Download Chapter 6 - Geneva Area City Schools

Chapter 6
The Standard Deviation
as a Ruler and the
Normal Model
Copyright © 2010, 2007, 2004 Pearson Education, Inc.
The Standard Deviation as a Ruler
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The trick in comparing very different-looking
values is to use standard deviations as our rulers.
The standard deviation tells us how the whole
collection of values varies, so it’s a natural ruler
for comparing an individual to a group.
As the most common measure of variation, the
standard deviation plays a crucial role in how we
look at data.
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Slide 6 - 3
Standardizing with z-scores
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y  y

z
s
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Slide 6 - 4
Standardizing with z-scores (cont.)
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Standardized values have no units.
z-scores measure the distance of each data
value from the mean in standard deviations.
A negative z-score tells us that the data value is
below the mean, while a positive z-score tells us
that the data value is above the mean.
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Slide 6 - 5
Benefits of Standardizing
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Standardized values have been converted from
their original units to the standard statistical unit
of standard deviations from the mean.
Thus, we can compare values that are measured
on different scales, with different units, or from
different populations.
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Slide 6 - 6
Examples (p.130 #11)
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A town’s January high temperatures average
36°F with a standard deviation of 10°, while in
July the mean high temperature is 74° and the
standard deviation is 8°. In which month is it
more unusual to have a day with a high
temperature of 55°? Explain.
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Slide 6 - 7
Example (p. 130 #18)
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John Beale of Stanford, CA, recorded the speeds
of cars driving past his house, where the speed
limit read 20 mph. The mean reading was 23.84
mph, with a standard deviation of 3.56 mph.
 a) How many standard deviations from the
mean would a car going under the speed limit
be?
 b) Which would be more unusual, a car
traveling 34 mph or one going 10 mph?
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Slide 6 - 8
Example 1
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Your statistics teacher has announced that the
lower of your two tests will be dropped. You got a
90 on test 1 and an 80 on test 2. You’re all set to
drop the 80 until she announces that she grades
“on a curve.” She standardized the scores in
order to decide which is the lower one. If the
mean on the first test was 88 with a standard
deviation of 4 and the mean on the second test
was 75 with a standard deviation of 5, which test
will be dropped and why? Does this seem “fair”?
Explain why or why not.
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Slide 6 - 9
Homework
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Homework: p. 129 #7,15,17
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Slide 6 - 10
Classwork
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Z-score WKST
Rd p. 107-113
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Slide 6 - 11
Shifting Data
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(pg. 108) The following histograms show a shift from men’s actual weights
to kilograms above recommended weight:
74 kg (the recommended healthy weight) was subtracted from each data
value in the first histogram.
From the second histogram we can see that the average weight in kg
above the recommended weight is about 8.36 kg. 82.36 (mean actual
weight) – 74 = 8.36
What can we say about the shape, center, and spread of the two
histograms?
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Slide 6 - 12
Shifting Data (cont.)
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Shifting data:
 Adding (or subtracting) a constant amount to
each value just adds (or subtracts) the same
constant to (from) the mean. This is true for the
median and other measures of position too.
 In general, adding a constant to every data
value adds the same constant to measures of
center and percentiles, but leaves measures of
spread unchanged.
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Slide 6 - 13
Rescaling Data
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The men’s weight data set measured weights in kilograms. If we want to
think about these weights in pounds, we would rescale the data:
1kg ≈ 2.2 lbs so we multiply the values in the first histogram by 2.2 to get
the values in the second histogram.
What can we say about the shape, center, and spread?
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Slide 6 - 14
Rescaling Data (cont.)
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Rescaling data:
 When we divide or multiply all the data values
by any constant value, all measures of position
(such as the mean, median and percentiles)
and measures of spread (such as the range,
IQR, and standard deviation) are divided and
multiplied by that same constant value.
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Slide 6 - 15
Back to z-scores
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Standardizing data into z-scores shifts the data by
subtracting the mean and rescales the values by
dividing by their standard deviation.
 Standardizing into z-scores does not change the
shape of the distribution.
 Standardizing into z-scores changes the center by
making the mean 0.
 Standardizing into z-scores changes the spread by
making the standard deviation 1.
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So a z-score of 1.7 means the data value is 1.7 standard
deviations above the mean.
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Slide 6 - 16
When Is a z-score BIG?
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A z-score gives us an indication of how unusual a
value is because it tells us how far it is from the
mean.
A data value that sits right at the mean, has a zscore equal to 0.
A z-score of 1 means the data value is 1 standard
deviation above the mean.
A z-score of –1 means the data value is 1
standard deviation below the mean.
Copyright © 2010, 2007, 2004 Pearson Education, Inc.
Slide 6 - 17
When Is a z-score BIG?
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How far from 0 does a z-score have to be to be
interesting or unusual?
There is no universal standard, but the larger a zscore is (negative or positive), the more unusual
it is.
Remember that a negative z-score tells us that
the data value is below the mean, while a positive
z-score tells us that the data value is above the
mean.
Copyright © 2010, 2007, 2004 Pearson Education, Inc.
Slide 6 - 18
When Is a z-score Big? (cont.)
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There is no universal standard for z-scores, but
there is a model that shows up over and over in
Statistics.
This model is called the Normal model (You may
have heard of “bell-shaped curves.”).
Normal models are appropriate for distributions
whose shapes are unimodal and roughly
symmetric.
These distributions provide a measure of how
extreme a z-score is.
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Slide 6 - 19
When Is a z-score Big? (cont.)
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There is a Normal model for every possible
combination of mean and standard deviation.
 We write N(μ,σ) to represent a Normal model
with a mean of μ and a standard deviation of σ.
We use Greek letters because this mean and
standard deviation are not numerical summaries
of the data. They are part of the model. They
don’t come from the data. They are numbers that
we choose to help specify the model.
Such numbers are called parameters of the
model.
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Slide 6 - 20
When Is a z-score Big? (cont.)
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z
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y

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When Is a z-score Big? (cont.)
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Once we have standardized (shifted the data by
subtracting the mean and rescaled the values by
dividing by their standard deviation), we need only
one model:
 The N(0,1) model is called the standard Normal
model (or the standard Normal distribution).
Be careful—don’t use a Normal model for just any
data set, since standardizing does not change the
shape of the distribution.
 If the distribution is not unimodal and symmetric to
begin with, standardizing will not magically make a
set of data Normal.
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Slide 6 - 22
When Is a z-score Big? (cont.)
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When we use the Normal model, we are
assuming the distribution is Normal.
We cannot check this assumption in practice, so
we check the following condition:
 Nearly Normal Condition: The shape of the
data’s distribution is unimodal and symmetric.
 This condition can be checked with a
histogram or a Normal probability plot (to be
explained later).
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Slide 6 - 23
The 68-95-99.7 Rule
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Normal models give us an idea of how extreme a
value is by telling us how likely it is to find one
that far from the mean.
We can find these numbers precisely, but until
then we will use a simple rule that tells us a lot
about the Normal model…
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Slide 6 - 24
The 68-95-99.7 Rule (cont.)
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It turns out that in a Normal model:
 about 68% of the values fall within one standard deviation
of the mean;
 about 95% of the values fall within two standard deviations
of the mean; and,
 about 99.7% (almost all!) of the values fall within three
standard deviations of the mean.
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Slide 6 - 25
The 68-95-99.7 Rule (cont.)
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To be more specific:
0.15% 2.35% 13.5%
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34%
34%
13.5% 2.35% 0.15%
Slide 6 - 26
Example (p. 130 #20)
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Recall that the average speed of a car driving on
a street in Stanford, CA was 23.84 mph, with a
standard deviation of 3.56 mph. To see how
many cars are speeding, John subtracts 20 mph
from all speeds.
 a) What is the mean speed now? What is the
new standard deviation?
 b) His friend in Berlin wants to study the
speeds, so John converts all the original milesper-hour readings to kilometers per hour by
multiplying all speeds by 1.609 (km/mile). What
is the mean now? What is the new standard
deviation?
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Slide 6 - 27
Example (p. 130 #22)
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Suppose police set up radar surveillance on the
Stanford street described in Exercise 18 and 20.
They handed out a large number of tickets to
speeders going a mean of 28 mph, with a
standard deviation of 2.4 mph, a maximum of 33
mph, and an IQR of 3.2 mph. Local law
prescribes fines of $100, plus $10 per mile per
hour over the 20 mph speed limit. For example, a
driver convicted of going 25 mph would be fined
100 + 10(5) = $150. Find the mean, maximum,
standard deviation, and IQR of all the potential
fines.
Slide 6 - 28
Copyright © 2010, 2007, 2004 Pearson Education, Inc.
Example (p. 131 #26)
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Some IQ tests are standardized to a Normal model, with a
mean of 100 and a standard deviation of 16.
 a) Draw the model for these IQ scores. Clearly label it,
showing what the 68-95-99.7 Rule predicts.
 b) In what interval would you expect the central 95% of
IQ scores to be found?
 c) About what percent of people should have IQ scores
above 116?
 d) About what percent of people should have IQ scores
between 68 and 84?
 e) About what percent of people should have IQ scores
above 132?
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Slide 6 - 29
Example (p. 131 #28)
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Exercise 26 proposes modeling IQ scores with
N(100, 16). What IQ would you consider to be
unusually high? Explain.
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Slide 6 - 30
Homework
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Read p. 114-end
Chapter Homework: p. 129 #3
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Slide 6 - 31
The First Three Rules for Working with
Normal Models
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Make a picture.
Make a picture.
Make a picture.
And, when we have data, make a histogram to
check the Nearly Normal Condition to make sure
we can use the Normal model to model the
distribution.
 Is the distribution unimodal and symmetric?
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Slide 6 - 32
Finding Normal Percentiles by Hand
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When a data value doesn’t fall exactly 1, 2, or 3
standard deviations from the mean, we can look it
up in a table of Normal percentiles.
Table Z in Appendix D provides us with normal
percentiles, but many calculators and statistics
computer packages provide these as well.
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Slide 6 - 33
Finding Normal Percentiles by Hand (cont.)
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Table Z is the standard Normal table (pg. A-74 & A-75). We
have to convert our data to z-scores before using the table.
The figure shows us how to find the area to the left when
we have a z-score of 1.80:
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Slide 6 - 34
Finding Normal Percentiles Using Your Calculator
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Slide 6 - 35
Finding Normal Percentiles Using Your Calculator
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If we wanted to find the percentage of data points that fall
within the shaded area on the calculator:
nd  VARS (DIST)  normalcdf( left cut point, right cut
 2
point)
 normalcdf(-0.5,1) = 0.5328072082
So about 53.3% of a Normal model lies between half a
standard deviation below the mean and one standard
deviation above the mean.
Copyright © 2010, 2007, 2004 Pearson Education, Inc.
Slide 6 - 36
Example (p. 132 #38)
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Recall N(100,16), the Normal model for IQ
scores, what percent of people’s IQs would you
expect to be
 a) over 80?
 b) under 90?
 c) between 112 and 132?
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Slide 6 - 37
From Percentiles to Scores: z in Reverse –
Using the table
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Sometimes we start with areas and need to find
the corresponding z-score or even the original
data value.
Example: What z-score represents the first
quartile in a Normal model?
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Slide 6 - 38
From Percentiles to Scores: z in Reverse
(cont.)
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Look in Table Z for an area of 0.2500.
The exact area is not there, but 0.2514 is pretty
close.
This figure is associated with z = –0.67, so the
first quartile is 0.67 standard deviations below the
mean.
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Slide 6 - 39
From Percentiles to Scores: z in Reverse – Using
the Calculator
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What z-score represents the first quartile in a Normal
model?
nd  VARS (DIST)  invnormal(percentile)
 2
 invnormal (.25) = -0.6744897495
So the cut point for the leftmost 25% of a Normal model is
approximately z = -0.674.
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Slide 6 - 40
Example (p. 132 #40)
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Based on the model N(100, 16), what are the
cutoff bounds for
 a) the highest 5% of all IQs?
 b) the lowest 30% of the IQs?
 c) the middle 80% of the IQs?
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Slide 6 - 41
Example (p. 133 #42)
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Consider the IQ model N(100,16) one last time.
th percentile?
 a) What IQ represents the 15
th percentile?
 b) What IQ represents the 98
 c) What’s the IQR of the IQs?
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Slide 6 - 42
Are You Normal? How Can You Tell?
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When you actually have your own data, you must
check to see whether a Normal model is
reasonable.
Looking at a histogram of the data is a good way
to check that the underlying distribution is roughly
unimodal and symmetric.
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Slide 6 - 43
Are You Normal? How Can You Tell? (cont.)
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A more specialized graphical display that can
help you decide whether a Normal model is
appropriate is the Normal probability plot.
If the distribution of the data is roughly Normal,
the Normal probability plot approximates a
diagonal straight line. Deviations from a straight
line indicate that the distribution is not Normal.
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Slide 6 - 44
Are You Normal? How Can You Tell? (cont.)
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Nearly Normal data have a histogram and a
Normal probability plot that look somewhat like
this example:
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Slide 6 - 45
Are You Normal? How Can You Tell? (cont.)
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A skewed distribution might have a histogram
and Normal probability plot like this:
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Slide 6 - 46
What Can Go Wrong?
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Don’t use a Normal model when the distribution is
not unimodal and symmetric.
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Slide 6 - 47
What Can Go Wrong? (cont.)
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Don’t use the mean and standard deviation when
outliers are present—the mean and standard
deviation can both be distorted by outliers.
Don’t round off too soon.
Don’t round your results in the middle of a
calculation.
Don’t worry about minor differences in results.
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Slide 6 - 48
What have we learned?
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The story data can tell may be easier to
understand after shifting or rescaling the data.
 Shifting data by adding or subtracting the same
amount from each value affects measures of
center and position but not measures of
spread.
 Rescaling data by multiplying or dividing every
value by a constant changes all the summary
statistics—center, position, and spread.
Copyright © 2010, 2007, 2004 Pearson Education, Inc.
Slide 6 - 49
What have we learned? (cont.)
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We’ve learned the power of standardizing data.
 Standardizing uses the SD as a ruler to
measure distance from the mean (z-scores).
 With z-scores, we can compare values from
different distributions or values based on
different units.
 z-scores can identify unusual or surprising
values among data.
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Slide 6 - 50
What have we learned? (cont.)
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We’ve learned that the 68-95-99.7 Rule can be a
useful rule of thumb for understanding
distributions:
 For data that are unimodal and symmetric,
about 68% fall within 1 SD of the mean, 95%
fall within 2 SDs of the mean, and 99.7% fall
within 3 SDs of the mean.
Copyright © 2010, 2007, 2004 Pearson Education, Inc.
Slide 6 - 51
What have we learned? (cont.)
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We see the importance of Thinking about
whether a method will work:
 Normality Assumption: We sometimes work
with Normal tables (Table Z). These tables are
based on the Normal model.
 Data can’t be exactly Normal, so we check the
Nearly Normal Condition by making a
histogram (is it unimodal, symmetric and free
of outliers?) or a normal probability plot (is it
straight enough?).
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Slide 6 - 52
Homework
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Chapter Homework: p. 129 #25, 27, 37, 39, 41
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Slide 6 - 53
Classwork
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Using 68-95-99.7 Rule WKST
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Slide 6 - 54
Quiz
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Chapter 6 Quiz
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Slide 6 - 55