Download By convention magnetic momentum of a current loop is calculated by

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project

Document related concepts

Tensor operator wikipedia, lookup

Introduction to quantum mechanics wikipedia, lookup

Bell's theorem wikipedia, lookup

Propagator wikipedia, lookup

Renormalization wikipedia, lookup

Identical particles wikipedia, lookup

Standard Model wikipedia, lookup

ATLAS experiment wikipedia, lookup

Lepton wikipedia, lookup

Angular momentum operator wikipedia, lookup

Photon polarization wikipedia, lookup

Electron scattering wikipedia, lookup

Magnetic monopole wikipedia, lookup

Symmetry in quantum mechanics wikipedia, lookup

Aharonov–Bohm effect wikipedia, lookup

Compact Muon Solenoid wikipedia, lookup

Elementary particle wikipedia, lookup

Spin (physics) wikipedia, lookup

Theoretical and experimental justification for the Schrödinger equation wikipedia, lookup

Relativistic quantum mechanics wikipedia, lookup

Transcript
Calculating magnetic momentum of the proton
By convention magnetic momentum of a current loop is
calculated by:
1)
M=i.A
Where M is the calculated magnetic momentum of the loop, i
is equal to the current in the loop and A is the area enclosed
of the loop.
An elementary particle like for instance the proton particle,
may be regarded as a closed current loop. Because the
particle has an electric unit charge, we can write this current
to:
2)
i=e/t
where e is equal to the electric unit charge and t is equal to
the spin envelope time of the particle.
The enclosed area of this lope is written by:
3) a=.R2x
The envelope spin velocity is calculated by the formula:
4) v=c.(re/Rs)2
The spin envelope time there will be:
5) T=2.Rs/(c.(re/Rs)2)
Using these results, the magnetic momentum may be
written:
6)
M=(e.c.re/2).(Rx/Rs)2.(1/Rs)
Now we assume that the spin forces around the two axes are
balanced by external forces towards the particle surface. For
the electric field spin direction we can write:
7)
Pressure=(m.v2/Rs ).(1/(2.Rs.ds)
For the magnetic field spin direction we have:
8)
p=(m.v2/Rx).(1/(2.Rx.s)
The pressure p is the same in both cases. Then you get:
9)
2.Rs2=2.Rx2
Then you get:
10) (Rx/Rs)2=
Now we can write the particles magnetic momentum:
11) M=(e.c.re/2)..(1/Rs)
The particles radius in the electric field spin direction may be
calculated by:
12) Rs=re.(m/me)1/3
Where m is equal to the proton particle mass and me is equal
to the electron mass.
Inserting all known values we get the magnetic momentum of
the proton to the formula:
13)Ms=1.85E-26
which is a value in good agreement with measurements.