Download EAL Secondary Maths_Tests_And_Answers

Mathematics 1
(1)
Fill in the empty boxes.
1
2
(2)
4+3 =
(3) 10 - 9 =
(4)
2x6 =
(5) 15 3 =
(6)
859 x 3 =
(9)
(11)
258
188
+ 387
___
4
6
(7)
(10)
a) 4 +
= 7
b) 4 -
=2
c) 3 x
= 9
d) 20 
=5
7
150  5 =
9
10
13
(8) 3.14 + 6.2 =
537
- 318
___
If pupil has completed the above, move on to NC Level Questions
1
Mathematics Assessment 2
Level 3
(A) You can make six numbers using these digit cards:
Complete the list to show the six different numbers.
Answer of 100
(B) Fill in the missing numbers.
68
+
20
×
300

..............
..............
..............
=
100
=
100
=
100
2
65
(C)
×
–
2
..............
=
100
Sums
Calculate:
52 – 38
=
………...
259 + 386
=
………...
36 × 4
=
……….....
135 ÷ 5
=
……….....
Level 4
(D)
Forty-five
(a)
Fill in the missing numbers so that the answer is always 45.
The first one is done for you.
5
40 + ......
142 – ..........
50% of ..........
= 45
450 
1 of ..........
4
3
(E)
Multiplication
Work out 32 × 21
Show your working.
.....................................
(F)
Missing numbers
Fill in the missing numbers.
(G)
3.7
+
2.9
+
2.5
=
=
4
Fractions
(a)
Look at these fractions:
1
2
1
3
5
6
Mark each fraction on the number line.
The first one is done for you.
0
1
1
2
4
(H)
Equations
Solve these equations.
a + 12 = 24
a = ………………….
b – 12 = 24
b = …………………
Level 5
(I)
Each diagram below was drawn on a square grid.
(a) Write what percentage of each diagram is shaded.
The first one is done for you.
75
...............
%
............... %
............... %
5
(J)
Percentages
(Use a Calculator)

Calculate:
8% of £26.50 = £
12½ % of £98 = £
(K)
Solving
(a)
When x = 5, work out the values of the expressions below.
2x + 13 = .........................
5x – 5 = ...........................
3
+ 6x = ...........................
Level 6
(L)
Calculate
Calculate 57.3 × 2.1
Show your working.
. . . . . . . . …………….
6
(M)
Thinking fractions
Calculate 5  3
6 5
Show your working.
Write your answer as a fraction in its simplest form.
………………………..
(N)
Solve these equations.
Show your working.
8k  1 = 15
k = ............................
2m + 5 = 10
m = ............................
3t + 4 = t + 13
t = ............................
7
Level 7
(o) Multiplication grids
Write the missing numbers in these multiplication grids.
×
8
9
72
–6
×
3
30
0.2
1.2
6
3 marks
(p)
Finding y
Solve these equations. Show your working.
(a)
4 – 2y  10 – 6y
y
.........................
2 marks
8
(b)
5y + 20  3(y – 4)
y  .........................
2 marks
(c)
9y
9
2y 1
y  .........................
2 marks
9
(d)
9

y2
y2
y  ......................... or .........................
2 marks
(q)
Algebra
(a)
Find the values of a and b when p  10
a
3 p3
2
a  .........................
1 mark
b
2 p 2  p – 3
7p
b  .........................
1 mark
10
(b)
Simplify this expression as fully as possible:
3cd 2
5cd
1 mark
(c)
Multiply out and simplify these expressions:
3(x – 2) – 2 (4 – 3x)
1 mark
(x + 2)(x + 3)
1 mark
(x + 4)(x – 1)
1 mark
(x – 2)2
1 mark
11
Level 8
(r)
Writing Numbers
1
is equal to 0.0004
2500
(a)
Write 0.0004 in standard form.
...............................
1 mark
(b)
Write
1
in standard form.
25000
...............................
1 mark
(c)
Work out
1
1

2500 25000
Show your working, and write your answer in standard form.
...............................
2 marks
12
(s) Graphs
Match each graph to the correct equation.
A
B
y
C
y
x
D
y
x
E
y
x
y
x
x
Graph ................ shows the equation y  2x – 6
Graph ................ shows the equation y  6x3
Graph ................ shows the equation y  6 – x
Graph ................ shows the equation y  x2 – 6
Graph ................ shows the equation y  1
6x
2 marks
13
Mathematics 1
(Answers)
(1)
Fill in the empty boxes.
1
2
(2)
4+3 =
(4)
(6)
(9)
3
4
6
7
7
(3)
10 - 9 =
1
2x6 =
12
(5)
15 3 =
5
859 x 3 =
2577
150  5 =
30
258
188
+ 387
833
5
(7)
(10)
8
9
10
(8)
11
12
3.14 + 6.2 =
13
9.34
537
- 318
219
Fill in the blanks using words:
(11)
a) 3
b) 2
c) 3
d) 4
14
Mathematics Assessment 2
(Answers)
Level 3
(A)
You can make six numbers using these digit cards:
3
5
7
Complete the list to show the six different numbers.
357
375
537
573
735
753
Answer of 100
(B)
Fill in the missing numbers.
68
+
32
..............
=
100
20
×
5
..............
=
100
300

3
..............
=
100
15
65
(C)
×
2
30
..............
–
=
Sums
Possible methods/strategies
Calculate:
4
52 – 38
52
- 38
14
100
1
10
4
= 14
38
259 + 386 = 645
36 × 4
= 144
135 ÷ 5
= 27
48
52
259
+ 386
645
36
x 4
144
27
5 1335
36 x 2 = 72
72 x 2 = 144
135  10 = 13.5
13.5 x 2 = 27
16
Level 4
(D)
Forty-five
(a)
Fill in the missing numbers so that the answer is always 45.
The first one is done for you.
10
40 + 5
142 – 97
50% of 90
= 45
450  10
1 of 180
4
(E)
Multiplication
Work out 32 × 21
Show your working.
Alternatively
x
30
2
20
600
40
1
30
2
640
32
32
x 21
32
640
672
672
672
.....................................
17
(F)
Missing numbers
Fill in the missing numbers.
(G)
3.7
+
2.9
+
2.5
1.1
=
6.2
=
4
3.7
+ 2.5
6.2
Fractions
(a)
Look at these fractions:
1
2
1
3
5
6
Mark each fraction on the number line.
The first one is done for you.
0


1
3
5
6
1
1
2
(H)
Equations
Solve these equations.
a + 12 = 24
a = 24 - 12
12
a = ………………….
b – 12 = 24
b = 24 + 12
36
b = …………………
18
Level 5
(I)
Each diagram below was drawn on a square grid.
(b) Write what percentage of each diagram is shaded.
The first one is done for you.
75
...............
%
60
............... %
60
............... %
(J)
Percentages B
Calculate using calculator
£ 2.12
0.08 x 26.50
£ 12.25
0.125 x 98
8% of £26.50 =
12½ % of £98 =
19
(K)
Solving
(a)
When x = 5, work out the values of the expressions below.
(2x 5 + 13 = 23)
23
2x + 13 = .........................
(5x 5 – 5 = 20)
20
5x – 5 = ...........................
4
(3 + 6x 5 = 33)
33
+ 6x = ...........................
Level 6
0
Calculate
Calculate 57.3 × 2.1
Show your working.
114.6
573
21
573
11460
12033
50
7
0.3
2
100
14
0.6
0 .1
5
0.7
0.03
5.73
120.33
. . . . . . . . …………….
(M)
Thinking fractions
53
Calculate 6 5
Show your working.
15
30

1
2
or
20
1
5
62
1
3
x
=
51
1
2
Write your answer as a fraction in its simplest form.
1
2
………………………..
(N)
Solve these equations.
Show your working.
8k  1 = 15
8k = 16
2
k = ............................
2m + 5 = 10
2m = 5
2.5
m = ............................
3t + 4 = t + 13
2t = 9
4.5
t = ............................
1.
Completes both multiplication grids correctly,
ie
×
8
–5
9
72
–45
–6
–48
30
3
21
×
0.2
0.4
3
0.6
1.2
15
3
6
or
Completes one of the grids correctly and makes not more
than one error or omission in the other grid
2
or
Completes one of the grids correctly
1
or
Makes not more than one error or omission in each grid
!
For 2m or 1m, follow through
For the first grid, accept follow through only
from their –5 but note that their –5 must be
negative
eg

–6
(error but negative)
×
8
9
72
–54
–6
–48
30
follow through
For the second grid, accept follow through
only from their 15
eg

×
0.2
0.4
3
0.6
1.2
10
(error)
2
6
follow through
[3]
22
2.
Finding y
(a)
For 2m indicates a correct value, with no evidence that the value is
derived
from an incorrect method, eg:
2
1.5
For only 1m correctly reduces the equation to 2 terms, eg:
4y = 6
-4y = – 6
4y – 6 = 0
y=6÷4
y=
or
6
4
Solves for y with not more than one computational error, eg:
6y – 2y = 10 – 4
4y = 8
y=2
For 2m accept an improper fraction written
in its simplest terms eg:
3
‘2’
Throughout the question do not accept
incorrect methods leading to a correct value
eg for part (a)
‘10 + 4 = 6y + 2y, 14 = 8y, y = 1.5’
For 1m throughout the question accept
decimals rounded or truncated to 1 or more
d.p.
Throughout the question do not accept
inability to process negative values as a
computational error eg, in part (a)
from 4 – 2y = 10 – 6y,
accept 6y – 2y and 10 – 4,
but not 6y + 2y or 10 + 4,
or 8y
or 14
(b)
For 2m indicates – 16
2
For only 1m correctly multiplies y – 4 by 3, eg:
3y – 12 seen
5y – 3y = –20 – 12
2y = –32
y=–
(c)
32
2
For 2m indicates –1
2
For only 1m correctly reduces the equation to 2 terms, eg:
9y = –9
-9y = 9
23
0 = 9y + 9
or
Correctly multiplies 2y + 1 by 9, eg:
18y + 9 seen
or
Shows a correct simplification, eg:
y
1
2y 1
(d)
For 2m indicates both y = 1 and y = –5
2
For only 1m shows one correct solution, with no evidence that the
solution found is derived from an incorrect method.
or
Shows a correct simplification of 9 = (y + 2) 2, eg:
9 = y2 + 4y + 4
9 = y2 + 2y + 2y + 4
5 = y(y + 4)
y+2=
9=3
3=y+2
The other solution may be incorrect or
omitted.
[8]
3.
(a)
(b)
Indicates 1500
1
Indicates 20
1
Indicates a correct, fully simplified expression eg:
1
'
3d
'
5
3
' d'
5
3d ÷ 5
0.6d
Do not accept unconventional fractions eg:
'
(c)
1.5
d'
2.5
Indicates a correct, fully simplified expression for 3(x – 2) – 2(4 –
3x) eg:
1
9x – 14
–14 + 9 × x
Indicates a correct simplified expression for (x + 2) (x + 3) eg:
1
x2 + 5x + 6
x2 + 6 + 5 × x
24
Indicates a correct simplified expression for (x + 4) (x – 1) eg:
1
x2 + 3x – 4
3 × x – 4 + x2
Indicates a correct simplified expression for (x – 2)2 eg:
1
x2 – 4x + 4
x2 + x × – 4 + 4
x2 + 4(-x + 1)
x2 should be written with index notation, ie
not as x × x or xx. However, do not penalise
this error more than once within the
question.
Throughout the question do not accept
continuation from a correct response to an
incorrect response eg:
‘x2 + 5x + 6 = 5x3 + 6’
[7]
4.
Writing Numbers
(a)
4 × 10–4 or 4 × 10-04
!
Unconventional index from notation
eg, for part (a)
0.4 × 10–3
1
4 104
Penalise the first occurrence only.
Do not accept incorrect notation
eg, for part (a)
4–4
(b)
4 × 10–5
!
1
Follow through from part (a)
Provided the power is negative
eg, for part (a) as 2 × 10–5
2 × 10–6
(c)
4.4 × 10–4
2
or
1
Digits 44 seen
eg
25
4400
0.00044
44
100000
Do not accept digits 44 seen from an
incorrect method
eg
4 × 10–4 + 4 × 10–5 = 44 × 10–9
[4]
5.
Graphs
Gives all five correct letters in the correct order, ie
D
C
B
A
E
2
or
Gives at least three correct letters
1
[2]
26