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Calculating magnetic momentum of the proton By convention magnetic momentum of a current loop is calculated by: 1) M=i.A Where M is the calculated magnetic momentum of the loop, i is equal to the current in the loop and A is the area enclosed of the loop. An elementary particle like for instance the proton particle, may be regarded as a closed current loop. Because the particle has an electric unit charge, we can write this current to: 2) i=e/t where e is equal to the electric unit charge and t is equal to the spin envelope time of the particle. The enclosed area of this lope is written by: 3) a=.R2x The envelope spin velocity is calculated by the formula: 4) v=c.(re/Rs)2 The spin envelope time there will be: 5) T=2.Rs/(c.(re/Rs)2) Using these results, the magnetic momentum may be written: 6) M=(e.c.re/2).(Rx/Rs)2.(1/Rs) Now we assume that the spin forces around the two axes are balanced by external forces towards the particle surface. For the electric field spin direction we can write: 7) Pressure=(m.v2/Rs ).(1/(2.Rs.ds) For the magnetic field spin direction we have: 8) p=(m.v2/Rx).(1/(2.Rx.s) The pressure p is the same in both cases. Then you get: 9) 2.Rs2=2.Rx2 Then you get: 10) (Rx/Rs)2= Now we can write the particles magnetic momentum: 11) M=(e.c.re/2)..(1/Rs) The particles radius in the electric field spin direction may be calculated by: 12) Rs=re.(m/me)1/3 Where m is equal to the proton particle mass and me is equal to the electron mass. Inserting all known values we get the magnetic momentum of the proton to the formula: 13)Ms=1.85E-26 which is a value in good agreement with measurements.