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Word Problems, Syst. Of Equations 1. Find the value of B so that the system of equations is inconsistent (no solutions): 4x + 2y = 10 10x + By = 20 B=5 2. The cost of produce floor tile includes a fixed cost of $400 and a variable cost of $1.25 per tile. The company charges a setup fee of $300 and $2 per tile. How many tile must be sold before the company makes a profit? (134) Cost = set up + tile cost; Profit = setup fee + tile charge; breakeven is when cost = profit Cost = 400 + 1.25x, where x is the number of tile Profit = 300 + 2x need 400 + 1.25x = 300 + 2x; 100 = 0.75x, x = 100/0.75 = 133.3 tiles 3. The sum of twice one number plus a second number is 14. The first number minus the second number is 4. Find the numbers. 2n + m = 14, n – m = 4; From 2nd eq n = m + 4, put in 1st, 2(m+4) + m = 14 3m + 8 = 14, m = 2, n = 6 4. Find two numbers whose sum is 213 if one number is twice the other number. n +m = 213, 2n = m n + 2n = 213, 3n = 213, n = 71 n = 71, m = 142 5. Solve for x and y in terms of a, b, and c. Assume a, b, and c are all non-zero. ax + by = c 2ax – by = 2c Add two equations, and get 3ax = 3c, therefore, x = c/a substitute into 1st equation: a(c/a) + by = c, or c + by = c, y = 0 check; a(c/a) + b(0)= c OK, 2a(c/a) – b(0) = 2c or 2c = 2c OK. 6. Hilda invested part of her $25000 in savings bonds at 7% simple interest and the rest in stocks at 8% simple interest. If she receives $1900 a year in interest, how much did she invest in each account? Let B be the amount in bonds and S the amount in stocks S + B = 25,000, Interest = 1900 = 0.07B + 0.08 S From 1st equation, S = 25,000 – B, subst into 2nd: 1900 = 0.07B + 0.08(25,000 – B) = -0.01B + 2000, B = 100/0.01 = $10,000, S = $15,000 7. Tickets to a theatre cost $8 for students and $10 for nonstudents. They sold 390 tickets and made $3270. How many student tickets were sold? S = student tickets, N = non-student S+N=390, 8S + 10N = 3270. From 1st equation, N = 390-S. Subst into 2nd, 8S + 10(390-S) = 3270, -2S + 3900 = 3270, 2S = 630, S = 315 student tickets 8. The perimeter of a rectangular garden is 650 meters. If the length is 75 meters more than the width, what are the dimensions of the garden? P = 2L + 2W, L = W + 75. P = 2(W+75) + 2W = 4W + 150 = 650, 4W = 500, W =125m L = 200m 9. A baker wants to mix a 60% sugar solution with a 30% sugar solution to obtain 10 quarts of a 51% sugar solution. How much of the 30% solution will the baker use? Name 60% sol 30% sol 51% sol Amount x y 10 qt Concentration 60% 30% 51% Sugar 0.6x 0.3y 5.1 x + y = 10, 0.6x + 0.3y = 5.1 or 6x + 3y = 51 from 1st equation, x = 10-y; subst into 2nd: 6(10-y) + 3y = 51 or 60 -3y = 51; 3y = 9 or y = 3; needs 3 qt of 30% solution