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BINOMIAL vs. GEOMETRIC DISTRIBUTIONS ASSUMPTIONS DESCRIPTION FORMULA TI instructions Discrete BINOMIAL 1. 2 outcomes: “success” & not “success” 2. Independent trials 3. P(“success”) is constant 4. Number of trails is fixed B(n, p) P(X = k)= n Ck pkqn-k where: n = # of trials k = # of “successes” p = probability of “success” q = probability of not “success” binompdf (n, p, X) binomcdf (n, p, X) Discrete GEOMETRIC 1. 2 outcomes: “success” & not “success” 2. Independent trials 3. P(“success”) is constant 4. X is the 1st trial G(p) Example: What is the probability that I will get 3 Lady Gaga’s (p = 0.2) out of 10 boxes? Example: What is the probability that I will get my first Lady Gaga (p = 0.2) on the 3rd or 4th box? Answer: 1 – binomcdf(10, .2, 3) Or, C4 (.2 4 )(.86 )+ 10 C5 (.2 5 )(.85 ) 10 Answer:geometpdf(.2,3)+geometpdf(.2,4) Or, P(X is 1st)= q x-1p where X is the Xth geometpdf (p, X) geometcdf (p, X) (.82 )(.2)+(.83 )(.2) +...+ 10 C10 (.210 )(.80 ) NORMAL APPROXIMATION OF BINOMIAL & GEOMETRIC* DISTRIBUTIONS ASSUMPTIONS Continuous BINOMIAL 1. np ³ 10 and nq ³10 2. DESCRIPTION FORMULA N(m,s) m = np Continuous GEOMETRIC Normal approximation NOT used because geometric distribution is skewed m= 1 p s = npq x -m s Normcdf(lower, upper) s= q z= TI instructions * Normal approximation of geometric not included in AP Statistics. p2