Download Geometry Semester 2 Multiple Choice Final Review Answer Section

Geometry Semester 2 Multiple Choice Final Review
Answer Section
1.
2.
3.
4.
5. The triangles are congruent by SSS.
6. There is not enough information to determine whether the triangles are congruent by SSS or SAS. SAS does
not apply because the congruent angles in the figure are not included angles.
7. The triangles are congruent by SAS.
8. There is not enough information to determine whether the triangles are congruent by SSS or SAS. SAS does
not apply because the congruent angles in the figure are not included angles.
9. The triangles are congruent by AAS.
10. There is not enough information to determine whether the triangles are congruent by ASA or AAS.
11. The triangles are congruent by ASA.
12.
by the Reflexive Property.
13.
because they are vertical angles.
using the SAS Triangle Congruence Theorem.
using the ASA Triangle Congruence
Theorem.
14.
15.
16.
17.
18.
19.
B
D
A
C
Yes. There is enough information to conclude that
by HA.
No.
might not be congruent to
. There is not enough information.
20. Using
and the Base Angle Theorem,
. Using
. Since
and
are supplementary,
measures of the angles in a triangle is
,
.
21.
cm. Using the Base Angle Converse Theorem,
, where
and
. So,
.
and the Base Angle Theorem,
. Since the sum of the
. Solve the perimeter equation
22. Lake Winnie is 80 feet wide. The triangles are congruent by the Hypotenuse-Leg Congruence Theorem and
corresponding parts of congruent triangles are congruent, so the width of Lake Winnie is equal to the length
of the 48 meter leg of the triangle that is displayed below the lake.
23. Eight posts are needed to complete the fence. Using the Base Angle Converse Theorem, I know the length of
side AC is equal to the length of side BC. She will need four more posts for side AC and four more posts for
side BC.
24.
25.
26. The converse of the conditional would be:
If a triangle is obtuse, then the measure of one of its angles is greater than
.
The converse is true.
27. The converse of the conditional would be:
If a triangle is an isosceles triangle, then it has two sides with equal lengths.
The converse is true.
28. The inverse of the conditional would be:
If a polygon is not a triangle, then the sum of its exterior angles is not
.
The inverse is not true.
29. The inverse of the conditional would be:
If a polygon is not a square, then it is not a rhombus.
The inverse is not true.
30. The contrapositive of the conditional would be:
If a quadrilateral is not a parallelogram, then it is not a rectangle.
The contrapositive is true.
31. The contrapositive of the conditional would be:
If the radius of a circle is not 6 inches, then the diameter of the circle is not 12 inches.
The contrapositive is true.
32.
33.
34.
The angle formed by the ramp and the ground is approximately
35.
36.
37.
The angle formed by the string and the ground is approximately
38.
39.
The angle formed by the rope and the dock is approximately 55.15 .
40.
41.
42.
The area of the triangle is approximately 139.9 square centimeters.
43.
The area of the triangle is approximately 10.6 square inches.
44.
45.
46.
47.
48.
49.
50. All rhombi have the properties of a parallelogram, so every rhombus must be a parallelogram. Penny is
correct.
51. No. A rhombus has four congruent sides. If Sally makes the base of her sculpture with the four pieces of
wood she has cut, all four sides of the quadrilateral will not be the same length.
52.
The area of the kite is 75 square inches.
53.
Each of the shorter sides is 14 centimeters.
54. The sum is equal to
:
The sum of the interior angles of the polygon is
55. The sum is equal to
:
The sum of the interior angles of the polygon is
56.
8 sides
.
.
57.
5 sides
58.
The measure of each interior angle is
.
The measure of each interior angle is
.
59.
60.
The regular polygon has 5 sides.
61.
The regular polygon has 18 sides.
62.
63.
64. Interior and exterior angles are supplementary. So subtract
65. Interior and exterior angles are supplementary. So subtract
, the measure of the interior angle, from
, the measure of the interior angle, from
.
.
66.
67.
68.
8 sides
69.
10 sides
70. rhombus
parallelogram
quadrilateral
71. rectangle
parallelogram
quadrilateral
72. kite
quadrilateral
73. quadrilateral
74. False. Parallelograms have two pairs of parallel sides. Trapezoids only have one pair.
75. True
76. False. The diagonals of a rhombus, square, and a kite are perpendicular.
77. False. Both pairs of opposite angles are congruent in a parallelogram.
78. True.
79. False. All parallelograms have supplementary consecutive angles, not quadrilaterals.
80. point A
81.
82.
83.
84. point X
85.
86.
87. Sample answer:
88. Sample answer:
89.
90.
91. The measure of
is
.
92.
93.
94.
95.
96. The measure of arc FI is 120 degrees.
97. The measure of arc RS is 130 degrees.
98. 10
99. 5
100. 12
101.
102.
103.
104.
105.
Fraction of C:
Arc length of
The arc length of
is 3
meters.
106.
Fraction of C:
Arc length of
The arc length of
is
cm.
is
cm.
107.
Fraction of C:
Arc length of
The arc length of
108. Arc length:
mm
Perimeter of shaded region:
109. Arc length:
mm
cm
Perimeter of figure:
110. Arc length:
Perimeter of shaded region:
111.
cm
ft
ft
112.
113. Arc length
114. Total area of the circle
Sector AOB’s fraction of the circle
Area of sector AOB
The area of sector AOB is
.
115. Total area of the circle
Sector POQ’s fraction of the circle
Area of sector POQ
The area of sector POQ is
.
116. Total area of the circle
Sector AOB’s fraction of the circle
Area of sector AOB
Area of
Area of the segment:
The area of the shaded segment is approximately
.
117.
Because arc BCD is a semicircle, its measure is
118.
119.
120.
.
121.
122.
123.
center: ( 2, 2), radius: 5
124. This equation does not represent a circle because
125.
center: (4, 5), radius: 6
126. The radius of circle B is
, or 7. To calculate the circumference of B, substitute 7 for r in the formula for
the circumference of a circle.
A circle with three times the circumference of circle B has circumference 3(14 ), or 42 units. To calculate
its radius, substitute 42 for C in the formula for the circumference of a circle, and then solve for r.
The radius of the circle is 21. So an equation of the circle with the same center as circle B but with a
circumference that is three times that of circle B is
127.
Because the length of line segment AP is 8 units, line segment AP is a radius of circle A; therefore, point P
must lie on circle A.
128.
Because the length of line segment AP is 5 units, line segment AP is a radius of circle A; therefore, point P
must lie on circle A.
129.
130.