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Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 RESEARCH Open Access Generalized q-Bessel function and its properties Mansour Mahmoud* * Correspondence: [email protected] Mathematics Department, Faculty of Science, King Abdulaziz University, P.O. Box 80203, Jeddah, 21589, Saudi Arabia Permanent address: Department of Mathematics, Faculty of Science, Mansoura University, Mansoura, 35516, Egypt Abstract In this paper, the generalized q-Bessel function, which is a generalization of the known q-Bessel functions of kinds 1, 2, 3, and the new q-analogy of the modified Bessel function presented in (Mansour and Al-Shomarani in J. Comput. Anal. Appl. 15(4):655-664, 2013) is introduced. We deduced its generating function, recurrence relations and q-difference equation, which gives us the differential equation of each of the Bessel function and the modified Bessel function when q tends to 1. Finally, the quantum algebra E2 (q) and its representations presented an algebraic derivation for the generating function of the generalized q-Bessel function. MSC: Primary 33D45; 81R50; 22E70 Keywords: q-Bessel functions; generating function; q-difference equation; quantum algebra; irreducible representation 1 Introduction The q-shifted factorials are defined by [] (a; q) = , (a; q)k = k– – aqk , i=o (a , . . . , ar ; q)k = r (aj ; q)k ; k = , , , . . . , j= (a; q)∞ = ∞ – aqi , where a, ai ’s, q ∈ R such that < q < . i= The one-parameter family of q-exponential functions Eq(α) (z) = αn ∞ q n z (q; q)n n= with α ∈ R has been considered in []. Consequently, in the limit when q → , we have limq→ Eq(α) (( – q)z) = ez . Exton [] presented the following q-exponential functions: E(μ, z; q) = ∞ qμn(n–) n= [n]q ! zn , © 2013 Mahmoud; licensee Springer. This is an Open Access article distributed under the terms of the Creative Commons Attribution License (http://creativecommons.org/licenses/by/2.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 where [n]q ! = (q;q)n . (–q)n Page 2 of 11 The relation between these two notations is given by E(λ, z; q) = Eq(λ) q–λ ( – q)z . In Exton’s formula, if we replace z by function: x –q and μ by a, we get the following q-exponential n ∞ q a( ) n x , (q; q)n n= Eq (x, a) = () which satisfies the functional relation [] Eq (x, a) – Eq (qx, a) = xEq qa x, a , which can be rewritten by the formula Dq Eq (x, a) = Eq qa x, a , –q () where the Jackson q-difference operator Dq is defined by [] Dq f (x) = f (x) – f (qx) ( – q)x () and satisfies the product rule Dq f (x)g(x) = f (qx)Dq g(x) + g(x)Dq f (x). There are two important special cases of the function Eq (x, a) eq (x) = ∞ n= xn , (q, q)n |x| < () and Eq (x) = n ∞ q ( ) xn n= (q, q)n . () The q-Bessel functions of kinds , and are defined by [] (qn+ ; q)∞ x n x , , q; – ϕ (q; q)∞ qn+ qn+ x (qn+ ; q)∞ x n – () q; – , Jn (x; q) = ϕ (q; q)∞ qn+ n n+ n+ x (q x ; q) q ∞ q; – , Jn() (x; q) = ϕ (q; q)∞ qn+ Jn() (x; q) = () () () Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 Page 3 of 11 where r ϕs is the basic hypergeometric function [] r ϕs ∞ (a , . . . , ar ; q)k +s–r zk k a , . . . , ar (–)k q (k–) . q; z = (b , . . . , bs ; q)k (q; q)k b , . . . , bs k= () The functions Jn(i) (x; q), i = , , are q-analogues of the Bessel function, and the function Jn() (x; q) is a q-analogue of the modified Bessel function. Rogov [, ] introduced generalized modified q-Bessel functions, similarly to the classical case [], as Ini (x; q) = (qn+ ; q)∞ x n , , . . . , δ ϕ (q; q)∞ qn+ (n+)(–δ) q x q; , where ⎧ ⎪ ⎪ ⎨ for i = , δ = for i = , ⎪ ⎪ ⎩ for i = . Recently, Mansour and et al. [] studied the following q-Bessel function: (x/)n Jn() (x; q) = ϕ (q; q)n (n+) – –q x , q; , qn+ which is a q-analogy of the modified Bessel function. In this paper, we define the generalized q-Bessel function and study some of its properties. Also, in analogy with the ordinary Lie theory [, ], we derive algebraically the generating function of the generalized q-Bessel function. 2 The generalized q-Bessel function and its generating function Definition . The generalized q-Bessel function is defined by Jn (x, a; q) = ak ∞ (x/)n (–)k(a+) q (k+n) (x /)k , (q; q)n (qn+ ; q)k (q; q)k () k= which converges absolutely for all x when a ∈ Z+ and for |x| < if a = . As special cases of Jn (x, a; q), we get Jn() (x; q) = Jn (x, ; q), Jn() (x; q) = Jn (x, ; q), Jn() (x; q) = Jn (x, ; q), Jn() (x; q) = Jn (x, ; q). Lemma . The function Jn (x, a; q) is a q-analogy of each of the Bessel function and the modified Bessel function. Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 Page 4 of 11 Proof ∞ k k ak(k+n) ( – q)n x n x ( – q) (–)k(a+) q lim Jn ( – q)x, a; q = lim q→ q→ (q, q)n (qn+ ; q)k (q; q)k k= ∞ x n (–)k(a+) x k = ()n (n + )k ()k k= k n ∞ (–)k(a+) x x = . (n + k + )(k + ) k= Hence, we get lim Jn ( – q)x, a; q = Jn (x); a = , , , . . . () lim Jn ( – q)x, a; q = In (x); a = , , , . . . , () q→ and q→ where Jn (x) is the Bessel function and In (x) is the modified Bessel function. Lemma . The function Jn (x, a; q) satisfies n ∈ Z. J–n (x, a; q) = (–)n(a+) Jn (x, a; q), () Proof Using the definition (), we get J–n (x, a; q) = ak(k–n) ∞ (–)k(a+) q (q–n+k+ ; q)∞ x k–n (q; q)∞ (q; q)k k=n . For s = k – n, we obtain J–n (x, a; q) = as(s+n) ∞ (–)(s+n)(a+) q (qs+ ; q)∞ x s+n (q; q)∞ (q; q)s+n s= , and using the relations [] = qn+s+ ; q ∞ qs+ ; q n , (q; q)s+n = (q; q)s qs+ ; q n , qs+ ; q ∞ we obtain J–n (x, a; q) = (–) n(a+) as(s+n) ∞ (–)s(a+) q (qn+s+ ; q)∞ x s+n s= = (–)n(a+) Jn (x, a; q). (q; q)∞ (q; q)s Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 Page 5 of 11 Lemma . The function Jn (x, a; q) satisfies the relation Jn (–x, a; q) = (–)n Jn (x, a; q), n ∈ Z, () and hence it is even (or odd) function if the integer n is even (or odd). Now we will deduce the generating function of the generalized q-Bessel function Jn (x, a; q). Theorem The generating function g(x, t, a; q) of the function Jn (x, a; q) is given by g(x, t, a; q) = Eq a a ∞ q xt a (–)a+ q x a an , , Eq = q Jn (x, a; q)t n . t n=–∞ () Proof Let g(x, t, a; q) = Eq a a q xt a (–)a+ q x a , , Eq , t then g(x, t, a; q) = s a r a ∞ ∞ (–)s(a+) q [()+()]+ (s+r) x s+r r= s= (q; q)r (q; q)s t r–s . For s = r – n, we get r–n a r a ∞ ∞ (–)(r–n)(a+) q [()+( )]+ (r–n) x r–n n g(x, t, a; q) = t . (q; q)r (q; q)r–n n=–∞ r= Hence, for n ≤ , the coefficient of t n is given by cn = (–)–n(a+) q an ar ∞ (x/)–n (–)r(a+) q (r–n) x r , (q; q)–n r= (q; q)r (q–n+ ; q)r where (q, q)r–n = (q; q)–n (q–n+ ; q)r for n ≤ . Then cn = (–)–n(a+) q an J–n (x, a; q) = q an Jn (x, a; q). Similarly, for n ≥ . As special cases of gn (x, t, a; q), we obtain gn (x, t, ; q) = Eq xt –x xt –x , Eq , = eq eq , t t () which is a generating function of the q-Bessel function Jn() (x; q) [], xt –qx xt –qx t , Eq , = Eq Eq , gn x, √ , ; q = Eq q t t () Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 Page 6 of 11 which is a generating function of the q-Bessel function Jn() (x; q) [], √ √ qxt qx , , Eq , gn (x, t, ; q) = Eq t () which is a generating function of the q-Bessel function Jn() (x; q) and gn (x, t, ; q) = Eq / q/ xt q x , , Eq , t () which is a generating function of the q-Bessel function Jn() (x; q) []. 3 The q-difference equation of the function Jn (x, a; q) Now the generating function method [] will be used to deduce the q-difference equation of the generalized q-Bessel function. Using equation (), we have Eq a a ∞ q xth a (–)a+ q xh a an q Jn (xh, a; q)t n ; , , Eq = t n=–∞ h ∈ R – {}. () By applying the operator Dq , we get a+ a a (–)a+ q h q xth a (–)a+ q xh a Eq , , Eq ( – q)t t a a a q th q xth a (–)a+ q xh a + Eq , , Eq ( – q) t = ∞ q an Dq Jn (xh, a; q)t n . n=–∞ Using equation (), we obtain a a n+ n+ a an(n–) a+ a q+ (–)a+ q + ( )+ Jn+ q xh, a; q + Jn– q xh, a; q ( – q) ( – q) = q an h Dq Jn (xh, a; q). Hence Dq Jn (xh, a; q) a = a+ a n(a+)+ q h –an (–)a+ q Jn+ q xh, a; q + q Jn– q xh, a; q . ( – q) () Similarly, we can prove the following relation: Dq Jn (xh, a; q) a = a a+ (–an–n+) q h na (–)a+ q Jn+ q xh, a; q + q Jn– q xh, a; q . ( – q) () Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 Page 7 of 11 By using equations () and (), we obtain √ Jn+ ( qxh, a; q) + Jn– (xh, a; q) an –n √ = (–)(a+) q Jn+ (xh, a; q) + q Jn– ( qxh, a; q). (–)a+ q n(a+)+ () But √ Jn– ( qxh, a; q) = = ( √ qxh n– ∞ ) (q; q)∞ q k= ak (–)k(a+) q (k+n–) (qn+k ; q)∞ (q; q)k √ qxh k ak ∞ xh k ( xh )n– (–)k(a+) q (k+n–) (qn+k ; q)∞ k q –+ (q; q)∞ (q; q)k n– k= =q n– Jn– (xh, a; q) – q a(k+)(k+n) ∞ ( xh )n– (–)(k+)(a+) q (q; q)∞ (q; q)k n– k= k+ xh × qn+k+ ; q ∞ an (–)a q xh a n– = q Jn– (xh, a; q) + Jn q xh, a; q . Then an q –n (–)a q xh a √ Jn q xh, a; q . Jn– ( qxh, a; q) – Jn– (xh, a; q) = () Equations () and () give the relation q +n –xh a √ Jn+ ( qxh, a; q) – Jn+ (xh, a; q) = Jn q xh, a; q . () Equations () and () give the relation a(–n) (a+)(n+) a+ q n (–)a+ hq Dq + q δq – Jn (xh, a; q) = Jn+ q xh, a; q , ( – q)x ( – q) () √ where the operator δq is given by δq f (x) = f ( qx). Now consider the following operator: a(–n) q n q δq – , Mn,q = Dq + ( – q)x () then we can rewrite equation () by the formula (a+)(n+) Mn,q Jn (xh, a; q) = (–)a+ hq ( – q) a+ Jn+ q xh, a; q . () Also, equations () and () give the relation –a(+n) (a+)(–n) a+ q –n hq q δq – Jn (xh, a; q) = Jn– q xh, a; q . Dq + ( – q)x ( – q) () Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 Page 8 of 11 If we consider the operator –a(+n) q –n Nn,q = Dq + q δq – , ( – q)x () then we can rewrite equation () by the formula (a+)(–n) a+ hq Jn– q xh, a; q . Nn,q Jn (xh, a; q) = ( – q) () Hence, the q-difference equation of the function Jn (x, a; q) takes the formula a+ Mn–,q Nn,q Jn (xh, a; q) = (–)a+ q h a+ Jn q xh, a; q . ( – q) () If we replace h by – q and consider the limit as q tends to , then we obtain n– d – dx x n (–)a+ d + y(x), y(x) = dx x () or x y (x) + xy – n + (–)a+ x y = . () The differential equation () gives the Bessel function at a = , , , . . . and the modified Bessel function at a = , , , . . . , which proves again that Jn (x, a; q) is a q-analogy of each of them. 4 The recurrence relations of the function Jn (x, a; q) Lemma . Jn (x, a; q) = (a+)(n+) – qn+ Jn+ q–a/ x, a; q + (–)a+ q Jn+ (x, a; q). x () Proof ak ∞ x k (x/)n (–)k(a+) q (k+n) n+ n+ n+k– Jn (x, a; q) = –q +q –q (q; q)n (q; q)k (qn+ ; q)k+ k= = ak a ∞ (x/)n+ (–)k(a+) q (k+n+) (q– x) k – qn+ x (q; q)n+ (q; q)k (qn+ ; q)k k= + qn+ = ∞ n+ (x/) (q; q)n+ k= ak (–)k(a+) q (k+n) x k– (q; q)k– (qn+ ; q)k– – qn+ Jn+ q–a/ x, a; q x + (–) a+ (a+)(n+) q ak ∞ (x/)n+ (–)k(a+) q (k+n+) x k (q; q)n+ (q; q)k (qn+ ; q)k k= (a+)(n+) = – qn+ Jn+ q–a/ x, a; q + (–)a+ q Jn+ (x, a; q). x Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 Page 9 of 11 Similarly, if we write ( – qk + qk – qn+k– ) instead of ( – qn+ + qn+ – qn+k– ), we can prove the following lemma. Lemma . Jn (x, a; q) = –a a(n+) – qn+ Jn+ q x, a; q + (–)a+ q Jn+ (x, a; q). x () Now, if we replace a by a + in the recurrence relation (), we get the recurrence relation (). Then we have the following lemma. Lemma . The two functions Jn (x, a; q) and Jn (x, a + ; q) have the same recurrence relation. Then we have two cases of the recurrence relation. Case (): The function Jn (x, a; q) has the recurrence relation Jn (x, a; q) = – qn+ Jn+ (x, a; q) – qn+ Jn+ (x, a; q); x ∀a = , , , . . . , () which is the recurrence relation of each of Jn() (x; q) and Jn() (x; q). Case (): The function Jn (x, a; q) has the recurrence relation n Jn (x, a; q) = q n x – qn+ – q Jn+ (x, a; q) x + qn+/ Jn+ (x, a; q); ∀a = , , , . . . , () which is the recurrence relation of each of Jn() (x; q) and Jn() (x; q). 5 The quantum algebra approach to Jn (x, a; q) The quantum algebra Eq () is determined by generators H, E+ and E– with the commutation relations [H, E+ ] = E+ , [H, E– ] = –E– , [E– , E+ ] = . () By considering the irreducible representations (ω) of Eq () characterized by ω ∈ C, then the spectrum of the operator H will be the set of integers Z, and the basis vectors fm , m ∈ Z, satisfy E± fm = ωfm± , E+ E– fm = ω fm , Hfm = mfm , () where C = E+ E– is the Casimir operator which commutes with the generators H, E+ and E– . The following differential operators presented a simple realization of (ω) H =z d , dz E+ = ωz, E– = ω z () acting on the space of all linear combinations of the functions zm , z a complex variable, m ∈ Z, with basis vectors fm (z) = zm . Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 Page 10 of 11 In the ordinary Lie theory, matrix elements Tsm of the complex motion group in the representation (ω) are typically defined by the expansions [–] ∞ eαE+ eβE– eτ H fm = Tsm (α, β, τ )fs . () s=–∞ If we replace the mapping ex by the mapping Eq (x, a/) from the Lie algebra to the Lie group with putting τ = in equation (), we can use the model () to find the following q-analog of matrix elements of (ω): Eq (αE+ , a/)Eq (βE– , a/)fm = ∞ Tsm (α, β)fs , () s=–∞ and hence t a r ∞ a ω a m q [()+()] r+t r t m–t+r Eq αωz, Eq β , z = ω αβz . z (q; q)r (q; q)t r,t= Now replace s by m – t + r to get m+r–s a r ∞ ∞ a ω a m q [()+( )] m+r–s r m+r–s s Eq β , z = Eq αωz, ω αβ z z (q; q)r (q; q)m+r–s s=–∞ r= and by equating the coefficient of zs for m ≥ s on both sides, we get Tsm (α, β) = a m–s a ∞ q( ) q r(r+m–s–) r ω αβ , (ωβ)m–s (q; q)m–s (q; q)r (qm–s+ ; q)r r= a = q (m–s) m≥s m–s –a β (–)–(a+) (–)(m–s)(a+) Jm–s q ω (–)a+ αβ, a; q , α (–)a+ αβ > ; m ≥ s s–m –a a (s–m) (a+) α (–) Js–m q ω (–)a+ αβ, a; q , =q β (–)a+ αβ > ; m ≥ s, where J–n (x, a; q) = (–)n(a+) Jn (x, a; q). Similarly, Tsm (α, β) = q a (s–m) s–m –a (a+) α Js–m q ω (–)a+ αβ, a; q , (–) β (–)a+ αβ > ; s ≥ m. The combination between the two cases gives us the following expression: Tsm (α, β) = q (–) a+ a (s–m) (–) (a+) α β s–m –a Js–m q ω (–)a+ αβ, a; q , αβ > , which is valid for all m, s ∈ Z. Then we get the following result. () Mahmoud Advances in Difference Equations 2013, 2013:121 http://www.advancesindifferenceequations.com/content/2013/1/121 Page 11 of 11 Lemma . a ω a Eq β , Eq αωz, z s ∞ a α –a q s (–)(a+) Js q ω (–)a+ αβ, a; q zs , = β s=–∞ () where (–)a+ αβ > . As special cases: Considering () with a = , α = –β = , z = t and ω = x ,√we obtain the relation (). qx Considering () with a = , α = –β = , z = √tq and ω = , we obtain the relation (). Considering () with a = , α = β = , z = t and ω = Considering () with a = , α = β = , z = t and ω = √ qx , we obtain the relation (). q/ x , we obtain the relation (). Competing interests The author declares that he has no competing interests. Author’s contributions The author read and approved the final manuscript. 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