Download Name: Date: Geometry 1. Fill in the chart with the words below. Each

Name:
Date:
Geometry
1. Fill in the chart with the words below.
Each shape has all the qualities of those
above it (general at top, specific at
bottom).
•
•
•
•
•
•
•
•
Isosceles Trapezoid
Kite
Parallelogram
Quadrilaterals
Rectangle
Rhombus
Square
Trapezoid
Quadrilaterals
Parallelograms
Kites
Rhombuses
2. Fill in the chart below with the
properties about each type of
quadrilateral.
Parallelogram
Angles
Sum to 360º
Consecutive angles
supplementary;
both pairs opposite
angles congruent
Trapezoids
Rectangles
Squares
Rhombus
Both pairs opposite
angles bisected by
diagonals
Rectangle
Square
All four right angles
(therefore congruent)
Regular
Sides
Diagonals
Isosceles
Trapezoids
Both pairs opposite
sides parallel;
both pairs opposite
sides congruent
All four sides
congruent
Diagonals bisect each
other.
Diagonals are
perpendicular
Diagonals are
congruent.
Diagonals are
congruent and
perpendicular.
Trapezoid (include
Isosceles)
Kite
If isosceles, both pairs
base angles congruent
Exactly one pair
opposite angles
congruent
Exactly one pair (bases)
parallel
If isosceles, legs
congruent
Midsegment is parallel
to bases and length is
average of bases’
lengths.
Two pairs consecutive
sides congruent;
opposite sides NOT
congruent
If isosceles trapezoid,
diagonals are congruent.
Diagonals are
perpendicular.
Name:
Date:
Geometry
Properties of Quadrilaterals
Ex. 1: ABCD has (at least) two congruent consecutive sides. What quadrilateral(s) could meet this
condition?
Kite; rhombus; rectangle; square
Ex. 2: In quadrilateral RSTV, m∠R = 88º, m∠S = 113º, and m∠V = 113º. What kind of quadrilateral
could RSTV be? Must it be this type? Explain.
m∠T must be 46º because the sum of all four angles must be 360º. So it must be a kite because there is
only one pair of opposite sides congruent.
Ex. 3: When you join the midpoints of an isosceles trapezoid in order, what special quadrilateral is
formed? Why?
A rhombus; drawing in diagonals makes two triangles, and by the midsegment theorem, we see that
opposite sides of the new quadrilateral are parallel. Also, because it’s an isosceles trapezoid, there are
two pairs of congruent triangles by SAS. Then by CPCTC, there end up being two pairs of consecutive
congruent sides. So since both pairs of opposite sides are parallel and consecutive sides congruent, it
must be a rhombus.