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Example 3-2 At What Angle Is Your Heart? Vertical In your heart, pacemaker cells generate electrical signals that trigger a contraction of the heart as the signals spread from the top of the heart to the bottom. The direction in which these signals travel is called the electrical axis of the heart, which reflects the angle at which the heart is positioned in the chest cavity. The direction of a person’s electrical axis is found using a technique called electrocardiography. In a simplified version of electrocardiography, electrodes are placed on the person’s left wrist, right wrist, and right ankle.The electrical signal between the two wrist electrodes tells (b) us the horizontal, right-to-left component of (a) the heart’s electrical activity. The signal beHorizontal tween the right wrist and right ankle (which 1.00 mV component is recorded simultaneously with the signal between the wrists) gives us the vertical, top-to-bottom component. The vector found Electrode on Vertical Electrode on 1.40 mV by combining these horizontal and vertical component right wrist left wrist components points in the direction of the heart’s electrical axis (Figure 3-12a). The graphs in Figure 3-12b show 0s 1.25 s sample recordings of the electrical signal Electrode on versus time for these two pairs of electrodes. right ankle These graphs are called electrocardiograms, abbreviated ECG or EKG (after their Horizontal German name Elektrokardiogramm). In this particular example, the maximum ECG signal between the wrists is 1.00 millivolt (mV) and the maximum ECG signal Figure 3-12 Electrocardiography between the right wrist and right ankle is and the electrical axis of the 1.40 mV. At what angle u does the electrical heart (a) Locating the electrical signal propagate across the heart? axis. (b) Horizontal and vertical electrocardiograms. Set Up Finding vector direction from vector components: tan u = Solve The angle u is measured from the positive x axis toward the positive y axis, so we can safely use Equation 3-2b. Using your calculator, you’ll find that tan21 1.40 = 54.5°. We saw in Example 3-1 that a second solution is 180° plus the result from your calculator, or 180° + 54.5°, or 234.5°. However, the figure above shows that u is between 0 and 90°, so the correct answer is 54.5°. Reflect tan u = = Ay Ax (3-2b) 1.00 mV θ 1.40 mV Our goal is to find the angle u shown in the figure, which is the direction of the heart’s electrical axis measured relative to the horizontal. We choose the x axis to be horizontal and choose the y axis to be vertically downward. (We can choose the axes to be whatever we want, provided they’re mutually perpendicular.) The sketch shows the electrical axis as a green vector; it has an x component of 1.00 mV (shown in red) and a y component of 1.40 mV (shown in purple). As in Example 3-1, we’ll use Equation 3-2b to find this angle. electrical axis y component x component 1.40 mV = 1.40 1.00 mV u = tan21 1.40 = 54.5° or 234.5° Correct answer: u = 54.5° If the horizontal and vertical signals were equally strong, the electrical axis would be tilted at an angle of 45° from the horizontal. In this example the vertical component is somewhat larger than the horizontal component, so the angle is a bit more than 45°. Normal clinical values are between 230° (that is, pointing 30° above the horizontal) and +90° (pointing straight down), so our result is reasonable.