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Sampling Distribution for the Sample Mean Population = 1, 2, 3
Mean: 𝜇 = 2 Standard Deviation: 𝜎 = 0.816 All possible samples of size: n = 2 1, 1 1, 3 2, 2 3, 1 3, 3 Sample 1 +𝟏 = 𝟏 Mean: 𝒙
St. Dev: 𝑠 = 0 Sample 3 +𝟑 = 𝟐 Mean: 𝒙
St. Dev: 𝑠 = 1.414 Sample 5 +𝟓 = 𝟐 Mean: 𝒙
St. Dev: 𝑠 = 0 Sample 7 +𝟕 = 𝟐 Mean: 𝒙
St. Dev: 𝑠 = 1.414 Sample 9 +𝟗 = 𝟑 Mean: 𝒙
St. Dev: 𝑠 = 0 1, 2 2, 1 2, 3 3, 2 Sample 2 +𝟐 = 𝟏. 𝟓 Mean: 𝒙
St. Dev: 𝑠 = 0.707 Sample 4 +𝟒 = 𝟏. 𝟓 Mean: 𝒙
St. Dev: 𝑠 = 0.707 Sampling Distribution of the Sample Mean (Collect all of the 𝒙
+ ’s) +𝟏 = 𝟏
𝒙
+𝟐 = 𝟏. 𝟓
𝒙
+𝟑 = 𝟐
𝒙
+𝟒 = 𝟏. 𝟓
𝒙
+𝟓 = 𝟐
𝒙
+𝟔 = 𝟐. 𝟓
𝒙
+𝟕 = 𝟐
𝒙
+𝟖 = 𝟐. 𝟓
𝒙
+𝟗 = 𝟑
𝒙
Sample 6 Find the mean and standard deviation of all
𝒙
+’s above.
Sample 8 The mean of the sampling distribution of
sample mean. (Mean of all 𝒙
+’s.)
𝝁𝒙+ = 𝟐
+𝟔 = 𝟐. 𝟓 Mean: 𝒙
St. Dev: 𝑠 = 0.707 +𝟖 = 𝟐. 𝟓 Mean: 𝒙
St. Dev: 𝑠 = 0.707 The standard deviation of the sampling
distribution of sample means. (Standard
deviation of all 𝒙
+’s.)
𝝈𝒙+ = 𝟎. 𝟓𝟕𝟕
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