Download A-level Human Biology Mark scheme Unit 02 - Humans - their

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A-LEVEL
Human Biology
HBIO2
Mark scheme
2405
June 2016
Version: 1.0 Final
Mark schemes are prepared by the Lead Assessment Writer and considered, together with the
relevant questions, by a panel of subject teachers. This mark scheme includes any amendments
made at the standardisation events which all associates participate in and is the scheme which was
used by them in this examination. The standardisation process ensures that the mark scheme covers
the students’ responses to questions and that every associate understands and applies it in the same
correct way. As preparation for standardisation each associate analyses a number of students’
scripts: alternative answers not already covered by the mark scheme are discussed and legislated for.
If, after the standardisation process, associates encounter unusual answers which have not been
raised they are required to refer these to the Lead Assessment Writer.
It must be stressed that a mark scheme is a working document, in many cases further developed and
expanded on the basis of students’ reactions to a particular paper. Assumptions about future mark
schemes on the basis of one year’s document should be avoided; whilst the guiding principles of
assessment remain constant, details will change, depending on the content of a particular
examination paper.
Further copies of this Mark Scheme are available from aqa.org.uk
Copyright © 2016 AQA and its licensors. All rights reserved.
AQA retains the copyright on all its publications. However, registered schools/colleges for AQA are permitted to copy material from this
booklet for their own internal use, with the following important exception: AQA cannot give permission to schools/colleges to photocopy any
material that is acknowledged to a third party even for internal use within the school/college.
2
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
Additional
Comments/Guidance
Answers
Mark
1(a)
Centromere;
1
1(b)
They are alleles (of the gene);
Accept they have a different base
sequence/mutation.
1
1(c)(i)
There are (four) chromatids /
(each) chromosome consists of
two chromatids;
Accept there are four
chromosomes
1
1(c)(ii)
(Each new copy/DNA molecule)
consists of one new and one
original/old/template strand;
Accept each strand is a template
(for new DNA strands)
1
Total
4
3
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
Answers
2(a)
(a group of similar organisms
that) can reproduce to give fertile
offspring;
2(b)
Organisms cannot
interbreed/reproduce with another
group;
Additional
Comments/Guidance
Mark
1
Reject any reference to
inbreeding
1
Accept examples that cause
reproductive isolation, e.g.
organisms cannot interbreed due
to physical differences.
2(c)
1. Predation;
2. Disease;
3. Competition;
Accept suitable examples for
each
2 max
Accept (sudden) environmental
change/suitable named example
2(d)
Mutation/change in base
sequence (of allele);
2(e)
More red blood
cells/haemoglobin;
Accept suitable named mutation
1
1
Total
6
4
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
Additional
Comments/Guidance
Answers
Mark
3(a)(i)
Homo;
Reject ‘Homo sapiens’
1
3(a)(ii)
(Homo) habilis/(Homo)
erectus/(Homo) neanderthalensis;
Ignore ‘neanderthal’
1
Accept (Homo) neanderthalis
3(b)(i)
(tools in Group A) have not been
shaped (as much)/sharpened;
Accept clear converse for group B
tools.
3(b)(ii)
1. Chipped against other
stones/used one stone as a
hammer (to hit another stone);
2. Making sharp flakes;
3. Used bones to sharpen
edges;
MP 1 & 2 - Accept knapping of
flints
3(b)(iii)
Accept one suitable example of
use, e.g.
1
2 max
1 max
1. To cut/scrape meat (off
bones)/cleaver;
2. For hand-axes/spearheads;
3. Killing animals;
Total
6
5
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
4(a)
4(b)(i)
Additional
Comments/Guidance
Answers
1. Deoxyribose;
2. Phosphate/PO43-;
AUGAAU;
Mark
2
2. Reject phosphorus/P
2. Accept Pi
Ignore reference to bases
If read from the right accept
GUUCAU
1
Ignore bases after first 6
4(b)(ii)
4(c)
5;
1
1. Different genes;
2. Different (DNA) base
sequences;
2
OR
3. Mutations;
4. Cause differential
survival/selective advantage;
Total
6
6
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
Additional
Comments/Guidance
Answers
Mark
5(a)(i)
Metaphase;
1
5(a)(ii)
4.8 hours/4 hours 48 minutes/288
minutes;;
Allow one mark for 68 x 24
340
2
5(b)
DNA replication;
Accept synthesis of protein/of
ATP/of cytoplasm/of organelles.
1
5(c)
1. To attach to
centromeres/chromosomes /
align chromosome along the
equator;
2. To pull
chromatids/chromosomes
apart/to opposite poles/ends
(of the cell);
2
Total
6
7
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
Answers
6(a)
1. To allow comparison between
the groups/male and female;
2. As there may have been
different numbers in each
group/different numbers of
male and female;
6(b)
Factor:
Additional
Comments/Guidance
1. Accept allows comparison with
non-overweight people.
1. Neutral easier to compare
1. Ignore unqualified comparisons
Mark
2
2
Waist-to-hip ratio;
Explanation:
It shows the highest relative risk
in both males and females;
6(c) (i)
Men at a (significantly) higher
risk;
6(c) (ii)
1. Increased (relative) risk in all
categories;
2. Sample size unknown;
3. (however,) other factors can
cause colon cancer / (table
shows) risk (which) is not a
certainty;
1
Accept no SD values, so do not
know if differences between
overweight and non-overweight
people are real.
Total
3
8
8
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
7(a)
Answers
Statement
7ai
7aii
7aiii
;;;
Additional Comments/Guidance
Mark
3
Number from
Figure X
4
2
3
7(b) (i)
1. Aortic body;
2. Carotid body/sinus;
3. Medulla;
1. Neutral aorta.
2. Neutral carotid artery.
2
max
7(b) (ii)
1. Lack of oxygen increases
anaerobic respiration/
production of blood lactate;
2. (Chemoreceptors) detect fall
in pH;
3. Send increased frequency of
impulses to respiratory centre;
4. Increased frequency of
impulses to
intercostals/diaphragm;
Accept hypoxia / low pO2 detected
by carotid bodies for MP1 and 2.
3
max
3 & 4 Reject
signals/messages/information.
3 & 4 Must have idea of
increase/more.
Total
8
9
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Additional
Comments/Guidance
Question
Answers
8(a)
Letter Q placed on or near where
larvae penetrate the skin;
1
8(b)
1. Travel up the
airways/trachea / coughed up
(to the pharynx/throat);
2. (And) are swallowed/move
down oesophagus;
2
8(c)
1. (Put sample on slide and)
use microscope;
2. (to) look for eggs;
2
8(d) (i)
Attaching to (host) small
intestine;
1
8(d) (ii)
The hookworm feeds on the
hosts blood;
Accept the hookworm attached
with hooks which damages the
lining of the small intestine
Mark
1
Q Reject feeds ‘off’ the hosts
blood
8(d) (iii)
Increased chance that eggs will
survive / infect new human / to
allow eggs to reach new hosts /
more chance of completing life
cycle;
1
Total
8
10
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
9 (a) (i)
9 (a) (ii)
Additional
Comments/Guidance
Answers
1. As the farm size increases,
the number of species of
butterflies decreases;
2. Due to fewer plant
species/types of plant for
them to feed on / less variety
of food sources;
2. Ignore less food for butterflies.
1.78:1;
Accept 1.8:1 or 1. 7̇: 1
Mark
2
1
Reject 1.7:1
9 (a) (iii)
Yes (no mark)
1. Small farms do have more
species;
2. No overlap of SDs between
small and large farms (so)
differences are
significant/real;
2 max
2. Accept suitable use of data
No (no mark)
3. No idea of numbers of each
species;
4. Accept suitable economic
argument, e.g. government
money could be better spent
elsewhere;
5. May not be true in countries
other than Italy
9 (b) (i)
Negative correlation/description;
Accept (they are) inversely
proportional /description of
inverse proportionality.
11
1
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
9 (b) (ii)
Additional
Comments/Guidance
Answers
1. To reduce the number of
species;
2. Which might compete with
their crop/the hay in the
meadow;
Mark
2 max
OR
3. To get more hay/increase
yield of hay;
4. Frequent cutting stimulates
growth;
OR
5. To get more hay/increase
yield of hay;
6. To feed animals (and make
more profit);
Total
8
12
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
10 (a)
10 (b)
Additional
Comments/Guidance
Answers
1. (Determine) the base
sequence (of genes/and look
for similarities/differences);
1. Immunological;
2. Anatomical;
Mark
1
Accept fossil evidence/examples
of fossil evidence for one mark
2
Neutral behavioural and
embryological
10 (c) (i)
Blocks/absorbs/dissipates UV
(light) / lower risk of
mutation/(skin) cancer/burning;
1
10 (c) (ii)
1. The sun is weaker/less UV
(light) (in more northern
latitudes);
2. (Lighter skin means) more UV
(light) can be absorbed;
3. To make more vitamin D;
3
10 (c) (iii)
10 (d)
1. Enough vitamin D from
diet/fish;
2.and 3. Reject ideas relating to
absorbing vitamin D from sunlight
Accept (in summer) high levels of
UV are reflected by snow, (dark
skin) protects them (from this
reflected light);
The results of preference/(sexual)
attraction (when choosing mating
partner);
1
1
13
MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016
Question
Answers
Additional
Comments/Guidance
10 (e) (i)
1. More food/more regular food
supply/food sources;
2. Can store food in times of
plenty/for times of
shortages/in winter
3. Do not have to move to new
areas to find food / follow
animals;
4. Larger
populations/communities
form/settle / increased
reproduction;
5. Develop social
structures/different
roles/specialists
6. Develop the use of tools/skills;
7. Allow development of
culture/trade;
10 (e) (ii)
1.
Relevant reference to
small population size;
2.
Relevant reference to
inbreeding/gene flow;
10 (e) (iii)
1. Small samples might not be
reliable/representative (of all
(European humans);
2. Trend not followed with
Greenlanders/humans living
coastal regions;
3. Does not show that evolution
is happening now;
4. No fossils/skeletons showing
transitions between dark and
light/changes in pigmentation
mentioned/hair/skin/eyes;
Mark
6 max
2
Total
3 max
20
14