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ST 370 Probability and Statistics for Engineers Discrete Random Variables A random variable is a numerical value associated with the outcome of an experiment. Discrete random variable When we can enumerate the possible values of the variable (such as 0, 1, 2, . . . ), the random variable is discrete. Example: acceptance sampling Suppose that a sample of size 10 is drawn from a shipment of 200 items, of which some number are non-compliant; X is the number of non-compliant items in the sample. The possible values of X are 0, 1, 2, . . . , 10, so X is a discrete random variable. 1 / 15 Discrete Random Variables ST 370 Probability and Statistics for Engineers Continuous random variable When the variable takes values in an entire interval, the random variable is continuous. Example: flash unit recharge time Suppose that a cell phone camera flash is chosen randomly from a production line; the time X that it takes to recharge is a positive real number; X is a continuous random variable. Presumably, there is some lower bound a > 0 that is the shortest possible recharge time, and similarly some upper bound b < ∞ that is the longest possible recharge time; however, we usually do not know these values, and we would just say that the possible values of X are {x : 0 < x < ∞}. 2 / 15 Discrete Random Variables ST 370 Probability and Statistics for Engineers Probability distribution The probability distribution of a random variable X is a description of the probabilities associated with the possible values of X . The representation of a probability distribution is different for discrete and continuous random variables. Probability mass function For a discrete random variable, the simplest representation is the probability mass function (pmf) fX (x) = P(X = x) where x is any possible value of X . 3 / 15 Discrete Random Variables Probability distribution ST 370 Probability and Statistics for Engineers Example: acceptance sampling Suppose one item is chosen at random from a shipment of 200 items, of which 5 are non-compliant. Let ( 1 if the item is non-compliant, X = 0 if the item is compliant. We could say that X is the number of non-compliant items seen. The probability mass function of X is ( 0.975 fX (x) = 0.025 x =0 x =1 A random variable like X that takes only the values 0 and 1 is called a Bernoulli random variable. 4 / 15 Discrete Random Variables Probability distribution ST 370 Probability and Statistics for Engineers Example: Dice Suppose you roll a fair die, and the number of spots showing is X . Then X is a discrete random variable with probability mass function 1 fX (x) = , 6 x = 1, 2, 3, 4, 5, 6. Because the probability is the same for all the possible values of X , it is called the discrete uniform distribution. Properties of the probability mass function They are probabilities: fX (x) ≥ 0. P They cover all possibilities: x fX (x) = 1. 5 / 15 Discrete Random Variables Probability distribution ST 370 Probability and Statistics for Engineers Cumulative distribution function As an alternative to the probability mass function, the probability distribution of a random variable X can be defined by its cumulative distribution function (cdf) FX (x) = P(X ≤ x), −∞ < x < ∞. In terms of the probability mass function: X fx (xi ), −∞ < x < ∞. FX (x) = xi ≤x FX (·) has a jump at each possible value xi of X , and the jump equals the corresponding probability fX (xi ), so the probability mass function can be obtained from the cumulative distribution function. 6 / 15 Discrete Random Variables Cumulative distribution function ST 370 Probability and Statistics for Engineers Example: acceptance sampling x <0 0 FX (x) = 0.975 0 ≤ x < 1 1 x ≥1 curve(pbinom(x, 1, .025), from = -1, to = 2) 7 / 15 Discrete Random Variables Cumulative distribution function ST 370 Probability and Statistics for Engineers Example: dice 0 1/6 FX (x) = 2/6 ... 1 x <1 1≤x <2 2≤x <3 x ≥6 curve(pmax(0, pmin(1, floor(x)/6)), from = 0, to = 7) 8 / 15 Discrete Random Variables Cumulative distribution function ST 370 Probability and Statistics for Engineers Mean and Variance Mean value The mean value, or expected value, of a discrete random variable with probability mass function fX (·) is X µX = E (X ) = xfX (x). x E (X ) is a weighted average of the possible values of X , each weighted by the corresponding probability. The expected value E (X ) is a typical value of the random variable X , in the same way that a sample mean x̄ is a typical value of the sample x1 , x2 , . . . , xn . 9 / 15 Discrete Random Variables Mean and Variance ST 370 Probability and Statistics for Engineers Example: acceptance sampling One item is chosen at random from a shipment of 200 items, of which 5 are non-compliant, and X is the number of non-compliant items seen: E (X ) = 0 × fX (0) + 1 × fX (1) = 0.025. For any Bernoulli random variable X , E (X ) = P(X = 1). 10 / 15 Discrete Random Variables Mean and Variance ST 370 Probability and Statistics for Engineers Example: Dice Suppose you roll a fair die, and the number of spots showing is X : E (X ) = 1 × fX (1) + 2 × fX (2) + · · · + 6 × fX (6) = (1 + 2 + 3 + 4 + 5 + 6)/6 = 3.5. Note In these examples and in many others, the “expected” value is not one of the possible values of the random variable; this is not the paradox that it is sometimes made out to be! 11 / 15 Discrete Random Variables Mean and Variance ST 370 Probability and Statistics for Engineers Variance Suppose that X is a random variable with expected value µX . Then Y = (X − µX )2 is another random variable, and its expected value is X E (Y ) = yfY (y ) y X = (x − µX )2 fX (x). x 12 / 15 Discrete Random Variables Mean and Variance ST 370 Probability and Statistics for Engineers The variance of X is E (Y ) = E [(X − µX )2 ]: σX2 = V (X ) = E (X − µX )2 . The standard deviation of X is q σX = σX2 . 13 / 15 Discrete Random Variables Mean and Variance ST 370 Probability and Statistics for Engineers Example: acceptance sampling For any Bernoulli random variable X , µX = P(X = 1) = p, say, so σX2 = (0 − p)2 × P(X = 0) + (1 − p)2 × P(X = 1) = p 2 (1 − p) + (1 − p)2 p = p(1 − p) and σX = 14 / 15 p p(1 − p). Discrete Random Variables Mean and Variance ST 370 Probability and Statistics for Engineers Example: Dice x x − 3.5 (x − 3.5)2 fX (x) (x − 3.5)2 fX (x) 1 -2.5 6.25 1.0417 2 -1.5 2.25 3 -0.5 0.25 4 0.5 0.25 5 1.5 2.25 6 2.5 6.25 1 6 1 6 1 6 1 6 1 6 1 6 Total: 2.9168 0.3750 0.0417 0.0417 0.3750 1.0417 So σX2 = 2.917 and σX = 1.708. 15 / 15 Discrete Random Variables Mean and Variance