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A team of dogs drags a 121 kg sled 1.72 km over a horizontal surface at a constant speed. The coeο¬cient of friction between the sled and the snow is 0.205. The acceleration of gravity is 9.8 m/s. Find the work done by the dogs. Answer in units of kJ. N F Ffr x mg πΉππ β friction force πΉ β pulling force Constant speed => acceleration equals 0. Newtonβs first law of motion: π₯: πΉ = πΉππ π¦: π = ππ Friction force equals πΉππ = ππ = πππ, π - coefficient of friction. Therefore: πΉ = πππ The work done by a constant force of magnitude F on a body that moves a displacement d in the direction of the force is the product: π = πΉπ = ππππ = 0.205 β 121 ππ β 9.81 Answer: 419 ππ½ π β 1720 π = 419 ππ½ π 2