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Chapters 1 & 2 Geometry Honors – Important Postulates, Definitions, and Theorems Name ________________________________________________ Date ____________________ Commonly Used Postulates in Proof (See page 926 a complete list) 1. Segment Addition Postulate: B is between A and C iff AB + BC = AC. A ( also AB = AC – BC & BC = AC – AB ) B C 2. Angle Addition Postulate: B is in the interior of <ACD iff m<ACB + m<BCD = m<ACD. ( also m<ACB = m<ACD – m<BCD and A m<BCD = m<ACD – m<ACB ) C 3. Through any two points there exists exactly one line. B D 4. A line contains at least two points. 5. If two lines intersect, then their intersection is exactly one point. 6. Through any three noncollinear points there exists exactly one plane. 7. A plane contains at least three noncollinear points. 8. If two points lie in a plane, then the line containing them lies in the plane. 9. If two planes intersect, then their intersection is a line. 10. Linear Pair Postulate: If two angles form a linear pair, then they are supplementary. Definitions 1. Point M is the midpoint of AB iff M is between A and B such that AM = MB or AM MB A M 2. ⃗⃗⃗⃗⃗ bisects <ACD iff m<ACB = m<BCD or <ACB <BCD B A C B D 3. A point, line, plane, ray, or segment bisects a segment iff it intersects the segment at its midpoint. 4. Two lines are perpendicular iff they intersect to form a right angle. 5. An angle is a right angle iff its measure is 90. 6. An angle is an acute angle iff its measure is between 0 and 90. 7. An angle is an obtuse angle iff its measure is between 90 and 180. 8. Definition of congruent angles: Two angles are congruent iff their measures are equal. 9. Definition of congruent segments: Two segments are congruent iff their measures are equal. Geometry Theorems – Chapter 2 – the following theorems have been, or will be, covered and proved in class or homework. For each theorem, write the “given”, the “prove”, the diagram, and a 2-column proof. 1. Vertical Angle Theorem (vertical angles are ) Prove: <1 <3 & <2 <4 1. 2. 3. 4. 5. 6. Statements <1 <3; <2 <4 <1 & <2 form a linear pair <2 & <3 form a linear pair <3 & <4 form a linear pair <1 & <2 are supplementary <2 & <3 are supplementary <3 & <4 are supplementary m<1 + m<2 = 180 m<2 + m<3 = 180 m<3 + m<4 = 180 m<1 + m<2 = m<2 + m<3 m<2 + m<3 = m<3 + m<4 m<1 = m<3 m<2 = m<4 Reasons 1. Given 2. Def. Linear Pair 2 3. Linear Pair Postulate 4. Def. Supplementary 5. Substitution (=) 6. Subtraction (=) Q.E.D. 2. Midpoint Theorem Given: B is the midpoint of ̅̅̅̅ Prove: AC = 2AB; AC = 2BC; AB = ½ AC; BC = ½ AC 1. 2. 3. 4. 5. 6. 7. Statements ̅̅̅̅ B is the midpoint of 𝐴𝐶 AB = BC AB + BC = AC AB + AB = AC 2AB = AC 2BC = AC AB= ½ AC; BC = ½ AC Reasons 1. Given 2. Def. Midpoint 3. Segment Addition Postulate 4. Substitution (=) 5. Substitution (=) 6. Substitution (=) 7. Division (=) Q.E.D. 3. Angle Bisector Theorem Given: ⃗⃗⃗⃗⃗⃗ bisects <ABC Prove: m<ABC = 2m<1; m<ABC = 2m<2 m<1 = ½ m<ABC; m<2 = ½ m<ABC 1. 2. 3. 4. 5. 6. 7. Statements Reasons ⃗⃗⃗⃗⃗⃗ 𝐵𝐷 bisects <ABC 1. Given m<1 = m<2 2. Def. Bisect m<1 + m<2 = m<ABC 3. Angle Addition Postulate m<1 + m<1 = m<ABC 4. Substitution (=) 2m<1 = m<ABC 5. Substitution (=) 2m<2 = m<ABC 6. Substitution (=) m<1 = ½ m<ABC; m<2 = ½ m<ABC 7. Division (=) Q.E.D. 1 4 3 4. All right angles congruent Given: <A and <B are right angles Prove: <A <B 1. 2. 3. 4. Statements <A and <B are right angles m<A = 90; m<B = 90 m<A = m<B <A <B Reasons 1. Given 2. Def. Right Angle 3. Substitution (=) 4. Def. Angles Q.E.D. 5. Midpoints of congruent segments make congruent segments Given: ̅̅̅̅ ̅̅̅̅ ; B is midpoint of ̅̅̅̅ ; E is midpoint of ̅̅̅̅ Prove: ̅̅̅̅ ̅̅̅̅ ̅̅̅̅ ̅̅̅̅ 1. 2. 3. 4. 5. 6. 7. Statements ̅̅̅̅ ̅̅̅̅ ; 𝐴𝐶 𝐷𝐹 B is midpoint of ̅̅̅̅ 𝐴𝐶 ; ̅̅̅̅ E is midpoint of 𝐷𝐹 AC = DF AB = BC; DE = EF AC = 2BC; DF = 2DE 2BC = 2DE BC = DE AB = BC = DE = EF Reasons 1. Given 2. 3. 4. 5. 6. 7. Def. Segments Def. Midpoint Midpoint Theorem Substitution (=) Division (=) Transitive (=) Q.E.D. 6. Bisectors of congruent angles make congruent angles Given: <ABC <DEF; ⃗⃗⃗⃗⃗ bisects <ABC; ⃗⃗⃗⃗⃗⃗ bisects <DEF Prove: <ABG <GBC <DEH <HEF 1. 2. 3. 4. 5. 6. 7. Statements <ABC <DEF ⃗⃗⃗⃗⃗ 𝐵𝐺 bisects <ABC ⃗⃗⃗⃗⃗⃗ 𝐸𝐻 bisects <DEF m<ABC = m<DEF m<1 = m<2; m<3 = m<4 m<ABC = 2m<2; m<DEF = 2m<3 2m<2 = 2m<3 m<2 = m<3 m<1 = m<2 = m<3 = m<4 Reasons 1. Given 2. 3. 4. 5. 6. 7. Q.E.D. Def. Angles Def. Bisector Bisector Theorem Substitution (=) Division (=) Transitive (=) 7. Overlapping Segments Theorem Case 1 Given: ̅̅̅̅ ̅̅̅̅ Prove: ̅̅̅̅ ̅̅̅̅ Case 2 Given: ̅̅̅̅ Prove: ̅̅̅̅ ̅̅̅̅ ̅̅̅̅ Case 1 1. 2. 3. 4. 5. 6. Case 2 Statements ̅̅̅̅ 𝐴𝐵 ̅̅̅̅ 𝐶𝐷 AB = CD AB + BC = CD + BC AB + BC = AC CD + BC = BD AC = BD ̅̅̅̅ 𝐴𝐶 ̅̅̅̅ 𝐵𝐷 Reasons 1. Given 2. Def. Segments 3. Addition (=) 4. Segment Addition Postulate 5. Substitution (=) 6. Def. Segments Statements ̅̅̅̅ 𝐴𝐶 ̅̅̅̅ 𝐵𝐷 AC = BD AB + BC = AC CD + BC = BD AB + BC = CD + BC AB = CD ̅̅̅̅ 𝐴𝐵 ̅̅̅̅ 𝐶𝐷 1. 2. 3. 4. 5. 6. Reasons 1. Given 2. Def. Segments 3. Segment Addition Postulate 4. Substitution (=) 5. Subtraction (=) 6. Def. Segments Q.E.D. Q.E.D. 8. Overlapping Angles Theorem Case 1 Given: <1 <3 Prove: <ABE <DBC Case 2 1 Given: <ABE <DBC Prove: <1 <3 2 Case 1 1. 2. 3. 4. 5. 6. 3 Case 2 Statements Reasons <1 <3 1. Given m<1 = m<3 2. Def. Angles m<1 + m<2 = m<3 + m<2 3. Addition (=) m<1 + m<2 = m<ABE 4. Angle Addition m<3 + m<2 = m<DBC Postulate m<ABE = m<DBC 5. Substitution (=) <ABC <DBC 6. Def. Angles Q.E.D. 1. 2. 3. 4. 5. 6. Statements Reasons <ABE <DBC 1. Given m<ABE = m<DBC 2. Def. Angles m<1 + m<2 = m<ABE 3. Angle Addition m<3 + m<2 = m<DBC Postulate m<1 + m<2 = m<3 + m<2 4. Substitution (=) m<1 = m<3 5. Subtraction (=) <1 <3 6. Def. Angles Q.E.D. 9. Supplements of congruent (or the same) angles are congruent Given: <1 <2; <1 and <3 are supplementary; <2 and <4 are supplementary Prove: <3 <4 1. 2. 3. 4. 5. 6. Statements <1 <2 <1 & <3 are supplementary <2 & <4 are supplementary m<1 = m<2 m<1 + m<3 = 180 m<2 + m<4 = 180 m<1 + m<3 = m<2 + m<4 m<3 = m<4 <3 <4 Reasons 1. Given 2. Def. Angles 3. Def. Supplementary 4. Substitution (=) 5. Subtraction (=) [4 – 2] 6. Def. Angles Q.E.D. 10. Complements of congruent (or the same) angles are congruent Given: <1 <2; <1 and <3 are complementary; <2 and <4 are complementary Prove: <3 <4 1. 2. 3. 4. 5. 6. Statements <1 <2 <1 & <3 are complementary <2 & <4 are complementary m<1 = m<2 m<1 + m<3 = 90 m<2 + m<4 = 90 m<1 + m<3 = m<2 + m<4 m<3 = m<4 <3 <4 Reasons 1. Given 2. Def. Angles 3. Def. Complementary 4. Substitution (=) 5. Subtraction (=) [4 – 2] 6. Def. Angles Q.E.D. 11. If <1 and <2 are complementary and <2 <3, then <1 and <3 are complementary (Complementary Substitution). Given: < 1 and <2 are complementary; <2 <3 Prove: <1 and <3 are complementary 1. 2. 3. 4. 5. Statements Reasons <1 & <3 are complementary ; <2 <3 1. Given m<2 = m<3 2. Def. Angles m<1 + m<3 = 90 3. Def. Complementary m<1 + m<2 = 90 4. Substitution (=) <1 & <2 are complementary 5. Def. Angles Q.E.D. 12. If <1 and <2 are supplementary and <2 <3, then <1 and <3 are supplementary. (Supplementary Substitution) Given: < 1 and <2 are supplementary; <2 <3 Prove: <1 and <3 are supplementary 1. 2. 3. 4. 5. Statements Reasons <1 & <3 are supplementary ; <2 <3 1. Given m<2 = m<3 2. Def. Angles m<1 + m<3 = 90 3. Def. Supplementary m<1 + m<2 = 90 4. Substitution (=) <1 & <2 are complementary 5. Def. Angles Q.E.D. 13. lines intersect to form four right angles Given: line a line b Prove: <1, <2, <3, & <4 are right Statements 1. a b 2. <1 is right 3. <1 & 2 form a linear pair 4. <1 & <2 are supplementary 5. m<1 + m<2 = 180 6. m<1 = 90 7. 90 + m<2 = 180 8. m<2 = 90 9. m<2 = m<4; m<1 = m<3 10. m<4 = 90; m<3 = 90 11. <1, <2, <3, & <4 are right Reasons 1. Given 2. Def. 3. Def. Supplementary 4. Linear Pair Postulate 5. Def. Supplementary 6. Def. Right Angle 7. Substitution (=) 8. Subtraction (=) 9. Vertical Angle Theorem 10. Substitution (=) 11. Def. Right Angle Q.E.D. b 1 2 4 3 a 14. If the non-shared sides of a pair of adjacent angles are , then the adjacent angles are complementary. ⃗⃗⃗⃗⃗ Given: ⃗⃗⃗⃗⃗ Prove: <1 and <2 are complementary B D 1. 2. 3. 4. 5. 6. Statements ⃗⃗⃗⃗⃗ ⃗⃗⃗⃗⃗ 𝐴𝐵 𝐴𝐶 <BAC is right m<BAC = 90 m<BAC = m<1 + m<2 90 = m<1 + m<2 <1 & <2 are complementary Reasons 1. Given 2. Def. 3. Def. Right Angle 4. Angle Addition Postulate 5. Substitution (=) 6. Def. Complementary A 1 2 C Q.E.D. 14.5 If a pair of adjacent angles are complementary, then their non-shared sides are (same diagram) Given: <1 and <2 are complementary ⃗⃗⃗⃗⃗ Prove: ⃗⃗⃗⃗⃗ 1. 2. 3. 4. 5. 6. Statements <1 & <2 are complementary m<1 + m<2 = 90 m<BAC = m<1 + m<2 m<BAC = 90 <BAC is right ⃗⃗⃗⃗⃗ ⃗⃗⃗⃗⃗ 𝐴𝐵 𝐴𝐶 Q.E.D. Reasons 1. Given 2. Def. Complementary 3. Angle Addition Postulate 4. Substitution (=) 5. Def. Right Angle 6. Def. 15. “POW” = Parts of Whole Theorem (Segments) 1. 2. 3. 4. 5. 6. (Angles) ̅̅̅̅ Given: 𝐴𝐵 ̅̅̅̅ ̅̅̅̅ 𝐷𝐸 &𝐵𝐶 ̅̅̅̅ Prove: 𝐴𝐶 ̅̅̅̅ 𝐷𝐹 Statements ̅̅̅̅ 𝐷𝐸 ̅̅̅̅ 𝐸𝐹 ̅̅̅̅ &𝐵𝐶 ̅̅̅̅ 𝐴𝐵 AB = DE; BC = EF AB + BC = DE + EF AB + BC = AC; DE + EF = DF AC = DF ̅̅̅̅ 𝐷𝐹 ̅̅̅̅ 𝐴𝐶 Q.E.D. Reasons 1. Given 2. Def. Segments 3. Addition (=) 4. Segment Addition Postulate 5. Substitution (=) 6. Def. Segments Given: <1 <3 & <2 <4 Prove: <GJI <KMN 3 1 4 2 1. 2. 3. 4. 5. 6. Statements <1 <3; <2 <4 m<1 = m<3; m<2 = m<4 m<1 + m<2 = m<3 + m<4 m<1 + m<2 = m<GJI; m<3 + m<4 = m<KMN m<GJI = m<KMN <GJI <KMN Q.E.D. Reasons 1. Given 2. Def. Angles 3. Addition (=) 4. Angle Addition Postulate 5. Substitution (=) 6. Def. Angless ̅̅̅̅ 𝐸𝐹 16. “Con – POW” = Converse Parts of Whole Theorem (Segments) 1. 2. 3. 4. 5. 6. Given: ̅̅̅̅ 𝐴𝐶 ̅̅̅̅ ̅̅̅̅ 𝐷𝐹 & 𝐵𝐶 Prove: ̅̅̅̅ 𝐴𝐵 ̅̅̅̅ 𝐷𝐸 ̅̅̅̅ 𝐸𝐹 Statements Reasons ̅̅̅̅ ̅̅̅̅ & ̅̅̅̅ 𝐴𝐶 𝐷𝐹 𝐵𝐶 ̅̅̅̅ 𝐸𝐹 1. Given AC = DF; BC = EF 2. Def. Segments AB + BC = AC; DE + EF = DF 3. Segment Addition Postulate AB + BC = DE + EF 4. Substitution (=) AC = DF 5. Subtraction (=) ̅̅̅̅ 𝐷𝐹 ̅̅̅̅ 𝐴𝐶 6. Def. Segments Q.E.D. (Angles) Given: <GJI <KMN & <2 <4 Prove: <1 <3 3 1 4 2 1. 2. 3. 4. 5. 6. Statements <GJI <KMN; <2 <4 m<GJI = m<KMN; m<2 = m<4 m<GJI = m<1 + m<2; m<KMN = m<3 + m<4 m<1 + m<2 = m<3 + m<4 m<1 = m<3 <1 <3 Q.E.D. Reasons 1. Given 2. Def. Angles 3. Angle Addition Postulate 4. Substitution (=) 5. Subtraction (=) 6. Def. Angles