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1 ABC 2 ABC 3 ABC 4 ABC 5 ABC 6 ABC 7 ABC 8 ABC 9 ABC 10 ABC 11 ABC 12 ABC 13 ABC 14 ABC 15 ABC 16 ABC 17 ABC 18 ABC 19 ABC 20 ABC 21 ABC 22 ABC 23 ABC 24 ABC 25 ABC 26 ABC 27 ABC 28 ABC 29 ABC 30 ABC 31 ABC 32 ABC 33 ABC 34 ABC 35 ABC 36 ABC 37 ABC 38 ABC 39 ABC 40 ABC 41 ABC 42 ABC 43 ABC 44 ABC 45 ABC 46 ABC 47 ABC 48 ABC 49 ABC 50 ABC 51 ABC 52 ABC 53 ABC 54 ABC 55 ABC 56 ABC 57 ABC 58 ABC 59 ABC 60 ABC 61 ABC 62 ABC 63 ABC 64 ABC by Jenny Paden, [email protected] 1A Give two ways to write each algebra expression in words. 9+r the sum of 9 and r 9 increased by r 1B Lou drives at 65 mi/h. Write an expression for the number of miles that Lou drives in t hours. 65t 1C Evaluate each expression for a = 4, b =7, and c = 2. ac ac = 4 ·2 =8 Substitute 4 for a and 2 for c. Simplify. 2A Add. –5 + (–7) –5 + (–7) = 5 + 7 5 + 7 = 12 –12 When the signs are the same, find the sum of the absolute values. Both numbers are negative, so the sum is negative. 2B Add. x + (–68) for x = 52 First substitute 52 for x. x + (–68) = 52 + (–68) When the signs of the numbers are different, find the difference of the absolute values. 68 – 52 –16 Use the sign of the number with the greater absolute value. The sum is negative. 2C Subtract. 4 To subtract –3 1 add 3 1 . 2 2 When the signs of the numbers are the same, find the sum of the absolute values: 3 1 + 1 = 4. 2 2 Both numbers are positive so, the sum is positive. 3A Find the value of each expression. 12 The quotient of two numbers with the same sign is positive. 3B Find the value of each expression. –6x for x = 7 –6x = –6(7) = –42 First substitute 7 for x. The product of two numbers with different signs is negative. 3C Divide. Copy Change Flip Multiply the numerators and multiply the denominators. and have the same sign, so the quotient is positive. 4A Simplify • (-2)3 = • -8 • -72 = • -49 4B Evaluate the expression. 22 9 9 2 2= 4 9 9 81 Use 2 as a factor 2 times. 9 4C Write each number as a power of the given base. 81; base –3 (–3)(–3)(–3)(–3) (–3)4 The product of four –3’s is 81. 5A Find each square root. A. 42 = 16 =4 B. 32 = 9 = –3 Think: What number squared equals 16? Positive square root positive 4. Think: What is the opposite of the square root of 9? Negative square root negative 3. 5B Write all classifications that apply to each Real number. –32 32 –32 = – = –32.0 1 32 can be written as a fraction and a decimal. rational number, integer, terminating decimal 5C Write all classifications that apply to each real number. = 3.16227766… The digits continue with no pattern. irrational number 6A Simplify each expression. 15 – 2 · 3 + 1 15 – 2 · 3 + 1 15 – 6 + 1 10 There are no grouping symbols. Multiply. Subtract and add from left to right. 6B Simplify each expression. 12 – 32 + 10 ÷ 2 12 – 32 + 10 ÷ 2 There are no grouping symbols. 12 – 9 + 10 ÷ 2 Evaluate powers. The exponent applies only to the 3. Divide. Subtract and add from left to right. 12 – 9 + 5 8 6C Evaluate the expression for the given value of x. (x · 22) ÷ (2 + 6) for x = 6 (x · 22) ÷ (2 + 6) (6 · 22) ÷ (2 + 6) (6 · 4) ÷ (2 + 6) (24) ÷ (8) 3 First substitute 6 for x. Square two. Perform the operations inside the parentheses. Divide. 7A Write the product using the Distributive Property. Then simplify. 9(52) 9(50 + 2) 9(50) + 9(2) 450 + 18 468 Rewrite 52 as 50 + 2. Use the Distributive Property. Multiply. Add. 7B Simplify the expression by combining like terms. 72p – 25p 72p – 25p 47p 72p and 25p are like terms. Subtract the coefficients. 7C Simplify the expression by combining like terms. 0.5m + 2.5n 0.5m + 2.5n 0.5m and 2.5n are not like terms. 0.5m + 2.5n Do not combine the terms. 8A Name the quadrant in which each point lies. A. E Quadrant ll B. F no quadrant (y-axis) •F •E •G •H 8B The ordered pair of each point •F G (4, 1) •E •G •H H (-1, -1) 8C A cable company charges $50 to set up a movie channel and $3.00 per movie watched. Write a rule for the company’s fee. Write ordered pairs for the fee when a person watches 1, 2, 3, or 4 movies. y = 50 + 3x (1, 53), (2, 56), (3, 59), (4, 62) 9A Solve the equation. Check your answer. y – 8 = 24 +8 +8 y = 32 Since 8 is subtracted from y, add 8 to both sides to undo the subtraction. 9B Solve the equation. Check your answer. 5 =z– 7 7 7 Since is subtracted from z, add to 16 16 16 16 both sides to undo the subtraction. + 7 + 7 16 16 3=z 4 9C Solve the equation. Check your answer. 4.2 = t + 1.8 –1.8 – 1.8 2.4 = t Since 1.8 is added to t, subtract 1.8 from both sides to undo the addition. 10A Solve the equation. n = 2.8 6 n = 16.8 Since n is divided by 6, multiply both sides by 6 to undo the division. 10B Solve the equation. Check your answer. 9y = 108 y = 12 Since y is multiplied by 9, divide both sides by 9 to undo the multiplication. 10C Solve the equation. 5 w = 20 6 The reciprocal of 5 is 6 . Since w is 6 5 5 multiplied by , multiply both sides 6 6 by . w = 24 5 11A Solve 5t – 2 = –32. 5t – 2 = –32 +2 +2 5t = –30 5t = –30 5 5 t = –6 First t is multiplied by 5. Then 2 is subtracted. Work backward: Add 2 to both sides. Since t is multiplied by 5, divide both sides by 5 to undo the multiplication. 11B Solve –4 + 7x = 3. –4 + 7x = 3 +4 +4 7x = 7 7x = 7 7 7 x=1 First x is multiplied by 7. Then –4 is added. Work backward: Add 4 to both sides. Since x is multiplied by 7, divide both sides by 7 to undo the multiplication. 11C Solve 2a + 3 – 8a = 8 2a + 3 – 8a = 8 2a – 8a + 3 = 8 –6a + 3 = 8 –3 –3 –6a = 5 Use the Commutative Property of Addition. Combine like terms. Since 3 is added to –6a, subtract 3 from both sides to undo the addition. Since a is multiplied by –6, divide both sides by –6 to undo the multiplication. 12A Solve 4b + 2 = 3b –3b –3b b+2= 0 –2 –2 b = –2 4b + 2 = 3b To collect the variable terms on one side, subtract 3b from both sides. 12B Solve 0.5 + 0.3y = 0.7y – 0.3 0.5 + 0.3y = 0.7y – 0.3 –0.3y –0.3y 0.5 = 0.4y – 0.3 +0.3 0.8 + 0.3 = 0.4y 2=y To collect the variable terms on one side, subtract 0.3y from both sides. Since 0.3 is subtracted from 0.4y, add 0.3 to both sides to undo the subtraction. Since y is multiplied by 0.4, divide both sides by 0.4 to undo the multiplication. 12CSolve 3x + 15 – 9 = 2(x + 2) 3x + 15 – 9 = 2(x + 2) Distribute 2 to the expression in parentheses. 3x + 15 – 9 = 2(x) + 2(2) 3x + 15 – 9 = 2x + 4 3x + 6 = 2x + 4 –2x –2x x+6= –6 x = –2 4 –6 Combine like terms. To collect the variable terms on one side, subtract 2x from both sides. Since 6 is added to x, subtract 6 from both sides to undo the addition. 13A The ratio of the number of bones in a human’s ears to the number of bones in the skull is 3:11. There are 22 bones in the skull. How many bones are in the ears? Write a ratio comparing bones in ears to bones in skull. Write a proportion. Let x be the number of bones in ears. Since x is divided by 22, multiply both sides of the equation by 22. There are 6 bones in the ears. 13B Raulf Laue of Germany flipped a pancake 416 times in 120 seconds to set the world record. Find the unit rate. Round your answer to the nearest hundredth. Write a proportion to find an equivalent ratio with a second quantity of 1. Divide on the left side to find x. The unit rate is about 3.47 flips/s. 13C The ratio of games lost to games won for a baseball team is 2:3. The team has won 18 games. How many games did the team lose? Write a ratio comparing games lost to games won. Write a proportion. Let x be the number of games lost. Since x is divided by 18, multiply both sides of the equation by 18. The team lost 12 games. 14A Solve the proportion. Use cross products. 3(m) = 5(9) 3m = 45 Divide both sides by 3. m = 15 14B Solve the proportion. Use cross products. 6(7) = 2(y – 3) 42 = 2y – 6 +6 +6 Add 6 to both sides. 48 = 2y Divide both sides by 2. 24 = y 14C In a school, the ratio of boys to girls is 4:3. There are 216 boys. How many girls are there? 162 15A Find the value of x in the diagram if ABCD ~ WXYZ. ABCD ~ WXYZ Use cross products. x = 2.8 Since x is multiplied by 5, divide both sides by 5 to undo the multiplication. The length of XY is 2.8 in. 15B A flagpole casts a shadow that is 75 ft long at the same time a 6-foot-tall man casts a shadow that is 9 ft long. Write and solve a proportion to find the height of the flag pole. Since h is multiplied by 9, divide both sides by 9 to undo the multiplication. The flagpole is 50 feet tall. 15C A forest ranger who is 150 cm tall casts a shadow 45 cm long. At the same time, a nearby tree casts a shadow 195 cm long. Write and solve a proportion to find the height of the tree. 45x = 29250 Since x is multiplied by 45, divide both sides by 45 to undo the multiplication. x = 650 The tree is 650 centimeters tall. 16A Find 30% of 80 Method 1 Use a proportion. Use the percent proportion. Let x represent the part. 100x = 2400 x = 24 Find the cross products. Since x is multiplied by 100, divide both sides by 100 to undo the multiplication. 16B What percent of 45 is 35? Round your answer to the nearest tenth. Method 1 Use a proportion. Use the percent proportion. Let x represent the percent. 45x = 3500 x ≈ 77.8 Find the cross products. Since x is multiplied by 45, divide both sides by 45 to undo the multiplication. 16C 38% of what number is 85? Round your answer to the nearest tenth. Method 1 Use a proportion. Use the percent proportion. Let x represent the whole. 38x = 8500 x = 223.7 Find the cross products. Since x is multiplied by 38, divide both sides by 38 to undo the multiplication. 17A Mr. Cortez earns a base salary of $26,000 plus a sales commission of 5%. His total sales for one year were $300,000. Find his total pay for the year. total pay = base salary + commission = base + % of total sales = 26,000 + 5% of 300,000 = 26,000 + (0.05)(300,000) = 26,000 + 15,000 = 41,000 Mr. Cortez’s total pay was $41,000. 17B Find the simple interest paid for 3 years on a $2500 loan at 11.5% per year. I = Prt I = (2500)(0.115)(3) I = 862.50 Write the formula for simple interest. Substitute known values. Write the interest rate as a decimal. Multiply. The amount of interest is $862.50. 17C Lunch at a restaurant is $27.88. Estimate a 15% tip. Step 1 First round $27.88 to $30. Step 2 Think: 15% = 10% + 5% Move the decimal point one place left. 10% of $30 = $3.00 Step 3 Think 5% = 10% ÷ 2 = $3.00 ÷ 2 = $1.50 Step 4 15 = 10% + 5% = $3.00 + $1.50 = $4.50 The tip should be about $4.50. 18A Use the graph to answer each question. A. Which casserole was ordered the most? lasagna B. About how many more tuna C. noodle casseroles were ordered than king ranch casseroles? 10 18B Use the graph to answer each question. A. Which feature received the same satisfaction rating for each SUV? Cargo Find the two bars that are the same. B. Which SUV received a better rating for mileage? SUV Y Find the longest mileage bar. 18C Use the graph to answer each question. At what time was the humidity the lowest? 4 A.M. Identify the lowest point. 19A The numbers of defective widgets in batches of 1000 are given below. Use the data to make a stem-and-leaf plot. 14, 12, 8, 9, 13, 20, 15, 9, 21, 8, 13, 19 Number of Defective Widgets per Batch 0 1 2 8899 233459 01 Key: 1|9 means 19 The tens digits are the stems. The ones digits are the leaves. List the leaves from least to greatest within each row. Title the graph and add a key. 19B The number of runs scored by a softball team at 19 games is given. Use the data to make a box-and-whisker plot. 3, 8, 10, 12, 4, 9, 13, 20, 12, 15, 10, 5, 11, 5, 10, 6, 7, 6, 11 3, 4, 5, 5, 6, 6, 7, 8, 9, 10, 10, 10, 11, 11, 12, 12, 13, 15, 20 Minimum 3 Q2 10 Q1 6 First quartile Minimum 0 20 Third quartile Maximum Median ● Maximum Q3 12 ● ● 8 ● ● 16 24 19C The numbers of pounds of laundry in the washers at a laundromat are given below. Use the data to make a cumulative frequency table. 2, 12, 4, 8, 5, 8, 11, 3, 6, 9, 8 20A Find the mean, median, mode, and range of the data set. The number of hours students spent on a research project: 2, 4, 10, 7, 5 Write the data in numerical order. mean: Add all the values and divide by the number of values. median: 2, 4, 5, 7, 10 The median is 5. There are an odd number of values. Find the middle mode: none value. No value occurs more than range: 10 – 2 = 8 once. 20B Find the mean, median, mode, and range of each data set. The weight in pounds of six members of a basketball team: 161, 156, 150, 156, 150, 163 mean: median: 150, 150, 156, 156, 161, 163 The median is 156. modes: 150 and 156 range: 163 – 150 = 13 150 and 156 both occur more often than any other value. 20C The following list gives times of Tara’s oneway ride to school (in minutes) for one week: 12, 23, 13, 14, 13. Use the mean, median, and mode of her times to answer each question. mean = 15 median = 13 mode = 13 The graph shows customer satisfaction with different brands. Explain why the graph is misleading. The scale on the vertical axis starts at 76. This exaggerates the difference’s between the sizes of the bars. % 21A 21B The graph shows the amount of rainfall by year in a particular metropolitan area. Explain why the graph is misleading. The intervals on the vertical axis are not equal. 21C The graph shows the allocation of the county budget for 2005. Explain why the graph is misleading. The sections of the graph do not add to 100%, so the expenditures are not accurately represented. 22A Identify the sample space and the outcome shown for each experiment. Rolling a number cube Sample space:{1, 2, 3, 4, 5, 6} Outcome shown: 4 22B Identify the sample space and the outcome shown for each experiment. Spinning a spinner Sample space:{red, green, orange, purple} Outcome shown: green 22C An experiment consists of spinning a spinner. Use the results in the table to find the experimental probability of the event. Spinner lands on orange Outcome Frequency Green 15 Orange 10 Purple 8 Pink 7 23A An experiment consists of rolling a number cube. Find the theoretical probability of each outcome. rolling a 5 There is one 5 on a number cube. 23B An experiment consists of rolling a number cube. Find the theoretical probability of each outcome. rolling an odd number There 3 odd numbers on a cube. = 0.5 = 50% 23C A jar has green, blue, purple, and white marbles. The probability of choosing a green marble is 0.2, the probability of choosing blue is 0.3, the probability of choosing purple is 0.1. What is the probability of choosing white? Either it will be a white marble or not. P(green) + P(blue) + P(purple) + P(white) = 1.0 0.2 + 0.3 + 0.1 + P(white) = 1.0 0.6 + P(white) = 1.0 Subtract 0.6 from – 0.6 – 0.6 both sides. P(white) = 0.4 24A Tell whether each set of events is independent or dependent. Explain you answer. A number cube lands showing an odd number. It is rolled a second time and lands showing a 6. Independent; the result of rolling the number cube the 1st time does not affect the result of the 2nd roll. 24B An experiment consists of randomly selecting a marble from a bag, replacing it, and then selecting another marble. The bag contains 3 red marbles and 12 green marbles. What is the probability of selecting a red marble and then a green marble? P(red, green) = P(red) P(green) The probability of selecting red is , and the probability of selecting green is . 24C A coin is flipped 4 times. What is the probability of flipping 4 heads in a row. Because each flip of the coin has an equal probability of landing heads up, or a tails, the sample space for each flip is the same. The events are independent. P(h, h, h, h) = P(h) • P(h) • P(h) • P(h) The probability of landing heads up is with each event. 25A A sandwich can be made with 3 different types of bread, 5 different meats, and 2 types of cheese. How many types of sandwiches can be made if each sandwich consists of one bread, one meat, and one cheese. Method 2 Use the Fundamental Counting Principle. There are 3 choices for the first item, 352 5 choices for the second item, and 30 2 choices for the third item. There are 30 possible types of sandwiches. 25B A voicemail system password is 1 letter followed by a 3-digit number less than 600. How many different voicemail passwords are possible? Method 2 Use the Fundamental Counting Principle. 26 600 15,600 There are 26 choices for letters and 600 different numbers (000-599). There are 15,600 possible combinations of letters and numbers. 25C A group of 8 swimmers are swimming in a race. Prizes are given for first, second, and third place. How many different outcomes can there be? The order in which the swimmers finish matters so use the formula for permutations. n = 8 and r = 3. A number divided by itself is 1, so you can divide out common factors in the numerator and denominator. There can be 336 different outcomes for the race. 26A Graph each inequality. m ≤ –3 Draw a solid circle at –3. −3 –8 –6 –4 –2 0 2 4 6 8 10 12 Shade in all numbers less than –3 and draw an arrow pointing to the left. 26B Graph each inequality. c > 2.5 Draw an empty circle at 2.5. –4 –3 –2 –1 0 1 2 3 4 5 6 Shade in all the numbers greater than 2.5 and draw an arrow pointing to the right. 26C Graph each inequality. 22 – 4 ≥ w Draw a solid circle at 0. 22 –4≥w 4–4≥ w 0≥w –4 –3 –2 –1 0 1 Shade in all numbers less than 0 and draw an arrow pointing to the left. 2 3 4 5 6 27A Write the inequality shown by each graph. x<2 Use any variable. The arrow points to the left, so use either < or ≤. The empty circle at 2 means that 2 is not a solution, so use <. 27B Write the inequality shown by each graph. x ≥ –0.5 Use any variable. The arrow points to the right, so use either > or ≥. The solid circle at –0.5 means that –0.5 is a solution, so use ≥. 27C Ray’s dad told him not to turn on the air conditioner unless the temperature is at least 85°F. Define a variable and write an inequality for the temperatures at which Ray can turn on the air conditioner. Graph the solutions. Let t represent the temperatures at which Ray can turn on the air conditioner. Turn on the AC when temperature t ≥ t 85 70 75 80 85 is at least 85°F 90 85 Draw a solid circle at 85. Shade all numbers greater than 85 and draw an arrow pointing to the right. 28A Solve the inequality and graph the solutions. x + 12 < 20 x + 12 < 20 –12 –12 x+0 < 8 x < 8 –10 –8 –6 –4 –2 0 2 Since 12 is added to x, subtract 12 from both sides to undo the addition. 4 6 8 10 Draw an empty circle at 8. Shade all numbers less than 8 and draw an arrow pointing to the left. 28B Solve the inequality and graph the solutions. d – 5 > –7 d – 5 > –7 +5 +5 d + 0 > –2 d > –2 Since 5 is subtracted from d, add 5 to both sides to undo the subtraction. Draw an empty circle at –2. –10 –8 –6 –4 –2 0 2 4 6 8 10 Shade all numbers greater than –2 and draw an arrow pointing to the right. 28C Solve each inequality and graph the solutions. > –3 + t > –3 + t +3 +3 > 0+t t< Since –3 is added to t, add 3 to both sides to undo the addition. –10 –8 –6 –4 –2 0 2 4 6 8 10 29A Solve the inequality and graph the solutions. 7x > –42 7x > –42 Since x is multiplied by 7, divide both sides by 7 to undo the multiplication. > 1x > –6 x > –6 –10 –8 –6 –4 –2 0 2 4 6 8 10 29B Solve the inequality and graph the solutions. 3(2.4) ≤ 3 Since m is divided by 3, multiply both sides by 3 to undo the division. 7.2 ≤ m(or m ≥ 7.2) 0 2 4 6 8 10 12 14 16 18 20 29C Solve the inequality and graph the solutions. –12x > 84 Since x is multiplied by –12, divide both sides by –12. Change > to <. x < –7 –7 –14 –12 –10 –8 –6 –4 –2 0 2 4 6 30A Solve the inequality and graph the solutions. 45 + 2b > 61 45 + 2b > 61 –45 –45 Since 45 is added to 2b, subtract 45 from both sides to undo the addition. 2b > 16 b>8 0 2 4 6 Since b is multiplied by 2, divide both sides by 2 to undo the multiplication. 8 10 12 14 16 18 20 30B Solve the inequality and graph the solutions. 8 – 3y ≥ 29 Since 8 is added to –3y, subtract 8 from both sides to undo the addition. 8 – 3y ≥ 29 –8 –8 –3y ≥ 21 Since y is multiplied by –3, divide both sides by –3 to undo the multiplication. Change ≥ to ≤. y ≤ –7 –7 –10 –8 –6 –4 –2 0 2 4 6 8 10 30C Solve the inequality and graph the solutions. –12 ≥ 3x + 6 Since 6 is added to 3x, subtract 6 from both sides to undo the addition. –12 ≥ 3x + 6 –6 –6 –18 ≥ 3x Since x is multiplied by 3, divide both sides by 3 to undo the multiplication. –6 ≥ x –10 –8 –6 –4 –2 0 2 4 6 8 10 31A Solve the inequality and graph the solutions. –4(2 – x) ≤ 8 −4(2 – x) ≤ 8 −4(2) − 4(−x) ≤ 8 –8 + 4x ≤ 8 +8 +8 4x ≤ 16 Distribute –4 on the left side. Since –8 is added to 4x, add 8 to both sides. Since x is multiplied by 4, divide both sides by 4 to undo the multiplication. x≤4 –10 –8 –6 –4 –2 0 2 4 6 8 10 31B Solve the inequality and graph the solutions. 3 + 2(x + 4) > 3 Distribute 2 on the left side. x Combine like terms. Since 11 is added to 2x, subtract 11 from both sides to undo the addition. 3 + 2(x + 4) > 3 3 + 2x + 8 > 3 2x + 11 > 3 – 11 – 11 2x > –8 Since x is multiplied by 2, divide both sides by 2 to undo the multiplication. x > –4 –10 –8 –6 –4 –2 0 2 4 6 8 10 31C Solve the inequality and graph the solutions. Multiply both sides by 6, the LCD of the fractions. Distribute 6 on the left side. 4f + 3 > 2 –3 –3 4f > –1 Since 3 is added to 4f, subtract 3 from both sides to undo the addition. 32A Solve the inequality and graph the solutions. y ≤ 4y + 18 y ≤ 4y + 18 –y –y To collect the variable terms on one side, subtract y from both sides. 0 ≤ 3y + 18 –18 – 18 Since 18 is added to 3y, subtract 18 from both sides to undo the addition. –18 ≤ 3y Since y is multiplied by 3, divide both sides by 3 to undo the multiplication. –6 ≤ y (or y –6) –10 –8 –6 –4 –2 0 2 4 6 8 10 32BSolve the inequality and graph the solutions. 4m – 3 < 2m + 6 4m – 3 < 2m + 6 –2m – 2m 2m – 3 < +3 2m < +6 +3 9 To collect the variable terms on one side, subtract 2m from both sides. Since 3 is subtracted from 2m, add 3 to both sides to undo the subtraction Since m is multiplied by 2, divide both sides by 2 to undo the multiplication. 4 5 6 32CSolve the inequality and graph the solutions. 2(k – 3) > 6 + 3k – 3 2(k – 3) > 3 + 3k 2k + 2(–3) > 3 + 3k 2k – 6 > 3 + 3k –2k – 2k –6 > 3 + k –3 –3 –9 > k Distribute 2 on the left side of the inequality. To collect the variable terms, subtract 2k from both sides. Since 3 is added to k, subtract 3 from both sides to undo the addition. 33A Solve the compound inequality and graph the solutions. –5 < x + 1 < 2 –5 < x + 1 < 2 –1 –1–1 –6 < x < 1 Graph –6 < x. –10 –6 –4 –2 0 2 4 6 8 10 Graph x < 1. Graph the intersection by finding where the two graphs overlap. 33B Solve the compound inequality and graph the solutions. 8 < 3x – 1 ≤ 11 8 < 3x – 1 ≤ 11 +1 +1 +1 9 < 3x ≤ 12 Since 1 is subtracted from 3x, add 1 to each part of the inequality. Since x is multiplied by 3, divide each part of the inequality by 3 to undo the multiplication. 3<x≤4 –4 –3 –2 –1 0 1 2 3 4 5 33C Solve the inequality and graph the solutions. 8 + t ≥ 7 OR 8 + t < 2 8 + t ≥ 7 OR 8 + t < 2 –8 –8 –8 −8 t ≥ –1 OR t < –6 –10 –8 –6 –4 –2 0 2 4 6 8 10 Solve each simple inequality. 34A Each day several leaves fall from a tree. One day a gust of wind blows off many leaves. Eventually, there are no more leaves on the tree. Choose the graph that best represents the situation. The correct graph is B. 34B The air temperature increased steadily for several hours and then remained constant. At the end of the day, the temperature increased slightly before dropping sharply. Choose the graph that best represents this situation. The correct graph is graph C. 34C Sketch a graph for the situation. Tell whether the graph is continuous or discrete. • • • • • initially increases remains constant decreases to a stop increases remains constant Speed A truck driver enters a street, drives at a constant speed, stops at a light, and then continues. As time passes during the trip y (moving left to right along the x-axis) the truck's speed (y-axis) does the following: Time x The graph is continuous. 35A Express the relation {(2, 3), (4, 7), (6, 8)} as a table, as a graph, and as a mapping diagram. Table x y Graph Mapping Diagram y x 1 3 2 4 3 5 35B Give the domain and range of the relation. 6 5 2 1 –4 –1 0 The domain values are all x-values 1, 2, 5 and 6. The range values are y-values 0, –1 and –4. Domain: {6, 5, 2, 1} Range: {–4, –1, 0} 35C Give the domain and range of the relation. x y 1 1 4 4 8 1 The domain values are all x-values 1, 4, and 8. The range values are y-values 1 and 4. Domain: {1, 4, 8} Range: {1, 4} 36A Determine a relationship between the x- and y-values. Write an equation. x 5 y 1 or 10 15 20 2 3 4 The value of y is one-fifth of x. 36B Determine a relationship between the x- and y-values. Write an equation. {(1, 3), (2, 6), (3, 9), (4, 12)} y = 3x 1 2 3 4 3 6 9 12 The value of y is 3 times x. 36C Identify the independent and dependent variables in the situation. The height of a candle decrease d centimeters for every hour it burns. The height of a candle depends on the number of hours it burns. Dependent: height of candle Independent: time 37A Evaluate the function for the given input values. For f(x) = 3x + 2, find f(x) when x = 7 and when x = –4. f(x) = 3(x) + 2 f(7) = 3(7) + 2 Substitute 7 for x. = 21 + 2 Simplify. = 23 f(x) = 3(x) + 2 f(–4) = 3(–4) + 2 Substitute –4 for x. Simplify. = –12 + 2 = –10 37B Evaluate the function for the given input values. For g(t) = 1.5t – 5, find g(t) when t = 6 and when t = –2. g(t) = 1.5t – 5 g(t) = 1.5t – 5 g(6) = 1.5(6) – 5 g(–2) = 1.5(–2) – 5 =9–5 = –3 – 5 =4 = –8 37C Evaluate the function for the given input values. For h(c) = 2c – 1, find h(c) when c = 1 and when c = –3. h(c) = 2c – 1 h(1) = 2(1) – 1 h(c) = 2c – 1 h(–3) = 2(–3) – 1 =2–1 = –6 – 1 =1 = –7 38A A ___________ is a graph with points plotted to show a possible relationship between two sets of data. A. Bar Graph B. Circle Graph C. Line Graph D. Scatter Plot D. Scatter Plot 38B Example 1: Graphing a Scatter Plot from Given Data The table shows the number of cookies in a jar from the time since they were baked. Graph a scatter plot using the given data. Use the table to make ordered pairs for the scatter plot. The x-value represents the time since the cookies were baked and the y-value represents the number of cookies left in the jar. Plot the ordered pairs. 38C The table shows the number of points scored by a high school football team in the first four games of a season. Graph a scatter plot using the given data. Game Score 1 6 2 3 4 21 46 34 Use the table to make ordered pairs for the scatter plot. The x-value represents the individual games and the y-value represents the points scored in each game. Plot the ordered pairs. 39A Identify whether the graph represents a function. Explain. If the graph does represent a function, is the function linear? Each domain value is paired with exactly one range value. The graph forms a line. linear function 39B Identify whether the graph represents a function. Explain. If the graph does represent a function, is the function linear? Each domain value is paired with exactly one range value. The graph is not a line. not a linear function 39C Tell whether the set of ordered pairs satisfies a linear function. Explain. {(0, –3), (4, 0), (8, 3), (12, 6), (16, 9)} x +4 +4 +4 +4 y 0 –3 4 0 8 3 12 6 16 9 +3 +3 +3 +3 Write the ordered pairs in a table. Look for a pattern. A constant change of +4 in x corresponds to a constant change of +3 in y. These points satisfy a linear function. 40A Find the x- and y-intercepts. 5x – 2y = 10 5x – 0 = 10 5x = 10 x=2 The x-intercept is 2. y = –5 The y-intercept is –5. 40B Find the x- and y-intercepts. The y-intercept is 1. The x-intercept is –2. 40C Use intercepts to GRAPH the line described by the equation. 3x – 7y = 21 Step 1 Find the intercepts. Step 2 Graph the line. 3x = 21 x x=7 y = –3 Plot (7, 0) and (0, –3). Connect with a straight line. 41A Tell whether the slope of each line is positive, negative, zero or undefined. A. B. The line rises from left to right. The line falls from left to right. The slope is positive. The slope is negative. 41B Find the slope of the line. 2. 41C Find the slope of the line. undefined 42A Find the slope of the line that contains (2, 5) and (8, 1). Use the slope formula. Substitute (2, 5) for (x1, y1) and (8, 1) for (x2, y2). Simplify. 42B Find the slope of the line that contains (–2, –2) and (7, –2). Use the slope formula. Substitute (–2, –2) for (x1, y1) and (7, –2) for (x2, y2). Simplify. =0 42CThe graph shows a linear relationship. Find the slope. Let (0, 2) be (x1, y1) and (–2, –2) be (x2, y2). Use the slope formula. Substitute (0, 2) for (x1, y1) and (–2, –2) for (x2, y2). Simplify. 43A Write the equation in slope-intercept form. Then graph the line described by the equation. y = x + 0 is in the form y = mx + b. slope: y-intercept: b = 0 Step 1 Plot (0, 0). Step 2 Count 2 units up and 3 units right and plot another point. Step 3 Draw the line connecting the two points. 43B Graph the line given the slope and y-intercept. slope = 2, y-intercept = –3 Step 1 The y-intercept is –3, so the line contains (0, –3). Plot (0, –3). Step 2 Slope = Count 2 units up and 1 unit right from (0, –3) and plot another point. Step 3 Draw the line through the two points. Run = 1 Rise = 2 43C Write the equation that describes the line in slope-intercept form. slope = ; y-intercept = 4 y = mx + b y= x+4 Substitute the given values for m and b. Simply if necessary. 44A Write the trigonometric ratio as a fraction and as a decimal rounded to the nearest hundredth. sin J 44B Write the trigonometric ratio as a fraction and as a decimal rounded to the nearest hundredth. tan K 44C Find the measure of angle D 5.3 0 tan D 68 2.1 1 45A Find BC. Write a trigonometric ratio. Substitute the given values. Multiply both sides by BC and divide by tan 15°. BC 38.07 ft Simplify the expression. 45B Find the length of QR Substitute the given values. 12.9(sin 63°) = QR 11.49 cm QR Multiply both sides by 12.9. Simplify the expression. 45C Find the length of FD Substitute the given values. Multiply both sides by FD and divide by cos 39°. FD 25.74 m Simplify the expression. 46A The Seattle Space Needle casts a 67meter shadow. If the angle of elevation from the tip of the shadow to the top of the Space Needle is 70º, how tall is the Space Needle? Round to the nearest meter. You are given the side adjacent to A, and y is the side opposite A. So write a tangent ratio. y = 67 tan 70° Multiply both sides by 67. y 184 m Simplify the expression. 46B Use the diagram above to classify each angle as an angle of elevation or angle of depression. 1a. 5 1b. 6 1a. Depression 1b. Elevation 46C A plane is flying at an altitude of 14,500 ft. The angle of elevation from the control tower to the plane is 15°. What is the horizontal distance from the plane to the tower? Round to the nearest foot. 14500 tan 15 x 54,115 ft 47A Given the figure, segment JM is best described as: a. Chord b. Secant c. Tangent d. Diameter A. Chord 47B Given the figure, Line JM is best described as: a. Chord b. Secant c. Tangent d. Diameter B. Secant 47C Given the figure, line m is best described as: a. Chord b. Secant c. Tangent d. Diameter C. Tangent 48A Find a. 5a – 32 = 4 + 2a 3a – 32 = 4 3a = 36 a = 12 48B Find RS n + 3 = 2n – 1 4=n RS = 4 + 3 =7 48C Find RS x = 4x – 25.2 –3x = –25.2 x = 8.4 = 2.1 49A Find mLJN mLJN = 360° – (40 + 25)° = 295° 49B Find n. 9n – 11 = 7n + 11 2n = 22 n = 11 49C C J, and mGCD mNJM. Find NM. 14t – 26 = 5t + 1 9t = 27 t=3 NM = 5(3) + 1 = 16 50A Find each measure. mPRU 50B Find each measure. mSP 50C Find each measure. mDAE 51A Find each measure. mEFH = 65° 51B Find each measure. 51C Find each angle measure. mABD 52A Find the value of x. 50° = 83° – x x = 33° 52B 52C Find the value of x. 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