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CHAPTER 2 SEQUENCES
AND SERIES
Tori Beals, 3rd Hour
Trevor Campbell, 5th Hour
NUMBER PATTERNS (SECTION A)
A list of numbers where there is a pattern is
called a number sequence
The numbers in the sequence are said to be its
members or terms
Example of a number sequence 2, 4, 6, 8, 10, 12
The third term of this sequence is 6
SEQUENCES OF NUMBERS
(SECTION B)
A number sequence is a set of numbers defined
by a rule that is valid for positive integers
The general term or nth term is represented by
Un
Sequences may be defined in one of the following
ways
Listing the first few terms and assuming that the
pattern represented continues indefinitely
Giving a description in words
Using a formula which represents the general term
or nth term
CONT.
Example, Section 2B, #1). List the first five terms
of:
A) {2n}
2, 4, 6, 8, 10
B) {2n+2}
4, 6, 8, 10, 12
C) {2n-1}
1, 3, 5, 7, 9
D) {2n-3}
-1, 1, 3, 5, 7
ARITHMETIC SEQUENCES
(SECTION C)
An arithmetic sequence is a sequence in which
each term differs from the previous one by a fixed
number
Un is arithmetic if and only if U(n+1)=d for all
positive n integers where d is a constant called
the common difference
For an arithmetic sequence with the first term
U1 and common difference d the general term or
nth term is
Un=U1+(n-1)d (The general term formula)
CONT.
The name ‘arithmetic’:
If a, b, and c are any consecutive terms of an
arithmetic sequence then:
b-a= c-b
2b= a+c
b=(a+c)/2
So, the middle term is the arithmetic mean
of the terms on either side of it.
CONT.
Example 2C. 5) A
sequence is defined by
Un=3n-2
A)
Prove the sequence is
arithmetic (hint: find
U(n+1)-Un)
If n= 2 then
U2=3(2)-2
U2=4
and
U1=3(1)-2
U1=1
D=3
If n=4 then
U5=3(5)-2
U5=13
And
U4=3(4)-2
U4=10
D=3
CONT.
5c. Find the 57th term.
Un = 3n −2
U57 = 3(57) – 2
U57 = 171 −2
U57 = 169
5d. What is the least
term of the sequence
which is greater than
450?
U150 = 448
U151 = 451
U152 = 454
The 151st term is the
first (least) term of the
sequence that is
greater than 450.
GEOMETRIC SEQUENCES
(SECTION D)
A sequence is geometric if each term can be
obtained from the previous one by multiplying
the same non-zero constant.
For example: 2, 10, 50, 250, … is a geometric
sequence.
2×5= 10, 10×5= 50, 50×5= 250
Each term divided by the previous one gives the same
constant.
o
The general term for a geometric sequence is:
Un = U1 rn−1
CONT.
The name ‘geometric’:
If a, b, and c are consecutive integers of a
geometric sequence, then b/a = c/b.
Compound Interest:
General Compound Interest formula:
Un+1 = U1 × rn
CONT.
Example, Section 2D, #4:
a. Show that the sequence 5, 10, 20, 40, … is geometric.
10/5= 2, 20/10= 2, 40/20= 2. Therefore, U1 = 5, and r = 2.
Find Un and hence find the 15th term.
Un = (5)(2)n-1
U15 = (5)(2)15−1
(5)(2)14
(5)(16,384)
U15 = 81,920
CONT.
Example, Section 2D, #4:
a. Show that the sequence 5, 10, 20, 40, … is geometric.
10/5= 2, 20/10= 2, 40/20= 2. Therefore, U1 = 5, and r = 2.
Find Un and hence find the 15th term.
Un = (5)(2)n-1
U15 = (5)(2)15−1
(5)(2)14
(5)(16,384)
U15 = 81,920
SERIES
(SECTION E)
A series is the addition of the terms of a
sequence.
For the series { Un }, the corresponding series is
U1 + U2 + U3 + … + Un
The sum of a series is the result when we
perform the addition.
Given a series which includes the first n terms of
a sequence, its sum is Sn = U1 + U2 + U3 + … Un .
SIGMA NOTATION
Series can be written more compactly using
sigma notation.
uk
U1 + U2 + U3 + … Un is written as
This reads “the sum of all numbers of the form uk
where k = 1, 2, 3, … , up to n”.
PROPERTIES OF SIGMA NOTATION
CONT.
An arithmetic series is the addition of
successive terms of an arithmetic sequence.
Sum of an arithmetic series:
Sn = n/2( u1 + un)
OR
Sn = n/2(2u1 + (n −1)d)
CONT.
A geometric series is the addition of successive
terms of a geometric sequence.
Sum of a geometric series:
Sn = u1 (rn – 1) ÷ (r −1)
OR
Sn = u1 (1 − rn) ÷ (1 − r)
SUM OF AN INFINITE GEOMETRIC SERIES
When n becomes very large, Sn will change.
If r > 1, the series is divergent and the sum
becomes infinitely large.
If -1 < r < 1, then rn approaches 0 for very large n.
We say the series converges. Its sum is written
as:
Sn = u1 ÷ (1 –r), for r < 1
MORE EXAMPLE PROBLEMS
Section 2C, #7a. :
Find k given the consecutive arithmetic terms.
32, k, 3
k – 32 = 3 – k
2k – 32 = 3
2k = 35
k = 17.5
MORE EXAMPLE PROBLEMS (CONT.)
Section 2D, Example 10, page 79.
$5000 is invested for 4 years at 7% p.a. compound
interest, compounded annually. What will it
amount to at the end of this period?
5000 × (1.07)4
≈ 6553.98
It amounts to about $6553.98
MORE EXAMPLE PROBLEMS (CONT.)
Section 2E.1, #2a.
Expand and evaluate:
( Expand 3k – 5, starting with the first term of -2 and
stopping at the fourth term, 7).
= -(2) + 1 + 4 + 7
= 10
MORE EXAMPLE PROBLEMS (CONT.)
Section 2E.2, #1a.
Find the sum of:
3 + 7 + 11 + 15 + … to 20 terms.
U1 = 3 d = 4 n = 20
S20 = 20/2 (2(3) + (20 −1)4)
10(6 + 76)
10(82)
S20 = 820
MORE EXAMPLE PROBLEMS (CONT.)
Section 2E.3, #1a.
Find the sum of the following series:
12 + 6 + 3 + 1.5 + … to 10 terms.
U1 = 12 r = ½ n = 10
S10 = (12( 1 – 1/2 10) ÷ (1 – ½ )
(12(1 −1/1024) ÷ ½
(12(1023/1024)) ÷ ½
(11.99) ÷ ½
S10 ≈ 23.98
S10 ≈ 24
GOLDEN PACKET MATERIALS
General term of an arithmetic sequence
General term of a geometric sequence
Sum of the terms of an arithmetic sequence
Sum of the terms of a finite geometric sequence
Sum of an infinite geometric sequence
NEED TO MEMORIZE
Compound Interest Formula