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FOM Name: Teacher: FOM, Period CW #61: Properties of Exponents Objective: 2020s will learn and practice the properties of exponents. Exponential Notation ο§ For any number π₯, π₯ 1 = π₯, and for any positive integer π > 1, π₯ π is by definition: (π₯ β π₯ β― π₯). π₯π = β ο§ The number π₯ is called π raised to the base of π₯ π . ο§ π₯ 2 is called the square of π₯, and π₯ 3 is its cube. π times π πth power, where π is the exponent of π₯ in π₯ π , and π₯ is the Based on the information above, determine the base and exponent of the following integers: 73 10β4 π₯6 Base: Base: Base: Base: Exponent: Exponent: Exponent: Exponent: Laws of Exponents RULE 1: EXPONENT PRODUCT RULE When multiplying terms with the same base, multiply the coefficients and add the exponents. In general, if π₯ is any number and π, π are positive integers, then π₯ π β π₯ π = π₯ π+π because (π₯ β― π₯) × β (π₯ β― π₯) = β (π₯ β― π₯) = π₯ π+π π₯π × π₯π = β π times π times π+π times RULE 2: EXPONENT QUOTIENT RULE When dividing terms with the same base, divide the coefficients and subtract the exponents. In general, if π₯ is nonzero and π, π are positive integers, then π₯π = π₯ πβπ π₯π π₯π¦ PRACTICE: Simplify the following using the Product and Quotient Exponent Rules: 22 + 24 π₯2 + π₯3 Answer: Answer: RULE 3: POWER OF A POWER RULE π¦π ÷ π¦ π§ 44 ÷ 42 Answer: Answer: Different Bases For any numbers π₯ and π¦, and positive integer π, For any number π₯ and any positive integers π and π, (π₯ π )π = π₯ ππ because because (π₯π¦)π = π₯ π π¦ π (π₯π¦)π = β (π₯π¦) β― (π₯π¦) (π₯ π )π = β (π₯ β π₯ β― π₯)π π times (π₯ β π₯ β― π₯) × β― × β (π₯ β π₯ β― π₯) =β β π times π times = π₯ ππ . π times (π₯ β π₯ β― π₯) β β (π¦ β π¦ β― π¦) =β π times π π π times =π₯ π¦ . π times RULE 4: ZERO EXPONENT RULE Negative Exponent Rule Any number raised to the zeroth power is equal to one. For any nonzero number π₯, and for any positive 1 integer π, we define π₯ βπ as π₯ π . Example: 40 = 1 and π₯ 0 = 1 Note that this definition of negative exponents says 1 π₯ β1 is just the reciprocal, π₯, of π₯. As a consequence of the definition, for a nonnegative π₯ and all integers π, we get π₯ βπ = 1 π₯π PRACTICE: Simplify the following using the various Exponent Rules: (43 )2 π¦0 Rule: Rule: Answer: Answer: ((β7)4 )8 Rule: Rule: Answer: 37 × 37 Rule: Answer: Answer: 53 58 Rule: (4π₯)2 4β2 Rule: Answer: 65 65 Rule: Answer: 26 × 2β5 Rule: Answer: (π9 )4 12β2 π₯ 0 × 572 Rule: Rule: Rule: Answer: Answer: Answer: Answer: (ππ )π (ππ₯ π )π¦ Rule: Rule: Answer: Answer: (β5)4 × 3β4 Rule: Rule: Answer: Answer: (6β9 )0 Rule: Rule: Answer: Answer: π¦9 π¦0 1 5β8 32 33 (β2)β8 (β2)β1 Rule: Rule: Answer: Answer: