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Example 1.4 Consider an infinitely long cylinder with charge density ρ, dielectric constant ε 0 and radius r0 . What is the electric field in and around the cylinder? L r0 ρ r ε0 Solution Because of the cylinder symmetry one expects the electric field to be only dependent on the radius, r. Applying Gauss's law one finds: E ⋅ A = E 2π rL = Q ρπ r 2 L = for r < r0 ε0 ε0 and E ⋅ A = E 2π rL = Q ρπ r02 L = for r > r0 ε0 ε0 where a cylinder with length L was chosen to define the surface A, and edge effects were ignored. The electric field then equals: E (r) = ρr ρ r02 for r < r0 and E ( r ) = for r > r0 2ε 0 2ε 0 r The electric field therefore increases within the cylinder with increasing radius as shown in the figure below. The electric field decreases outside the cylinder with increasing radius. 09/ 04/ 02 © B. Van Zeghbroeck, 1998 E ρ r0 2ε 0 r 0 0 r0