Survey
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
Discovery of Subatomic Particles Chapter 3: Elements, Compounds, and the Periodic Table Earliest theories about atoms, such as Dalton’s atomic theory, imagined them to be indestructible. Experiments performed in the late 1800’s and early 1900’s showed atoms are composed of subatomic particles. Graded Set: p.100 #38, 76, 78, 90, 92, 94, 102 Bonus Set: p.100 #2, 7, 10, 13, 19, 22, 51, 75, 77, 85 2 Discovery of Electron Discovery of Proton JJ Thomson (1897) Detected using Mass Spectrometer Discovered negatively charged particles Electrons (e–) Electron removal resulted in an atom with a positive charge Mass is 1800 times heavier than electron Cathode Ray Tube Experiment: negatively charged particles moved from cathode (-) to anode (+) (read p.64-65) Youtube Proton (p) Positively charged particle 3 FYI 4 Discovery of Atomic Nucleus Rutherford’s Alpha Scattering Experiment Also known as: Gold Foil Experiment 5 Most alpha () particles (positively charged) passed right through gold A few deflected off at an angle (when they hit the tiny nucleus, also positively charged) Youtube 6 1 Discovery of Neutron Rutherford’s Nuclear Atom Discovered by Chadwick 1932 Nuclear mass always double the number of protons. Therefore, nucleus must contain must be another type of particle neutrons (1n) Demonstrated that nucleus: has almost all of mass in atom has a positive charge is very tiny, located at center of atom Where protons and neutrons are located Has same mass as proton Electrically neutral 7 Remember… 8 Atomic Structure Electrons (e–) Very low mass Occupy most of atom’s space Attraction between protons (p) and electrons (e–) holds electrons around nucleus Repulsion between electrons helps them spread out over volume of atom In a neutral atom, number of electrons must equal number of protons 9 Summary: Subatomic Particles 10 Atomic Notation Atomic number (Z) Nucleus (protons + neutrons) Number of protons that atom has in nucleus Unique to each type of element Mass number (A) Electrons Particle Mass (g) Electrical Charge Mass number = protons + neutrons Electron 9.10939 10–28 –1 1.67264 10–24 +1 0 1 e 1 1 1 H, 1 p 0 1 0n Proton Neutron 1.67495 10–24 Atomic Symbols Symbol Symbolized by A Z X Ex. What is the atomic symbol for helium? Z = 2, A = 4 11 4 2 He 12 2 Isotopes Example: What is the isotopic symbol for Uranium-235? Atoms of same element with different mass numbers Same number of protons Different number of neutrons Most elements are mixtures of 2 or more isotopes Chemically, isotopes behave alike e.g. Three isotopes of hydrogen (H) Hydrogen-1, Hydrogen-2, Hydrogen-3 Chemical symbol = U Mass number (A) = 235 Atomic number (Z ) = 92 235 92 U 13 Atomic Mass Units Learning Check: Uniform mass scale for atoms Symbol: amu or u Based on the most abundant isotope: carbon-12 1 atom of carbon-12 = 12 atomic mass units Fill in the blanks: symbol 60Co 81Br 65 29 Cu 206 82 Pb neutrons protons 14 electrons 33 27 27 46 35 35 36 29 29 124 82 82 15 Calculating Atomic Mass 16 Learning Check Generally, elements are mixtures of isotopes e.g. Hydrogen Isotope Mass % Abundance 1H 1.007825 u 99.985 2H 2.0140 u 0.015 Atomic mass Naturally occurring magnesium is a mixture of 3 isotopes; 78.99% of the atoms are 24Mg (atomic mass, 23.9850 u), 10.00% of 25Mg (atomic mass, 24.9858 u), and 11.01% of 26Mg (atomic mass, 25.9826 u). From these data calculate the average atomic mass of magnesium. 0.7899 x 23.9850 u = 18.95 u 24Mg Weighted average of masses of all stable isotopes of given element 0.1000 x 24.9858 u = 2.499 u 0.1101 x 25.9826 u = 2.861 u Total mass of avg = 24.31 u 25Mg Use isotopic abundances and masses 17 26Mg 18 3 Your Turn! A naturally occurring element consists of two isotopes. The data on the isotopes: isotope #1 68.5257 u 60.226% isotope #2 70.9429 u 39.774% Calculate the average atomic mass of this element. 0.60226 × 68.5257 u = 41.270 u 0.39774 × 70.9429 u = 28.217 u 69.487 u 19 4