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International Journal of Mathematical Analysis
Vol. 8, 2014, no. 36, 1757 - 1766
HIKARI Ltd, www.m-hikari.com
http://dx.doi.org/10.12988/ijma.2014.47203
s-Generalized Fibonacci Numbers: Some Identities,
a Generating Function and Pythagorean Triples
A. P. Aires1 , P. Catarino2 , H. Campos2 , A. Borges3 and P. Vasco3
Departamento de Matemática, Escola de Ciências e Tecnologia
Universidade de Trás-os-Montes e Alto Douro, UTAD, http://www.utad.pt
Quinta de Prados, 5000-801 Vila Real, Portugal
1
2
Member of CIDTFF and Collaborator of CM-UTAD, Portuguese Research Centers
Member of CM-UTAD and Collaborator of CIDTFF, Portuguese Research Centers
3
Member of CM-UTAD, Portuguese Research Center
c 2014 A. P. Aires, P. Catarino, H. Campos, A. Borges and P. Vasco. This is
Copyright an open access article distributed under the Creative Commons Attribution License, which
permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
Abstract
The purpose of this paper is to obtain some identities for the sGeneralized Fibonacci sequence as a consequence of its Binet’s formula.
We also give the generating function for this sequence, as well as another
expression for its general term using the ordinary generating function.
Moreover, we find the connection between s-Generalized Fibonacci numbers and Pythagorean numbers triples.
Mathematics Subject Classification: 11B37, 11B39, 11B83, 05A15
Keywords: Fibonacci sequence; Binet’s formula; Generalized Fibonacci
sequence; Pythagorean numbers triples; Pythagorean Theorem; generating
function
1
Introduction
We are familiar with the Fibonacci numbers {Fn }n , and we know how can
we be surprised with their applications in what is around us in the world.
1758
A. P. Aires, P. Catarino, H. Campos, A. Borges and P. Vasco
This sequence is an example of a sequence defined by a recurrence relation of
second order. Such type of sequences denoted by wn (a, b; c, d) (where a, b are
non-negative integers and c, d are arbitrary integers) were studied by Horadam,
in [4] and [3]. These type of sequences are defined by the recurrence relation
of second order
wn = cwn−1 − dwn−2 , (n ≥ 2)
(1)
with initial conditions w0 = a, w1 = b. The characteristic equation of these
type of sequences is given by x2 = cx − d, which has two distinct roots when
c2 − 4d 6= 0. Note that the Fibonacci sequence is a particular case of this type
of sequence, where c = 1, d = −1, a = 0 and b = 1.
The Binet’s formula is also well known for several types of sequences.
Claude Levesque, in [7], finds the Binet’s formula for a general mth order
linear recurrence. Sometimes, some basic properties follow from this formula.
Many papers are dedicated to the Fibonacci sequence, such as the work of Hoggatt [13], Vorobiov [9], Horadam [2], [1], and also, more recently, [6], [10], [12]
and [11], among others. Horadam in [1], obtained several results related
to a Generalized Fibonacci sequence denoted by {Hp,q } (where p is a nonnegative integer and q a positive integer) with the first six terms given by
p, p + q, 2p + q, 3p + 2q, 5p + 3q, 8p + 5q, . . ., for which the nth Generalized
Fibonacci number is denoted by Hn . Note that the familiar Fibonacci sequence
is a particular case of this sequence, where p = 0 and q = 1 and Hn satisfies
the following recurrence relation:
Hn = Hn−1 + Hn−2 , (n ≥ 2),
(2)
with initial conditions H0 = p and H1 = p + q. Note that this sequence can
also be recognized as a sequence of the type wn (p, p + q; 1, −1) and the relation
(2) is equal to (1) for c = 1 and d = −1.
In what follows the Pythagorean number triples are often involved. We recall that a Pythagorean number triple is a set of three mutually prime integers
x, y and z for which x2 + y 2 = z 2 . Horadam in [2] find a connection between
Hp,q numbers and Pythagorean number triples.
In this paper we give a new generalization of the sequence {Hn }, we establish some identities involving this new sequence, we give its ordinary generating function and we find the connection between this new generalization and
Pythagorean numbers triples, following closely the paper of Horadam [2].
2
s-Generalized Fibonacci sequence and some
identities
Let p and q be a nonnegative integer and a positive integer, respectively. For
any positive real number s, the s-Generalized Fibonacci sequence, say hsp,q , is
1759
s-Generalized Fibonacci numbers
given by
p, sp + q, (s + 1)p + q, (2s + 1)p + 2q, (3s + 2)p + 3q, . . . ,
(3)
satisfying a recurrence relation similar to the usual Fibonacci sequence. If we
denote the nth s-Generalized Fibonacci number by hn , the recurrence relation
can be written as follows:
hn = hn−1 + hn−2 , (n ≥ 2)
(4)
with initial conditions given by, h0 = p, h1 = sp+q. Note that the Generalized
Fibonacci sequence {Hn } is a particular case of this sequence, with s = 1. We
can also identify the sequence {hn } as a sequence of type wn (p, sp + q; 1, −1).
Next we find the explicit formula for the term of order n of the s-Generalized
Fibonacci sequence, using the well-known results involving recursive relations.
Consider the following characteristic equation, associated to the recurrence
relation (2) and (4),
x2 − x − 1 = 0
(5)
√
√
with two roots r1 = 1+2 5 (the golden number) and r2 = 1−2 5 . The well-known
identity that allows us to obtain the nth s-Generalized Fibonacci term of this
sequence without knowing any other terms is the Binet’s formula. In this case
that formula is given in the following result:
Theorem 2.1 (Binet’s formula) The nth s-Generalized Fibonacci number is given by
1
hn = √ (lr1n − mr2n )
(6)
2 5
where l = 2(sp + q − pr2 ), m = 2(sp + q − pr1 ) and r1 and r2 are the roots of
the characteristic equation (5).
Proof. The sequence hn = c1 (r1 )n + c2 (r2 )n is the solution of the equation
(4), since the equation (5) has two distinct roots. By considering n = 0 and
n = 1 and solving this system of linear equations, we obtain a unique value for
2
√
√
, c2 = pr1 −sp−q
c1 and c2 . So, we get the following distinct values, c1 = q+sp−pr
5
5
and the result follows. Theorem 2.2 (Catalan’s identity)
hn−r hn+r −
h2n
n−r+1
= lm(−1)
r1r − r2r
lr1r − mr2r
2
h2r .
(7)
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A. P. Aires, P. Catarino, H. Campos, A. Borges and P. Vasco
Proof. Using the Binet’s formula (6) and the fact that r1 r2 = −1, we
obtain
2 hn−r hn+r − h2n = 2√1 5
(lr1n−r − mr2n−r )(lr1n+r − mr2n+r ) − (lr1n − mr2n )2
2
= 2√1 5 (−lm)(r1 r2 )n−r (r1r − r2r )2
2
= 2√1 5 lm(−1)n−r+1 (r1r − r2r )2 .
Using again the Binet’s formula, the result follows. Note that taking r = 1 in Catalan’s identity, we get the Cassini’s identity
for the s-Generalized Fibonacci sequence. In fact, the equation (7), for r = 1,
yields
2
r1 − r2
n
2
h21
hn−1 hn+1 − hn = lm(−1)
lr1 − mr2
√
and using the fact that r1 − r2 = 5, we obtain that
2
h1
2
n
.
hn−1 hn+1 − hn = 5 lm(−1)
lr1 − mr2
Now using the Binet’s formula (6) for n = 1, we proved the following result:
Theorem 2.3 (Cassini’s identity): hn−1 hn+1 − h2n =
lm(−1)n
.
4
The application of the Catalan’s identity allows us to obtain the following
formula that generalizes the Gelin-Cesàro’s identity:
.
Theorem 2.4 hn−2 hn−1 hn+1 hn+2 − h4n = − lm
4
Proof. Using the Catalan’s identity (7) with r = 1 and also with r = 2,
we obtain
lm(−1)n
2
hn−1 hn+1 − hn =
4
and
lm(−1)n−1
hn−2 hn+2 − h2n =
,
4
respectively. Multiplying both members of these identities and doing some
calculations, we obtain the required equality. The d’Ocagne’s identity can also be obtained using the Binet’s formula. In
this case we have:
Theorem 2.5 (d’Ocagne’s identity) If k > n then
k−n
1
r1 − r2k−n
n
hk hn+1 − hk+1 hn = (−1) lm
hk−n .
2
lr1k−n − mr2k−n
1761
s-Generalized Fibonacci numbers
√
Proof. Using the Binet’s formula (6), the fact that r1 r2 = −1, r1 −r2 = 5
and k > n, we get
2
1
√
hk hn+1 − hk+1 hn =
(r1 r2 )n lm(r1 − r2 )(r1k−n − r2k−n )
2 5
2
√
1
√
=
(−1)n lm 5(r1k−n − r2k−n )
2 5
2
k−n
√
1
r1 − r2k−n
n
√
=
(−1) lm 5
(lr1k−n − mr2k−n ).
k−n
k−n
lr1 − mr2
2 5
and the result follows. The limit of the ratio between two consecutive terms of the s-Generalized
Fibonacci sequence can also be calculated using the Binet’s formula (6) and
some tools of calculus of limits.In this case we obtain that:
Theorem 2.6
hn
= r1 .
n→∞ hn−1
lim
(8)
Proof. We have that
hn
lim
= lim
n→∞ hn−1
n→∞
lr1n − mr2n
lr1n−1 − mr2n−1
.
(9)
Since | rr12 | < 1, limn→∞ ( rr12 )n = 0. Writing (9) in an equivalent form as follows
hn
= lim
lim
n→∞
n→∞ hn−1
l − m( rr21 )n
!
l r11 − m( rr21 )n r12
we easily obtain the desired result. Using again some basic tools of the calculus of limits and (8) we can easily
show the following result.
Corollary 2.7
1
hn−1
=
= −r2 . n→∞ hn
r1
lim
3
(10)
s-Generalized Fibonacci sequence and ordinary generating function
Next we shall give a generating function for the s-Generalized Fibonacci sequence. We will show that the terms of this sequence can be considered as the
coefficients of the power series of the corresponding generating function. Let
1762
A. P. Aires, P. Catarino, H. Campos, A. Borges and P. Vasco
us consider the s-Generalized Fibonacci sequences (hn )n for any nonnegative
integer n. By definition of ordinary generating function of any sequence, the
ordinary generating function associated to this sequence is defined by
G(hn ; x) =
∞
X
hn xn = h0 + h1 x + h2 x2 + · · · + hn xn + · · ·
(11)
n=0
Using the initial conditions, we get
∞
X
hn xn .
(12)
(hn−1 + hn−2 )xn .
(13)
G(hn ; x) = p + (sp + q)x +
n=2
Now from (4) we can write (12) as follows
G(hn ; x) = p + (sp + q)x +
∞
X
n=2
By considering the right side of the equation (13) and doing some calculations,
we obtain
G(hn ; x) = p + (sp + q)x + x
∞
X
hn−1 x
n−1
+x
n=2
2
∞
X
hn−2 xn−2 .
(14)
n=2
Let be k = n − 1 and j = n − 2. Then the right side of the equation (14) can
be written by
#
"∞
∞
X
X
k
2
p + (sp + q)x + x
(hk x ) − p + x
hj xj
j=0
k=0
which is equal to
p + (sp + q)x − px + x
∞
X
k
hk x + x
2
∞
X
hj xj .
j=0
k=0
Therefore,
∞
X
n=0
n
hn x = p + (sp + q)x − px + x
∞
X
n=0
n
hn x + x
2
∞
X
hn xn ,
n=0
P
n
2
which is equivalent to ∞
n=0 hn x (1− x− x ) = p +(sp+ q)x − px, and then the
ordinary generating
function of the s-Generalized Fibonacci sequence can be
P
n
written as ∞
h
x
= p+(sp+q)x−px
. As a particular case, for s = 1, we get
n=0 n
1−x−x2
the ordinary generating function of the Generalized Fibonacci sequence {Hn }n
1763
s-Generalized Fibonacci numbers
P
p+qx
n
studied by Horadam in [2] and [1], i. e., ∞
n=0 Hn x = 1−x−x2 .
an+1
Recall that for a sequence (an )n , if limn→∞ an P= L, where L is a positive
n
real number, then, considering the power series ∞
n=0 an x , its radius of convergence R is equal to L1 . So, for the s-Generalized Fibonacci sequence, using
(8) we know that it can be written as a power series with radius of convergence equal to r11 . Next we give another expression for the general term of the
s-Generalized Fibonacci sequence using the ordinary generating function.
Theorem 3.1 Let us consider f (x) =
we have that hn =
function f .
f (n) (0)
,
n!
i
h
1 1
n
h
x
,
for
x
∈
−
,
. Then
n
n=0
r1 r1
P∞
where f (n) (x) denotes the nth order derivative of the
Proof. We have from (11) that f (0) = h0 = p and
0
f (x) =
∞
X
nhn xn−1 = sp + q +
∞
X
nhn xn−1 .
n=2
n=1
Also,
f
(2)
(x) =
∞
X
n(n − 1)hn xn−2
n=2
= 2 · 1 · h2 +
∞
X
n(n − 1)hn xn−2 . . . f (l) (x)
n=3
=
∞
X
n(n − 1) · · · (n − (l − 1))hn xn−l .
n=l
So,
f (l) (x) = l(l − 1) · · · (l − (l − 1))hl +
∞
X
n(n − 1) · · · (n − (l − 1))hn xn−l
n=l+1
and then we get
(l)
f (x) = l! hl +
∞
X
n(n − 1) · · · (n − (l − 1))hn xn−l .
n=l+1
Therefore, f (l) (0) = l! hl which is equivalent to hl =
n ≥ 1, we have that hn =
f (n) (0)
n!
, as required. f (l) (0)
.
l!
Hence, for all
1764
4
A. P. Aires, P. Catarino, H. Campos, A. Borges and P. Vasco
s-Generalized Fibonacci number triples
As we have mentioned before, the s-Generalized Fibonacci sequence is a case
of the sequence studied by Horadam, in [4] and [3], namely hn = wn (p, sp +
q; 1, −1). Using Lemmas (2.1) and (2.2) established in [5] applied to this
sequence we get respectively the following identities:
2hn+2 − hn+3 = hn , 2hn+2 + hn+3 = 4hn+2 − hn .
(15)
Also the Theorem (3.1) in [5], for this case, give us the following identity
(hn hn+3 )2 + (2hn+2 (hn+2 − hn ))2 = (h2n + 2hn+2 (hn+2 − hn ))2
(16)
that, using (4), can be simplified as follows
(hn hn+3 )2 + (2hn+2 hn+1 )2 = (h2n + 2hn+2 hn+1 )2 .
(17)
The triple consisting of the three numbers involving s-Generalized Fibonacci
numbers stated in (16) and (17) are called a s-Generalized Fibonacci number
triple. In [1], Horadam stated without proof the ”Pythagorean Theorem” (see
(16) in [1]) concerning the sequence {Hn }n and in ?? he gives its proof. It is
well known that all Pythagorean triples are given by (x2 − y 2 , 2xy, x2 + y 2 )
where x > y and x and y are mutually prime but not simultaneously odd,
so that x + y is always odd. Let us consider, in this case, x = hn+2 and
y = hn+2 −hn = hn+1 , n ≥ 0. Then x2 −y 2 = hn hn+3 , 2xy = 2hn+2 (hn+2 −hn )
and x2 +y 2 = h2n +2hn+2 (hn+2 −hn ). Then we have the following result involving
this type of triples:
Theorem 4.1 All Pythagorean triples are s-Generalized Fibonacci number
triples.
Proof. Put p = s(x − y), sp + q = sy and then (3) gives us the following
sequence
s(x − y), sy, sx, s(x + y), s(2x + y), . . .
(18)
For n = 0, using (17) and (18) and doing some calculations we have
(h0 h3 )2 +(2h2 h1 )2 = (h20 +2h2 h1 )2 ⇔ (s2 (x2 −y 2 ))2 +(2s2 xy)2 = (s2 (x2 +y 2 ))2 ,
(19)
which proves the Theorem. Note that if s = 1 we have p = x − y, q = 2y − x and the equation (19)
gives (x2 − y 2 )2 + (2xy)2 = (x2 + y 2 )2 that proves the Theorem 2 in [2], a
particular case of Theorem 4.1.
In [5], Shannon and Horadam showed the possibility to relate the results of
Teigen and Hadwin [4] to the generalized sequence wn (a, b; c, d). In particular,
s-Generalized Fibonacci numbers
1765
in this paper, the authors conclude that (17) is valid for the sequence {Hn }n
and the method of Teigen and Hadwin are related. Now we generalize this
result by showing also how (17) and this method are related as well. In fact,
Teigen and Hadwin, proved that a Pythagorean triple (u, v, w) can be represented by u = x + z, v = y + z, w = x + y + z, where x, y and z are all positive,
2xy = z 2 and z is even. For the s-Generalized Fibonacci sequence, consider
x = h2n , z = 2hn hn+1 , then z 2 = 2h2n (2h2n+1 ), so that y = 2h2n+1 . Using (4) and
(15) we get
u = h2n + 2hn hn+1 = hn (hn + 2hn+1 ) = hn (2hn+2 − hn+3 + 2hn+1 ) = hn hn+3 ,
v = 2h2n+1 + 2hn hn+1 = 2hn+1 (hn+1 + hn ) = 2hn+1 hn+2
and
w = h2n + 2h2n+1 + 2hn hn+1 = h2n + 2hn+1 (hn+1 + hn ) = h2n + 2hn+1 hn+2 .
Hence (u, v, w) = (hn hn+3 , 2hn+1 hn+2 , h2n + 2hn+1 hn+2 ) is related to the
s-Generalized Fibonacci number triple (17).
Acknowledgements. The first author is a Member of the research center
CIDTFF-Centro de Investigação em Didáctica e Tecnologia na Formação de
Formadores (CIDTFF/UTAD) and the others authors are Members of the
research center CM-UTAD-Centro de Investigação em Matemática da UTAD.
This work has been partially supported by the Portuguese Government through
the FCT - Fundação para a Ciência e a Tecnologia - under the projects PEstC/CED/UI0194/2013-2014 and PEst-OE/MAT/UI4080/2014.
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Received: July 9, 2014
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