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Chapter 9 – Circles 9.1 Answer Key Parts of Circles Answers 1. diameter 2. secant 3. chord 4. point of tangency 5. common external tangent 6. common internal tangent 7. the center 8. radius 9. The diameter is the longest chord in any circle. 10. ʘB: 4 units, ʘC: 5 units, D: 2 units, .ʘE: 2 11. ʘD ≅ ʘE because they have the same radius length. 12. They will have 2 common external tangents and no common internal tangents. 13. CE = Radius of ʘE + Radius of ʘC = 5 + 2 = 7 14. y=x−2 CK-12 Basic Geometry Concepts 1 Chapter 9 – Circles 9.2 Answer Key Tangent Lines Answers 1. Yes 2. No 3. Yes 4. 𝑥 = 4√10 5. 𝑥 = 4√11 6. x=9 7. x=3 8. x=5 9. 𝑥 = 8√2 10. Yes, by AA. 𝑚∠𝐶𝐴𝐸 = 𝑚∠𝐷𝐵𝐸 = 90° and ∠𝐴𝐸𝐶 ≅ ∠𝐵𝐸𝐷 by vertical angles. 11. CE = 25 12. BE = 12 13. DE = 15 14. BC = 37, AD = 35 15. 32 units 16. BH = BD and DF = FH. So, BDFH is a kite because adjacent sides are congruent. 17. If the radius of the circle is 5, then the length of each side of the square is 10. The perimeter would be 4 ∙ 10 = 40. 18. No, because the opposite sides are congruent and at most a circle can touch three sides. For a circle to be inscribe in any shape, it needs to touch all the sides of that shape. 19. Answers will vary. 20. Answers will vary. CK-12 Basic Geometry Concepts 2 Answer Key Chapter 9 – Circles 21. Statement ̅̅̅̅ ̅̅̅̅ 1. 𝐴𝐵 and 𝐶𝐵 with points of tangency at A and C. ̅̅̅̅ 𝐴𝐷 and ̅̅̅̅ 𝐷𝐶 are radii. ̅̅̅̅ ≅ 𝐷𝐶 ̅̅̅̅ 2. 𝐴𝐷 3. ̅̅̅̅ 𝐷𝐴 ⊥ ̅̅̅̅ 𝐴𝐵 and ̅̅̅̅ 𝐷𝐶 ⊥ ̅̅̅̅ 𝐶𝐵 4. 𝑚∠𝐵𝐴𝐷 = 90° and 𝑚∠𝐵𝐶𝐷 = 90° ̅̅̅̅. 5. Draw 𝐵𝐷 6. ∆𝐴𝐷𝐵 and ∆𝐷𝐶𝐵 are right triangles 7. ̅̅̅̅ 𝐷𝐵 ≅ ̅̅̅̅ 𝐷𝐵 8. ∆𝐴𝐵𝐷 ≅ ∆𝐶𝐵𝐷 ̅̅̅̅ ≅ 𝐶𝐵 ̅̅̅̅ 9. 𝐴𝐵 22. 23. Reason Given All radii are congruent. Tangent to a Circle Theorem Definition of perpendicular lines Connecting two existing points Definition of right triangles (Step 4) Reflexive PoC HL CPCTC a) ABCD is a kite. b) The line that connects the center and the external point B bisects ABC. ̅̅̅̅ ≅ 𝐵𝑇 ̅̅̅̅ by the Two Tangents Theorem and the transitive property. ̅̅̅̅ ≅ 𝐶𝑇 𝐴𝑇 CK-12 Basic Geometry Concepts 3 Chapter 9 – Circles 9.3 Answer Key Arcs in Circles Answers 1. minor arc 2. major arc 3. semicircle 4. major arc 5. minor arc 6. semicircle 7. Yes, CD DE because their corresponding central angles are congruent. 8. mCD 66 9. mCAE 228 10. 100, 260 11. 175, 185 12. 38, 322 13. 109, 251 14. 124, 236 15. 34, 326 16. Yes, they are in the same circle with equal central angles. 17. Yes, the central angles are vertical angles and they are equal, which means the arcs equal. 18. No, we don’t know the measure of the corresponding central angles. 19. 90 20. 49 21. 82 22. 16 CK-12 Basic Geometry Concepts 4 Chapter 9 – Circles 23. 188 24. 172 25. 196 26. 270 27. x = 54 28. x = 47 29. x = 25 CK-12 Basic Geometry Concepts Answer Key 5 Chapter 9 – Circles 9.4 Answer Key Chords in Circles Answers 1. ̅̅̅̅ ≅ 𝐷𝐹 ̅̅̅̅ 𝐴𝐶 2. AC ≅ DF 3. DJ ≅ JF 4. ̅̅̅̅ 𝐷𝐸 ≅ ̅̅̅ 𝐸𝐽 5. AGH ≅ HGC 6. DGF ≅ AGC 7. Possible Answers ̅̅̅̅ 𝐴𝐺 , ̅̅̅̅ 𝐻𝐺 , ̅̅̅̅ 𝐶𝐺 , ̅̅̅̅ 𝐹𝐺 , ̅̅̅ 𝐽𝐺 , ̅̅̅̅ 𝐷𝐺 8. 107 9. 8 10. 118 11. 133 12. 140 13. 120 14. x = 64, y = 4 15. x = 8, y = 10 16. x ≈ 15.3, y ≈ 12.3 17. x ≈ 18.36 18. x = 9, y = 6 19. x = 4.5 20. x=3 21. x=7 22. x ≈ 6.63 23. 121.3 CK-12 Basic Geometry Concepts 6 Chapter 9 – Circles 24. 112.9 25. ̅̅̅̅ 𝐵𝐹 ≅ ̅̅̅̅ 𝐹𝐷 and BF FD by Chord Theorem #3. 26. ̅̅̅̅ 𝐶𝐴 ≅ ̅̅̅̅ 𝐴𝐹 by Chord Theorem #4. 27. ̅̅̅̅ is a diameter by Chord Theorem #2. 𝑄𝑆 CK-12 Basic Geometry Concepts Answer Key 7 Answer Key Chapter 9 – Circles 9.5 Inscribed Angles in Circles Answers 1. semicircle 2. congruent 3. chords 4. J L 1 2 𝑚∠𝐽𝐾𝐿 = 𝑚∠𝐽𝑀𝐿 M K 5. 51 6. 46 7. x = 180, y = 21 8. x = 60, y = 49 9. x = 30, y = 60 10. 37 11. 42 12. 6 13. 10 CK-12 Basic Geometry Concepts 8 Answer Key Chapter 9 – Circles 14. Statement 1. Inscribed ABC and diameter ̅̅̅̅ 𝐵𝐷 mABE = x and mCBE = y 2. x + y = mABC 3. ̅̅̅̅ 𝐴𝐸 ≅ ̅̅̅̅ 𝐸𝐵 and ̅̅̅̅ 𝐸𝐵 ≅ ̅̅̅̅ 𝐸𝐶 4. ∆𝐴𝐸𝐵 and ∆𝐸𝐵𝐶 are isosceles 5. mEAB = x and mECB = y 6. mAED = 2x and mCED = 2y Reason Given 8. mAD mDC mAC Angle Addition Postulate All radii are congruent Definition of an isosceles triangle Isosceles Triangle Theorem Exterior Angle Theorem The measure of an arc is the same as its central angle. Arc Addition Postulate 9. mAC = 2x + 2y Substitution 10. mAC = 2(𝑥° + 𝑦°) Distributive PoE 11. mAC = 2mABC Subsitution 7. mAD = 2x and mDC = 2y 1 12. 𝑚∠𝐴𝐵𝐶 = 2 𝑚 AC CK-12 Basic Geometry Concepts Division PoE 9 Chapter 9 – Circles 9.6 Answer Key Inscribed Quadrilaterals in Circles Answers 1. inscribed 2. opposite, supplementary 3. 48 4. 120 5. 54 6. 45 7. 87 8. 27 9. x = 200, y = 100 10. x = 68, y = 99 11. x = 93, y = 97 12. x = 24 13. x = 35 CK-12 Basic Geometry Concepts 10 Answer Key Chapter 9 – Circles 9.7 Angles On and Inside a Circle Answers 1. x = 103 2. x = 100 3. x = 38 4. x = 216 5. x = 66 6. x = 113 7. x = 60, y = 40 8. Statement 1. Intersecting chords ̅̅̅̅ 𝐴𝐶 and ̅̅̅̅ 𝐵𝐷. ̅̅̅̅ 2. Draw 𝐵𝐶 A D Reason Given Construction B a° C 3. 𝑚∠𝐷𝐵𝐶 1 ̂ = 2 𝑚𝐷𝐶 1 ̂ = 2 𝑚𝐴𝐵 4. 𝑚∠𝐴𝐶𝐵 5. 𝑚∠𝑎 = 𝑚∠𝐷𝐵𝐶 + 𝑚∠𝐴𝐶𝐵 1 ̂ + 1 𝑚𝐴𝐵 ̂ 6. 𝑚∠𝑎 = 2 𝑚𝐷𝐶 2 9. inside, intercepted 10. on, half CK-12 Basic Geometry Concepts Inscribed Angle Theorem Inscribed Angle Theorem Exterior Angle Theorem Substitution 11 Answer Key Chapter 9 – Circles 9.8 Angles Outside a Circle Answers 1. x = 63, y = 243 2. x = 42 3. x = 150 4. x = 70 5. x = 152 6. x = 180, y = z = 45 7. x = 180, y = 60 8. x = 27 9. x = 5 10. Statement 1. Intersecting secants ⃗⃗⃗⃗⃗ 𝐴𝐵 and ⃗⃗⃗⃗⃗ 𝐴𝐶 . ̅̅̅̅ 2. Draw 𝐵𝐸 . B D a° Reason Given Construction A E 3. C 1 ̂ 𝑚∠𝐵𝐸𝐶 = 2 𝑚𝐵𝐶 1 ̂ 𝑚∠𝐷𝐵𝐸 = 2 𝑚𝐷𝐸 4. 5. 𝑚∠𝑎 + 𝑚∠𝐷𝐵𝐸 = 𝑚∠𝐵𝐸𝐶 6. 𝑚∠𝑎 = 𝑚∠𝐵𝐸𝐶 − 𝑚∠𝐷𝐵𝐸 1 ̂ − 1 𝑚𝐷𝐸 ̂ 7. 𝑚∠𝑎 = 2 𝑚𝐵𝐶 2 1 ̂ − 𝑚𝐷𝐸 ̂) 8. 𝑚∠𝑎 = (𝑚𝐵𝐶 2 CK-12 Basic Geometry Concepts Inscribed Angle Theorem Inscribed Angle Theorem Exterior Angle Theorem Subtraction PoE Substitution Distributive Property 12 Answer Key Chapter 9 – Circles 9.9 Segments from Chords Answers 1. 102, x = 5 2. 5, 10, x = 2 3. x = 7.5 4. x = 6√2 5. x = 10 6. x = 10 7. x=9 8. x=4 9. 10 inches 10. Statement ̅̅̅̅ and ̅̅̅̅ 1. Intersecting chords 𝐴𝐶 𝐵𝐸 with segments a, b, c, and d. 2. ∠𝐴𝐸𝐷 ≅ ∠𝐵𝐶𝐷 ∠𝐸𝐴𝐷 ≅ ∠𝐶𝐵𝐷 3. ∆𝐴𝐷𝐸~∆𝐵𝐷𝐶 𝑎 𝑑 4. 𝑐 = 𝑏 5. 𝑎𝑏 = 𝑐𝑑 CK-12 Basic Geometry Concepts Reason Given Theorem 9-8 AA Similarity Postulate Corresponding parts of similar triangles are proportional Cross multiplication 13 Answer Key Chapter 9 – Circles 9.10 Segments from Secants Answers 1. 3 + x, x = 3 2. 20, 8 + 7, x = 6 3. x = 11 4. x ≈ 17.14 5. x=6 6. Statement ̅̅̅̅ and 𝑅𝑇 ̅̅̅̅ with segments a, b, 1. Secants 𝑃𝑅 c, and d. 2. ∠𝑅 ≅ ∠𝑅 3. ∠𝑄𝑃𝑆 ≅ ∠𝑆𝑇𝑄 4. ∆𝑅𝑃𝑆~∆𝑅𝑇𝑄 𝑎 𝑐 5. = 𝑐+𝑑 𝑎+𝑏 6. 𝑎(𝑎 + 𝑏) = 𝑐(𝑐 + 𝑑) 7. z=7 8. x = 11 9. m = 13.75 10. n=3 11. s=7 12. x = 16 13. x = 4. 6 14. x ≈ 12.25 15. x = 14 CK-12 Basic Geometry Concepts Reason given Reflexive PoC Theorem 9-8 AA Similarity Postulate Corresponding parts of similar triangles are proportional Cross multiplication 14 Chapter 9 – Circles 9.11 Answer Key Segments from Secants and Tangents Answers 1. x + 15, x = 5 2. x=6 3. x = 4√42 4. x = 10 5. The error is in the set up. It should be10 ∙ 10 = 𝑦 ∙ (15 + 𝑦). The correct answer is y = 5. 6. 2.2 7. 3 8. 12 9. 2. 6 10. 1 11. 3 12. ≈ 4.9 13. 5.5 14. 15. 36 15. 6 CK-12 Basic Geometry Concepts 15 Chapter 9 – Circles 9.12 Answer Key Circles in the Coordinate Plane Answers 1. center: (-5, 3), radius = 4 2. center: (0, -8), radius = 2 3. center: (7, 10), radius = 2√5 4. center: (-2, 0), radius = 2√2 5. (𝑥 − 4)2 + (𝑦 + 2)2 = 16 6. (𝑥 + 1)2 + (𝑦 − 2)2 = 7 7. (𝑥 − 2)2 + (𝑦 − 2)2 = 4 8. (𝑥 + 4)2 + (𝑦 + 3)2 = 25 9. yes 10. no 11. yes 12. yes 13. (𝑥 − 2)2 + (𝑦 − 3)2 = 52 14. (𝑥 − 10)2 + 𝑦 2 = 29 15. (𝑥 + 3)2 + (𝑦 − 8)2 = 200 16. (𝑥 − 6)2 + (𝑦 + 6)2 = 325 CK-12 Basic Geometry Concepts 16