Download the winning roulette system

THE WINNING ROULETTE SYSTEM
by http://www.webgoldminer.com/
Is it possible to earn money from online gambling? Are there any 100% sure
winning roulette systems? Are there actually people who make a living from gambling?
The three questions have a same answer – yes.
1. Choosing a better online casino.
Every online casino has a specific payout. An online casino payout is a number that
is calculated from monthly statistics usually by a third party auditing firm. The payout
value describes how much of the casino's monthly turnaround returns to players and how
much is kept by casino. It is calculated from actual casino software logs for all games
played in the casino during the past month. As all casino games are precisely balanced
from statistical viewpoint the payout dynamics comes from elsewhere and casinos with
highest payout ratios are more attractive to the players because players have better chance
to win. The payouts at the different online casinos vary from 95% to about 99%. For
example: an online casino with reported 98.5% payout implies that out of (hypothetical)
$1,000,000 that players wagered last month $985,000 was won back or otherwise taken by
the players, leaving the casino with only $15,000. So, one of the things that you always
must look for is the casino's payout. The bigger the better. The fair too, because there is
always a chance to be deceived from a casino with no declared payout.
2. Introduction to the Roulette game.
The Roulette is the most fair casino game (from the games that you play against the
casino of course). Why? Because of the bet payoffs, which are the same for all roulettes in
every casino and the efficient value – (chance to win the betting) x (payoff coefficient).
This efficient value in one slot game for example is much smaller (vary from 30% to 90%
according to the slot machine type) than the roulettes' (which vary from 92,1% to 94,7%).
As you know the roulette has 38 numbers – 0, 00, 1, 2, 3 … 35, 36.
The chance to win a betting is formed by the ratio – (count of the numbers you
have chosen as your bet) / 38. For example: You make a four-number bet (28, 29, 31, 32).
Your chance to win this betting is: 4 / 38 = 0,105 or 10,5%.
Payoff 2 to 1 means a payoff coefficient 3. For example: You make a column bet and
you put 100$ in chips on one of the three columns. If you win, you take your 100$ plus
200$ (because the payoff is 2 to 1). This makes 300$. The payoff coefficient forms from the
ratio – money after possible win / staked money or in this case: 300 / 100 = 3. You can
receive this coefficient in one other way too – simply replace in the payoff phrase "to" with
"+" (2 to 1 = 2 + 1 = 3).
And finally – what actually means "efficient value"? This is the probability to win
from the casino. For example: You come in the casino with 5000$. You play the whole day
and in the end your money are more, if the efficient value of the game you played is more
than 100%. The following formula describes this – (your start money) x [(efficient value of
the game you play) to the (played hours) power] = (your end money).
Here are all the roulette bets possibilities, chances to win, payoff coefficients and
efficient values:
N
1
2
3
4
5
6
7
8
Bet type
Straight bet
Split bet
Street bet
Corner bet
Five-Number bet
Six-Line bet
Dozen, Column bet
Red, Black, Even, Odd, Low, High bet
Chance to win
2,63 %
5,26 %
7,89 %
10,52 %
13,15 %
15,79 %
31,58 %
47,37 %
Payoff coeff.
36
18
12
9
7
6
3
2
Efficient value
94,7 %
94,7 %
94,7 %
94,7 %
92,1 %
94,7 %
94,7 %
94,7 %
May be you've noticed that the efficient values of all betting types are under 100%.
Does this means that you will always lose from the most fair casino game? Yes. Every
regular player that plays at the roulette for long time will have less money at the end.
What if I make a big straight bet and I win, I'll get ahead with a lot of money, won't I? Yes,
you will, but you can't win every day in such way. After some period of time, in which
you will lose little by little, you will reach your start money again. So, you can't make a
living in such way. The casino earn from the regular players. But not from all players.
And here comes the betting strategies, which help you win the "unbeatable roulette". But
first…
3. Choosing a betting type.
As you can see from the bets descriptions above, only the five-number bet efficient
value is different from the others (with 2,6% smaller). So one of the eight bet possibilities
fades out from the choice of "wanna be a winner" player. But the other seven bet types
have the same efficient value. So, the next thing, in which we compare these seven types is
the chance to win the betting. The bigger chance means that you'll need less start money
to fulfil your strategy. And the 8) betting type has the biggest chance to win the betting.
But there are six possible bets from this type. You can place money on red, black, even,
odd, low or high. The "winning order" comes here…
4. Introduction to the strategy.
Do you know, what is a geometric progression? Here is one example for those of
you who don’t know: The numbers 1, 2, 4, 8, 16, 32 are given. Can you guess which is the
next number? It's 64. The relation between the numbers is that every number from the
sequence is twice bigger from the previous. A sequence from numbers with any relation
valid for all numbers from the sequence is called progression. If you haven't understand
that good look here - http://www.mdx.ac.uk/WWW/STUDY/glonumar.htm#Progression.
The betting strategy rely on a simple geometric progression. Check the following
table:
Bet Number
1
2
3
4
5
6
7
8
9
1.
2.
3.
4.
5.
6.
7.
8.
9.
Stake ( $ )
1
2
4
8
16
32
64
128
256
Gain ( $ )
+1
+1
+1
+1
+1
+1
+1
+1
+1
This table describes the following thing:
You bet on "Red" 1$. If you win you get 2$, you're ahead with 1$. If you lose:
You bet on "Red" 2$. If you win you get 4$, you're ahead with 1$. If you lose:
You bet on "Red" 4$. If you win you get 8$, you're ahead with 1$. If you lose:
You bet on "Red" 8$. If you win you get 16$, you're ahead with 1$. If you lose:
You bet on "Red" 16$. If you win you get 32$, you're ahead with 1$. If you lose:
You bet on "Red" 32$. If you win you get 64$, you're ahead with 1$. If you lose:
You bet on "Red" 64$. If you win you get 128$, you're ahead with 1$. If you lose:
You bet on "Red" 128$. If you win you get 256$, you're ahead with 1$. If you lose:
You bet on "Red" 256$. If you win you get 512$, you're ahead with 1$.
So, now you ask yourself – what is the chance to have 9 times no red number?
And here comes the probability theory in help. The chance the ball to stop on a black
number, 0 or 00 is: 100% - (your chance to win the betting on "Red") = 100% - 47,37% =
52,63%. The first time you place a bet on "Red" the chance to lose is 52,63%. But the second
time this chance changes. Why? The "Independent Events" is one chapter of the
probability theory. Two events are said to be independent, if the result of the second event
is not affected by the result of the first event. If A and B are independent events, the
probability of both events occurring is the product of their individual probabilities. If you
can't
understand
this,
here
Bet Number
1
2
3
4
5
6
7
8
9
10
11
Chance to lose
52,63 %
27,69 %
14,57 %
7,67 %
4,03 %
2,12 %
1,11 %
0,58 %
0,30 %
0,16 %
0,08 %
you'll
find one very nice explanation http://regentsprep.org/Regents/Math/mutual/Lindep.htm. The following table is based upon the
probability theory and shows how the chance to lose changes with every next bet you
place on "Red":
This table is the answer to your question – the chance to have nine times in a row
no red number is 0,3%. This means that from 1000 times you've played with this system, 3
times you will lose and the other 997 you will win. 997 times you win 1$, this makes
(+997$) for you, and 3 times you lose 511$, this makes (-1533$) for you. Overall (-536$). So,
this shows that the system isn't a winning one… yet. But look what is the chance to lose 10
times in a row – 0,16%. This means that from 1000 times, you'll lose 1,6 times. This is the
same like: from 2000 times to lose 3 times. This gives you 1997$ - 3 x (511$) = 464$. The
system is now a winning one. And 464$ / 2000 = 0,25$ per one play time. And this money
will be more, if you can afford more bets. If you lose 0,08% of the time you play (this
means 11 same bets in a row), you'll get 0,6$ per one play time. But why you need to
afford paying the bets, when you can simply make spins without making a bet. And here
comes the system, which gives you the incredible 0,9$ per play time.
5. The winning system itself.
Get a sheet of paper and draw the following table on it.
Number Red
Black
Even
Odd
1 – 18
19 – 36
Make as much blank rows (in the table above they are 4) as you have space for (one
sheet of paper can have like 20 ~ 30 blank rows for example). Every time you spin the
roulette (doesn't matter if you've made a bet or not), you'll have to enter the winning
number in the column "Number" and then make a "X" mark (or some other mark of your
choice) in the columns, where this number takes part. For example:
Number Red
15
Black
X
Even
Odd
X
1 – 18
X
19 – 36
1 – 18
X
19 – 36
If the ball stops on 0 or 00 make a blank row.
Number Red
15
0
00
Black
X
Even
Odd
X
Now, follow this rules in order to execute the strategy correctly.
1) When you haven't any "X" in the same columns from the last 2 spins, make a free spin
(spin without a betting). For example:
Number Red
12
X
30
X
11
Black
Even
X
X
X
Odd
1 – 18
X
19 – 36
X
X
X
The last 2 spins the ball has stoped on 30 and 11 – you have no "X" in the same
columns and you should make a free spin.
2) When you have "X" in the same columns from the last 2 spins, look if there isn't "X" in
the same columns from the last 3 spins. If there isn't you should bet 1$ on the no-X
column (blank column), if there is look in the previous row for another "X" in this
column. The number of "X" marks in the same columns from the last 2 or more spins
defines your stake. For this later… Now look at the following example:
Number Red
35
12
X
Black
X
Even
X
Odd
X
1 – 18
X
19 – 36
X
27
7
X
X
X
X
X
X
The last 2 spins the ball has stoped on 27 and 7 – you have "X" in both "Red" and "Odd"
columns. You look at the previous row for a "X" mark in "Red" or "Odd" column. There
is "X" in "Red", but no "X" in "Odd". You look now at the previous row for a "X" mark
in "Red" column. There isn't any. So, in the last 3 spins the ball has been stoping on
"Red". Now you place your bet on "Black".
3) Your stake is defined by the number of consecutive "X" marks in the same columns
from your last spins.
Consecutive
"X"
2
3
4
5
6
7
8
9
10
Stake
1$
2$
4$
8$
16 $
32 $
64 $
128 $
256 $
Every next consecutive "X" mark doubles your stake.
I am sure that you haven't understand these three rules very good, but with the
following example you will.
6. Example for playing with this system on online casino roulette or how to make
380$ within eight hours.
The following sentences describe my first 30 spins. Enjoy!
You can find this example at http://www.webgoldminer.com/roulettestr.htm.