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Calculating magnetic momentum of the proton
By convention magnetic momentum of a current loop is
calculated by:
Where M is the calculated magnetic momentum of the loop, i
is equal to the current in the loop and A is the area enclosed
of the loop.
An elementary particle like for instance the proton particle,
may be regarded as a closed current loop. Because the
particle has an electric unit charge, we can write this current
where e is equal to the electric unit charge and t is equal to
the spin envelope time of the particle.
The enclosed area of this lope is written by:
3) a=.R2x
The envelope spin velocity is calculated by the formula:
4) v=c.(re/Rs)2
The spin envelope time there will be:
5) T=2.Rs/(c.(re/Rs)2)
Using these results, the magnetic momentum may be
Now we assume that the spin forces around the two axes are
balanced by external forces towards the particle surface. For
the electric field spin direction we can write:
Pressure=(m.v2/Rs ).(1/(2.Rs.ds)
For the magnetic field spin direction we have:
The pressure p is the same in both cases. Then you get:
Then you get:
10) (Rx/Rs)2=
Now we can write the particles magnetic momentum:
11) M=(.(1/Rs)
The particles radius in the electric field spin direction may be
calculated by:
12) Rs=re.(m/me)1/3
Where m is equal to the proton particle mass and me is equal
to the electron mass.
Inserting all known values we get the magnetic momentum of
the proton to the formula:
which is a value in good agreement with measurements.