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2.4 Objective: The student will be able to: recognize and use algebraic properties Addition and Subtraction Properties 1) Addition Property For all numbers a, b and c if a = b, then: a+c=b+c 2) Subtraction Property For all numbers a, b and c if a = b, then: a - c= b - c Algebraic Properties 1)Reflexive Property: For every number a, a = a, 2) Symmetric Property: For all numbers a and b, if a = b, then a = b and b = a If 4 = 2 + 2 then 2 + 2 = 4. Multiplication Property: For all numbers a, b and c if a = b, then: a • c= b • c Division Property: For all numbers a, b and c if a = b and if c ≠ 0, then: More Properties 3) Transitive: If a = b and b = c, then a = c. If 4 = 2 + 2 and 2 + 2 = 3 + 1 then 4 = 3 + 1. 4) Substitution: If a = b, then a can be replaced by b. (5 + 2)x = 7x The Distributive Property The process of distributing the number on the outside of the parentheses to each term on the inside. a(b + c) = ab + ac and (b + c) a = ba + ca a(b - c) = ab - ac and (b - c) a = ba - ca Example #1 5(x + 7) 5•x+5•7 5x + 35 Name the Property 1. If 2x+1= 4, then 2x = 3 Substraction 2. (10 + 2) 3 = 12 3 Substitution 3. 2 + 3 = 5 then 5 = 2 + 3 Symmetric 4. If 5 2 = 10 & 10 = 5 + 5 then 52=5+5 Transitive 5. If 7x = 21, then x = 3 Division Property 6. 2( 5+x) = 2• 5 +2 • x Distributive 7. k + 7 = k + 7 Reflexive 8. 2+k = k+ 2 Symmetric Example 1: Writing Reasons Solve 5x – 18 = 3x +2 1. 5x – 18 = 3x + 2 1. Given 2. Subtraction property 2. 2x – 18 = 2 3. Addition property 3. 2x = 20 4. Division property 4. x = 10 Example 2: Writing Reasons Solve 55z – 3(9z + 12)= -64 1. 55z – 3(9z + 12)= -64 2. 55z – 27z – 36 = -64 3. 28z – 36 = -64 4. 28z = -28 5. z = -1 1. 2. 3. 4. 5. Given Distributive property Simplify Addition property Division property Example 4: Using properties of length 1. AB = CD 1. Given 2. 3. 4. 5. 2. 3. AB + BC = BC + CD AC = AB + BC BD = BC + CD AC = BD 4. 5. Addition property Segment addition postulate Segment addition postulate Substitution property