎧ψ 1 ( x) = A1e jk1x + B1e − jk1x ( x ≤ 0) L eq(1) ⎪ −γ x +γ x ⎨ψ 2 ( x) = A2 e 2 + B2 e 2 ( x ≥ 0) L eq(2) ⎪ jk1 x − jk1 x ( x ≥ a) L eq(3) ⎩ψ 3 ( x) = A3e + B3e k1 = 2mE h2 W.K. Chen γ2 = 2m(Vo − E ) h2 37 Electrophysics, NCTU If the barrier width a is thinner than the penetration depth, electron can tunnel through the barrier and appear in region III The transmission coefficient (defined as the ratio of the transmitted flux in region III to the incident flux in region I) Region I υt A3 A3* A3 A3* ⇒T = ⋅ = υi A1 A1* A1 A1* ⇒ T ≈ 16( Region II Region III (Q υt = υi ) E E ) ⋅ (1 − ) exp(−2γ 2 a) υo υo for E << Vo a<d Tunneling: There is a finite probability that a particle impinging a potential barrier will penetrate the barrier and appear in region III W.K. Chen Electrophysics, NCTU 38 Example 2.5 Tunneling probability o Vo = 20 eV, E = 2 eV, width a = 3 A E << Vo ⇒ T ≈ 16( E ) ⋅ (1 − E ) exp(−2γ a) 2 υo υo for E << Vo 2m(Vo − E ) 2(9.11×10 −31 )(20 − 2)(1.6 ×10 −19 ) 10 −1 2 . 17 × 10 m = γ2 = = h2 (1.054 ×10 −34 ) 2 ⇒ T ≈ 16( 2 2 ) ⋅ (1 − ) exp[−2(2.17 ×1010 )(3 ×10 −10 )] = 3.17 ×10 −6 20 20 The tunneling probability may appear to be a small value, but the value is not zero W.K. Chen 39 Electrophysics, NCTU 2.4 Extensions of the wave theory to atoms − e2 V (r ) = 4πε o r ∇ 2ψ (r , θ , φ ) + + 2mo ( E − V ( x))ψ (r , θ , φ ) = 0 h2 Time-independent Schrodinger’s wave equation In spherical coordinate, Schrodinger’s wave equation is 2mo 1 ∂ 2 ∂ψ 1 ∂ 2ψ 1 ∂ ∂ψ ⋅ ( r ) + ⋅ + ⋅ (sin θ ) + ( E − V (r ))ψ = 0 r 2 ∂r ∂r r 2 sin 2 θ ∂φ 2 r 2 sin 2 θ ∂θ ∂θ h2 Assume separation-of-variables is valid ψ (r ,θ , φ ) = R(r ) ⋅ Θ(θ ) ⋅ Φ(φ ) W.K. Chen Electrophysics, NCTU 40 2m sin 2 θ ∂ 2 ∂R 1 ∂ 2 Φ sin θ ∂ ∂Θ ⋅ (r )+ ⋅ 2 + ⋅ (sin θ ) + r 2 sin 2 θ 2 o ( E − V ) = 0 R ∂r ∂r Φ ∂φ Θ ∂θ ∂θ h The second term is a function of φ only, independent of r and θ, it must be constants 1 ∂ 2Φ ⋅ 2 = −m 2 Φ ∂φ z Spherical coordinate The solution Φ = e jmφ θ m = 0,±1,±2,±3L r + W.K. Chen M M x y φ 41 Electrophysics, NCTU Sets of quantum numbers R(r ) ⇒ n = 1,2,3L Θ(θ ) ⇒ l = n − 1, n − 2, n − 3, LL,0 Φ (φ ) ⇒ m = ±l , ± (l − 1),LL,0 + En ∝ 1 n2 The electron energy for one-electron atom is − mo e 4 En = (4πε o ) 2 2h 2 n 2 n: principle quantum number The negative energy indicates the electron is bound to nucleus The energy of bound electron is quantized The quantized energy is again a result of the particle being bound in a finite region of space W.K. Chen Electrophysics, NCTU 42 Infinite potential well One-electron atom + h 2 n 2π 2 E = En = 2ma 2 − mo e 4 En = (4πε o ) 2 2h 2 n 2 En ∝ n 2 En ∝ W.K. Chen Electrophysics, NCTU 1 n2 43 Wave function for one-electron atom ψnlm: notation of wave function for one-electron atom ψ 100 1 ⎛1⎞ = ⋅⎜ ⎟ π ⎜⎝ ao ⎟⎠ 3/ 2 e − r / ao The wave function of lowest energy state is spherical symmetric o 4πε o h 2 ao = = 0 . 529 A mo e 2 The radial probability density function for one-electron atom in the (a) lowest energy state and (b) next-higher energy state W.K. Chen Electrophysics, NCTU 44 Lowest energy states The wave function of lowest energy state is spherically symmetric The most probable distance from the nucleus is at r=ao, which is the same as Bohr theory We may now begin to conceive the concept of an electron cloud, or energy shell, surrounding the nucleus rather than a discrete particle around nucleus Next higher energy states The radial probability density function for the next higher wave function ( n=2, l=0)is also spherically symmetric Two energy shells are existed for the next higher energy states The second shell is the most probable energy state for the next higher energy states, but there is still a small probability that the electron will exist at the small radius W.K. Chen 45 Electrophysics, NCTU n = 1,2,3L l = n − 1, n − 2, n − 3, LL,0 m = ±l , ± (l − 1),LL,0 W.K. Chen Electrophysics, NCTU 46