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جامـ ــعه بابـ ـ ـ ـ ـ ـ ـ ــل كليه الهندسه \ قسم الهندسه الميكانيكيه :1 السؤال العلياي التاي تتوا السااد ارسم مخطط انسيابي لحساب عدد ومعدل الطلبه النااححي لفا ال تاضااياو والزياتااال والوييااال وا حيااال:ما عشا ت طالا (عليااا ا ما اد الي حلااه السادساة .)واللغه الع بيه والغه ا نولياته Solution الط تقه ا ولى n = 20 ' student numbers STU = 0 ' SUMATION OF STUDENT FOR I = 1 TO n INPUT A$, X1, X2, X3, X4, X5, X6 IF X1 < 50 THEN 10 IF X2 < 50 THEN 10 IF X3 < 50 THEN 10 IF X4 < 50 THEN 10 IF X5 < 50 THEN 10 IF X6 < 50 THEN 10 STU = STU + 1 AVE = (X1 + X2 + X3 + X4 + X5 + X6) /6 PRINT STU, A$, AVE 10 NEXT I PRINT STU END الط تقه الثانيه n = 20 ' student numbers DIM A$(20), X(20, 6), AVE(20) STU = 0 ' SUMATION OF STUDENT FOR I = 1 TO n INPUT A$(I) FOR J = 1 TO 6 INPUT X(I, J) NEXT J NEXT I FOR I = 1 TO n FOR J = 1 TO 6 IF X(I, J) < 50 THEN 10 NEXT J STU = STU + 1 FOR J = 1 TO 6 AVE(I) = AVE(I) + X(I, J) / 6 NEXT J PRINT STU, A$(I), AVE(I) 10 NEXT I PRINT STU END :2 السؤال ارسم مخطط انسيابي لت تي بشول تنازلي عش ه اعدد عش ائي وما مام اتدااد مدا ع ا عاداد .الي حبه فقط Solution الط تقه ا ولى الط تقه الثانيه READ X1, X2, X3, X4, X5, X6, X7, X8, X9, X10 DATA 12,-1,2,3,-4,6,5,-3,1,4 XMAX = X1 IF X2 > XMAX THEN XMAX = X2 IF X3 > XMAX THEN XMAX = X3 IF X4 > XMAX THEN XMAX = X4 IF X5 > XMAX THEN XMAX = X5 IF X6 > XMAX THEN XMAX = X6 IF X7 > XMAX THEN XMAX = X7 IF X8 > XMAX THEN XMAX = X8 IF X9 > XMAX THEN XMAX = X9 IF X10 > XMAX THEN XMAX = X10 PRINT " THE LARGER NUMBER ="; XMAX SUM = 0 IF X1 > 0 THEN SUM = SUM + X1 IF X2 > 0 THEN SUM = SUM + X2 IF X3 > 0 THEN SUM = SUM + X3 IF X4 > 0 THEN SUM = SUM + X4 IF X5 > 0 THEN SUM = SUM + X5 IF X6 > 0 THEN SUM = SUM + X6 IF X7 > 0 THEN SUM = SUM + X7 IF X8 > 0 THEN SUM = SUM + X8 IF X9 > 0 THEN SUM = SUM + X9 IF X10 > 0 THEN SUM = SUM + X10 PRINT " the summation of positive number ="; SUM END N = 10 DIM X(N) FOR I = 1 TO N READ X(I) NEXT DATA 12,-1,2,3,-4,6,5,-3,1,4 XMAX = X(1) SUM = 0 FOR I = 2 TO N IF X(I) > XMAX THEN XMAX = X(I) IF X(I) > 0 THEN SUM = SUM + X(I) NEXT PRINT "MAXIMUM NUMBER="; XMAX, "THE SUMMATION OF POSITIVE NUMBER = "; SUM; "" END تداد اكب عدد م ح واصغ عدد سل م بي عش ت عدد عش ائي :3 السؤال ارسم مخطط انسيابي Solution الط تقه ا ولى الط تقه الثانيه READ X1, X2, X3, X4, X5, X6, X7, X8, X9, X10, X11, X12, X13, X14, X15, X16, X17, X18, X19, X20 DATA 12,-1,2,3,-4,6,5,-3,1,4 XMAP = 0 'MAXIMUM POSITIVE NUMBER SHOULD BE LARGER THEN ZERO XMIN = 0 'MINIMUM NEGATIVE NUMBER SHOULD BE LEES THAN ZERO IF X1 > 0 THEN IF X1 > XMAP THEN XMAP = X1: ELSE : IF X1 < XMIN THEN XMIN = X1 END IF IF X2 > 0 THEN IF X2 > XMAP THEN XMAP = X2: ELSE : IF X2 < XMIN THEN XMIN = X2 END IF IF X1 > 0 THEN IF X3 > XMAP THEN XMAP = X3: ELSE : IF X3 < XMIN THEN XMIN = X3 END IF IF X4 > 0 THEN IF X4 > XMAP THEN XMAP = X4: ELSE : IF X4 < XMIN THEN XMIN = X4 END IF IF X1 > 0 THEN IF X5 > XMAP THEN XMAP = X5: ELSE : IF X5 < XMIN THEN XMIN = X5 END IF N = 20 DIM X(N) FOR I = 1 TO N INPUT X(I) NEXT XMAP = 0 'MAXIMUM POSITIVE NUMBER SHOULD BE LARGER THEN ZERO XMIN = 0 'MINIMUM NEGATIVE NUMBER SHOULD BE LEES THAN ZERO S = 0: P = 0 FOR I = 1 TO N IF X(I) > XMAP THEN XMAP = X(I): P = P + 1 IF X(I) < XMIN THEN XMIN = X(I): S = S + 1 NEXT IF P = 0 THEN PRINT "THERE IS NO POSITIVE NUMBER" IF S = 0 THEN PRINT "THERE IS NO NEGATIVE NUMBER" PRINT " THE MAXIMUM POSITIVE NUMBER ="; XMAP PRINT " THE MINIUM NEGATIVE NUMBER ="; XMIN END PRINT " THE MAXIMUM POSITIVE NUMBER ="; XMAP PRINT " THE MINIUM NEGATIVE NUMBER ="; XMIN END :4 السؤال اكت اليعاد و التاليه بفيغ لبيسك Z M X 2 Y 2 2 Sin ( Ln ( X Y ) X ) 3 4 Sin (X) (X Y) 2 X 1 3 X e Cos(X) Y :5 السؤال اكت اليعاد و التاليه بفيغ لبيسك )Cos a Sin b Tan (a b 2 2 Ln (a Cos 2 b) b 5 a Z )t g 3 2X 4 (X 2 3 ) X g Ln ( t u السؤال :6 اكت اليعاد و التاليه بفيغ لبيسك Cos 2 (X 0.3) (X Y) 3 ) e x 3 X Ln ( x Ln (2X 3) X 4 5X e X Z r السؤال :7 وحد بعد النقطه ( )Xo، Yoع اليستقيم a X + b Y + c = 0 عليا ا معادله اليسافه بي مستقيم ونقطه هي كالتالي aX o bYo c a 2 b2 d السؤال :8 اوحد ناتج طباعه الب نامج التالي : Print "D="D, S READ X1, X2, Y1, Y2 DATA 1, 3, -4, 2 )D = SQR ((X2 - X1) ^ 2 + (Y2 - Y1) ^ 2 )S = (Y2 - Y1) / (X2 - X1 PRINT "D="; D, "S="; S S= 3 D= 6.324555 , Solution :