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Unit 4: Triangle Congruence 4.8 Isosceles and Equilateral Triangles (Part 1) Warm Up 11/22 (HW #21 [4.8] Page 277 #s 13 – 20) 1. Find each angle measure. A 60°; 60°; 60° 2. Solve x2 + 5x + 6 = 0 for x. x = – 3 and x = – 2 B C Objectives Prove theorems about isosceles triangles. Apply properties of isosceles triangles. *Standard 12.0 Students find and use measures of sides and of interior and exterior angles of triangles and polygons to classify figures and solve problems. (see page 273) Recall that an isosceles triangle has at least two congruent sides. The congruent sides are called the legs. The vertex angle is the angle formed by the legs. The side opposite the vertex angle is called the base, and the base angles are the two angles that have the base as a side. 3 is the vertex angle. 1 and 2 are the base angles. (see page 273) Example 2A: Finding the Measure of an Angle (see page 274) Find mF. mF = mD = x° mF + mD + mA = 180 x + x + 22 = 180 2x = 158 x = 79 Isosc. ∆ Thm. ∆ Sum Thm. Substitute the given values. Simplify and subtract 22 from both sides. Divide both sides by 2. Thus mF = 79° Check It Out! Example 2A (see page 274) Find mH. mH = mG = x° mH + mG + mF = 180 x + x + 48 = 180 2x = 132 x = 66 Thus mH = 66° Isosc. ∆ Thm. ∆ Sum Thm. Substitute the given values. Simplify and subtract 48 from both sides. Divide both sides by 2. 1. Find x. A B C D Example 2B: Finding the Measure of an Angle (see page 274) Find mG. mJ = mG (x + 44) = 3x 44 = 2x x = 22 Isosc. ∆ Thm. Substitute the given values. Simplify x from both sides. Divide both sides by 2. Thus mG = 22° + 44° = 66° mG = 66° Check It Out! Example 2B (see page 274) Find mN. mP = mN Isosc. ∆ Thm. (8y – 16) = 6y Substitute the given values. 2y = 16 Subtract 6y and add 16 to both sides. y = 8 Divide both sides by 2. Thus mN = 6(8) = 48°. mN = 48° 2. Find mR and mP. 3. The vertex angle of an isosceles triangle measures (a + 15)°, and one of the base angles measures 7a°. Find a and each angle measure.