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HW #3 2004200456 Lim Myeong Jun Resistive sensor Capacitive sensor Inductive sensor LVDT Problem solution Piezoelectric sensor Electromagnetic spectrum Radiation thermometer ∵ ρ : Specific resistance 1. 2. 3. 4. Strain gage : Changes in L & ρ Force sensing resistor : Changes in A Thermister : Changes in temperature Potentiometer : Changes in Length F R Ceramic R NTC thermister (Negative temperature coefficient) PTC thermister (Positive temperature coefficient) A) R + E [v ] Rs B) - Vout Rs Vo, Vs, F, T : Non linear R E [v ] + C ) Bridge circuit D ) Linearization Rs Rp Rp Rs R Linear range Capacitive sensor x εR A Inductive sensor 1.Self Inductance 2.Mutual Inductance 3.Difference Inductance Most capacitive sensor is based on changes in x. LVDT(Linear Variable Differential Transformer) a c x=D x= δ d x=0 x=-δ b x=-D Primary coil e f Magnetic core + Vo - Mutual Inductance Sensor Line is Vs and dot is Vo at magnetic core When core is x=0 When core is x=+δ When core is x=- δ Vertical displacement Given by Vs(t) = sin(2π*1000t) [V] (f = 1000Hz, T = 1ms) 180º Phase change Method 1: Rectifier + LPF Full wave rectifier x=D x=0 x=-D D=20mm, 2D=40mm LPF V(t) t Method 2: Phase-Sensitive demodulation x(t)·Vo²(t) Vo(t) LPF(Low Pass Filter) x(t) = sin(2π· 1000t) V(t) t V(t) In phase-sensitive demodulation Vo(t) Vm(t) x(t) = sin(2π· 1000t) LPF(Low Pass Filter) V(t) formula x q : Charge , x : Deflection Fig. piezoelectric sensor That means piezoelectric sensor has no DC response. 1) i=0 i(t) + IA R i=0 Vs(t) = R*i(t) Vo(t) R 2) C i(t), Current flow - 0V IA Vo(t) + Change Amplifier |H| k/c fc = 1/2πRC f If you plan to use the piezoelectric sensor, for measuring pulse, the lowest frequency of pulse, signal is assumed to be 0.1Hz