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The Rational Matrices Keles H. Karadeniz Technical University, Faculity of Science, Department of Mathematics, Campus of Kanuni, Trabzon, TURKEY (Tel: +90462-377-2568; e-mail: [email protected]). Abstract: In this paper, we give the research about rational properties of two matrices with the same dimension. We will see that the properties here are analogous to the case in real numbers. This study is about their properties and some examples are given. Keywords: matrix, division, matrices division, rational matrices. , ∈ ℚℳ Proof. Let 1. INTRODUCTION Let with B ≠ 0 . Then the matrix A and B ∈ M ( ℝ ) + Let us start with the definition as follows. i is called the division of by and denoted by B n × n A B j ÷ or . The set of rational matrices are showen by ℚℳ = , ∈ ℳℝ, || ≠ 0 . The term rational in the set 1 ℚℳ = , ∈ ℳℝ, || ≠ 0 refers to the fact that a rational matrix represents a ratio of two matrices. The set of rational matrices is include by ℳℝ. A rational matrix is a matrix like , where , are matrices. If = 0 then this division is not defined. = 0 ∈ ℚℳ and = ∈ ℚℳ. Theorem 1. Let Proof. Let , = ! . ∈ ℚℳ . Then . "() # / + ' ( * ) % *() & % &÷% &= |$| ∈ ℚℳ . $ , $ . |$| -() +( || * ) . . "() # / + ' ( * ) % *() & = ||' + , |$| ∈ ℚℳ . Then |$| $ Theorem 2. Let ii. = . , ∈ ℚℳ, || ≠ 0. Then $ % & ÷ % & = % &% & . We can easily get + = ! Proof. Let . Sequare matrix of reel numbers is denoted with ℳℝ or ℳ. 1 , ! $ , ∈ ℚℳ. Then % & ÷ % & = || $ . = || . = || " + # $ $ Let , , ∈ ℳℝ, || ≠ 0. Then Lemma 2. Let 2. THE RATIONAL MATRICES % & ÷ % & = ||' + , Corollary 1. Let i. = || " + # = We will give the Lemma without proof[1]. Lemma 1. = || + || Example 1. $ $ , ∈ ℚℳ, || ≠ 0. $ 0 1 2 3 2 67 0 =4 5 3 4 5 = 4 54 5 . 1 1 Let = 4 1 3 2 0 1 2 3 5, = 4 1 1 2 5, 1 . =4 2 1 1 5 5 and > = 4 1 2 −1 =4 2 ⟹ $ . + * 5 =4 −1 =4 −1 1 4 54 5 = 4 $ 5 4 −1 Lemma 3. Let i. % & = ii. % & = . E . 7 5 3 0 −1 5, = 4 1 $ 1 $ −4 3 5⇒ =4 3 −1 4 5= −1 . + * −4 5 3 4 5, −1 3 −1 iii. If || ≠ 0 from Lemma 1. 4 −1 54 −1 2 4 5, −1 0 5= 1 iii. B ∈ ℚℳ, ∈ ℳℝ. Then n a C (B) ⋯ sk k1 ∑ k =1 ⋮ ⋮ n ∑ ask Ck 1 ( B ) ⋯ k =1 $ $ I A i B + 0 = ,0 + . = n ∑ ask ckn Cs 1 ( B ) k =1 ⋮ n n ∑ ∑ ask ck 1 Csn ( B ) s=1 k =1 For $ I J . . ∑a sk j A= 1 A B B % &% & = 1 j B 2 A B i j = A 2 B . $ + %*& . n A = 1 Ai n ? n B j B B Example 2. Let = 4 Ck 1 ( B ) [ i ]A = ∈ ℚℳ. Then ∈ ℚℳ and K ∈ ℤ! . Is then c11 ⋯ c1n k =1 ⋮ ⋮ ⋮ ⋮ n c ⋯ c nn ∑ ask Ck1 ( B ) n1 k =1 n , $ ii. If = from i) B J Fig. 1. Matrix A. + ∈ ℚℳ. Then +% + &=% + &+ A C B B = = () $ = 4 5 . 4 5. = A= + Lemma 4. Let n n a c C ( B) ⋯ ∑ sk k 1 s1 ∑ s=1 k =1 ⋮ ⋮ n n ∑ ∑ ask ck 1 Csn ( B ) ⋯ s=1 k =1 A , , I $ J iv. %& % $ & is rational matrix. Proof. If = F( , = G( and = H( then AC i. Let us the following lemma without proof. iii. If || ≠ 0, also i. Theorem 3. Let ii. . = || = || || = 4 5 . 4 5 . 2 1 1 1 5, = 4 1 1 0 5 and K = 2. 1 Fig. 4. Matrix A 2 B 2 . then 2 A ≠ A . B B2 2 Note. In general, for rational matrices we will get, n A ≠ A . B Bn Fig. 2. Matrix B. Then 2 =M1 1 1 O 3 % & =4 −2 0 1 0 1 1 1 N = 4 2 15 2 1 1 −1 0 1 1 1 E 2 5 3 5 and E = 4 5, 1 −7 −4 ii. %& 6 6Q = = , ∈ ℚℳ and K, P ∈ ℤ! , then Theorem 4. If i. %& n $ . - . Q 6 Q = R% & S = % & . Proof. i. For the proof see paper [Keleş, H. ( 2011)]. ii. It is see clearly. Theorem 5. Let , $ ∈ ℚℝ . Then . "() # / + ' ( * ) % *() & % & ÷ % & = ||' + , Proof. If Fig. 3. Matrix () A 2 . , $ $ ∈ ℚℝ . |$| $ . |$| -() % & ÷ % & = || +( * ) . . "() # / + ( ' * ) % *() & = ||' + , |$| . B REFERENCES Keleş, H. ( 2011). Matrix Division. International Association of Engineers (IAENG. London. U.K. ). Keleş, H. ( 2008). Lineer Cebire Giriş. Akademi Yayınevi. Trabzon.Turkey. 2008. Bolian, L. and Hong-Jian L. ., ( 2000). Matrices in Combinatorics and Graph Theory. Kluwer Academic Publishers. The Netherlands.