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Topic: Date: Page # Ohm’s Law Lab 6/5/2014 168 Seed Question: Suppose you were to apply different voltages across a light-bulb and record the corresponding currents through the bulb. What do you think the graph of Voltage vs Current would look like? Sketch it! V vs I I V V R 0 I Exploration: Let’s investigate the relationship between voltage across a light bulb and current through it, by testing a bulb to destruction. Hook up the light bulb to the power supply, being careful not to short circuit the power supply by touching the ends of the leads together. Before you turn on the power supply make sure the voltage knob is rotated fully counterclockwise: 0 V. Keep the current knob rotated fully clockwise for this lab. Read the voltage (in volts V) and current (in amps A) right off the power supply panel, recording it by hand here. Start from 0 and increase go up by 0.5 V, recording your data rapidly until the bulb burns out. You only get 1 shot at this. Do a large, hand plotted graph of voltage vs current: Make sure V is on the y-axis. Make sure your data stretches over at least the top half of page 169. Plot a best-fit line of the linear portion of your graph and find its slope. Show your calculation directly on the graph: draw a large triangle, indicate the rise and run and don’t forget the units! V (V) I (A) Why did your burn out? Look at your light bulb carefully and 0 0 see how it is different. What changed? 0.5 1.0 etc What can you conclude about the way voltage depends on current? State it mathematically. What does the slope of your graph represent? Big Idea: The light bulb is not quite an ideal resistor. Ideal resistors have voltages that depend linearly on current: they have a constant resistance and obey Ohm’s Law: Ohm’s Law: V = I R Units: volts (V) amps (A) ohm’s Ω 1 V = 1 A∙Ω The resistance R is the slope of the graph of V vs I, and has units of Ω: 1 Ω = 1 V/A For Further Contemplation: ?