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Evaluate trigonometric functions of acute angles, and use a
calculator to evaluate trigonometric functions.
Use the fundamental trigonometric identities.
Use trigonometric functions to model and solve real-life problems.
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Focus and Review
Attendance
Questions from yesterday’s work
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4.3
Right Triangle Trigonometry
Copyright © Cengage Learning. All rights reserved.
Objectives
 Evaluate trigonometric functions of acute
angles, and use a calculator to evaluate
trigonometric functions.
 Use the fundamental trigonometric identities.
 Use trigonometric functions to model and solve
real-life problems.
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The Six Trigonometric Functions
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The Six Trigonometric Functions
This section introduces the trigonometric functions from a
right triangle perspective.
Consider a right triangle with one acute angle labeled  , as
shown below. Relative to the angle , the three sides of the
triangle are the hypotenuse, the opposite side (the side
opposite the angle  ), and the adjacent side (the side
adjacent to the angle  ).
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The Six Trigonometric Functions
Using the lengths of these three sides, you can form six
ratios that define the six trigonometric functions of the
acute angle .
sine cosecant
cosine
secant
tangent
cotangent
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The Six Trigonometric Functions
In the following definitions, it is important to see that
0 <  < 90 ( lies in the first quadrant) and that for such
angles the value of each trigonometric function is positive.
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Memory Aid
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The Six Trigonometric Functions
In the following definitions, it is important to see that
0 <  < 90 ( lies in the first quadrant) and that for such
angles the value of each trigonometric function is positive.
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Example 1 – Evaluating Trigonometric Functions
Use the triangle in Figure 4.20 to find the values of the six
trigonometric functions of .
Solution:
By the Pythagorean Theorem,
(hyp)2 = (opp)2 + (adj)2, it follows that
Figure 4.20
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Example 1 – Solution
cont’d
So, the six trigonometric functions of  are
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Example 1 – Solution
cont’d
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Practice
Problems 7, 8, 13, 18
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The 45-45-90 Triangle and the
30-60-90 Triangle
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The Six Trigonometric Functions
In Example 1, you were given the lengths of two sides of
the right triangle, but not the angle .
Often, you will be asked to find the trigonometric functions
of a given acute angle . To do this, construct a right
triangle having  as one of its angles.
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The 45-45-90 Triangle
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The 45-45-90 Triangle
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The 45-45-90 Triangle
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The 45-45-90 Triangle
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The 45-45-90 Triangle
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The 45-45-90 Triangle
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The 45-45-90 Triangle
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The 30-60-90 Triangle
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The 30-60-90 Triangle
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The 30-60-90 Triangle
2
2
1
1
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The 30-60-90 Triangle
2
1
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The 30-60-90 Triangle
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The Six Trigonometric Functions
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The Six Trigonometric Functions
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The Six Trigonometric Functions
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Applications Involving Right Triangles
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Applications Involving Right Triangles
Many applications of trigonometry involve a process called
solving right triangles.
In this type of application, you are usually given one side of
a right triangle and one of the acute angles and are asked
to find one of the other sides, or you are given two sides
and are asked to find one of the acute angles.
In Example 8, the angle you are given is the angle of
elevation, which represents the angle from the horizontal
upward to an object.
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Applications Involving Right Triangles
Find the measure of each side indicated. Round to the
nearest tenth.
A
B
A
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C
B
C
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Applications Involving Right Triangles
Find the measure of each angle indicated. Round to the
nearest tenth.
3
200 yd
400 yd
3
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Applications Involving Right Triangles
In the following example, the angle you are given is the
angle of elevation, which represents the angle from the
horizontal upward to an object.
In other applications you may be given the angle of
depression, which represents the angle from the
horizontal downward to an object. (See next slide.)
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Applications Involving Right Triangles
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Example 8 – Using Trigonometry to Solve a Right Triangle
A surveyor is standing 115 feet from the base of the
Washington Monument, as shown in figure below. The
surveyor measures the angle of elevation to the top of the
monument as 78.3. How tall is the Washington
Monument?
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Example 8 – Solution
From the figure, you can see that
where x = 115 and y is the height of the monument. So, the
height of the Washington Monument is
y = x tan 78.3
 115(4.82882)
 555 feet.
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Applications Involving Right Triangles
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Cofunctions of Complimentary Angles
In the box, note that sin 30 = = cos 60. This occurs
because 30 and 60 are complementary angles.
In general, it can be shown from the right triangle
definitions that cofunctions of complementary angles are
equal. That is, if  is an acute angle, then the following
relationships are true.
sin(90 –  ) = cos 
cos(90 –  ) = sin 
tan(90 –  ) = cot 
cot(90 –  ) = tan 
sec(90 –  ) = csc 
csc(90 –  ) = sec 
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Cofunctions of Complimentary Angles
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Cofunctions of Complimentary Angles
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Cofunctions of Complimentary Angles
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Cofunctions of Complimentary Angles
Equivalent statements can be derived relating cosine,
cotangent, and cosecant to sine, tangent, and secant,
respectively. Therefore, the following cofunction
relationships hold:
sin(90 –  ) = cos 
cos(90 –  ) = sin 
tan(90 –  ) = cot 
cot(90 –  ) = tan 
sec(90 –  ) = csc 
csc(90 –  ) = sec 
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Trigonometric Identities
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Trigonometric Identities
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Cofunctions of Complimentary Angles
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Trigonometric Identities
In trigonometry, a great deal of time is spent studying
relationships between trigonometric functions (identities).
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Important Note
You need to memorize all of the
Fundamental Trigonometric
Identities found on page 282
verbatim. Stating these
identities will be included on all
of the quizzes and tests for the
remainder of Chapter 4.
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Example 5 – Applying Trigonometric Identities
Let  be an acute angle such that sin  = 0.6. Find the
values of (a) cos  and (b) tan  using trigonometric
identities.
Solution:
a. To find the value of cos , use the Pythagorean identity
sin2  + cos2  = 1.
So, you have
(0.6)2 + cos2  = 1
Substitute 0.6 for sin .
cos2  = 1 – (0.6)2
Subtract (0.6)2 from each side.
cos2  = 0.64
Simplify.
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Example 5 – Solution
cont’d
cos  =
Extract positive square root.
cos  = 0.8.
Simplify.
b. Now, knowing the sine and cosine of , you can find the
tangent of  to be
= 0.75.
Use the definitions of cos  and
tan , and the triangle shown in
Figure 4.23, to check these results.
Figure 4.23
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Example 6 – Applying Trigonometric Identities
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Independent Practice
Section 4.3 (page 286)
# 1 – 4 (vocabulary), 5, 6, 10, 13, 14, 15, 16, 17, 19, 31 –
34, 41, 42, 45, 46, 47, 49, 51, 53, 55, 57, 59, 61, 63, 66, 69,
71, 73
Extra Credit: # 76 (5 points on next quiz)
IMPORTANT NOTE: Problem 65 has
been changed to Problem 66.
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