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A-LEVEL Human Biology HBIO2 Mark scheme 2405 June 2016 Version: 1.0 Final Mark schemes are prepared by the Lead Assessment Writer and considered, together with the relevant questions, by a panel of subject teachers. This mark scheme includes any amendments made at the standardisation events which all associates participate in and is the scheme which was used by them in this examination. The standardisation process ensures that the mark scheme covers the students’ responses to questions and that every associate understands and applies it in the same correct way. As preparation for standardisation each associate analyses a number of students’ scripts: alternative answers not already covered by the mark scheme are discussed and legislated for. If, after the standardisation process, associates encounter unusual answers which have not been raised they are required to refer these to the Lead Assessment Writer. It must be stressed that a mark scheme is a working document, in many cases further developed and expanded on the basis of students’ reactions to a particular paper. Assumptions about future mark schemes on the basis of one year’s document should be avoided; whilst the guiding principles of assessment remain constant, details will change, depending on the content of a particular examination paper. Further copies of this Mark Scheme are available from aqa.org.uk Copyright © 2016 AQA and its licensors. All rights reserved. AQA retains the copyright on all its publications. However, registered schools/colleges for AQA are permitted to copy material from this booklet for their own internal use, with the following important exception: AQA cannot give permission to schools/colleges to photocopy any material that is acknowledged to a third party even for internal use within the school/college. 2 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question Additional Comments/Guidance Answers Mark 1(a) Centromere; 1 1(b) They are alleles (of the gene); Accept they have a different base sequence/mutation. 1 1(c)(i) There are (four) chromatids / (each) chromosome consists of two chromatids; Accept there are four chromosomes 1 1(c)(ii) (Each new copy/DNA molecule) consists of one new and one original/old/template strand; Accept each strand is a template (for new DNA strands) 1 Total 4 3 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question Answers 2(a) (a group of similar organisms that) can reproduce to give fertile offspring; 2(b) Organisms cannot interbreed/reproduce with another group; Additional Comments/Guidance Mark 1 Reject any reference to inbreeding 1 Accept examples that cause reproductive isolation, e.g. organisms cannot interbreed due to physical differences. 2(c) 1. Predation; 2. Disease; 3. Competition; Accept suitable examples for each 2 max Accept (sudden) environmental change/suitable named example 2(d) Mutation/change in base sequence (of allele); 2(e) More red blood cells/haemoglobin; Accept suitable named mutation 1 1 Total 6 4 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question Additional Comments/Guidance Answers Mark 3(a)(i) Homo; Reject ‘Homo sapiens’ 1 3(a)(ii) (Homo) habilis/(Homo) erectus/(Homo) neanderthalensis; Ignore ‘neanderthal’ 1 Accept (Homo) neanderthalis 3(b)(i) (tools in Group A) have not been shaped (as much)/sharpened; Accept clear converse for group B tools. 3(b)(ii) 1. Chipped against other stones/used one stone as a hammer (to hit another stone); 2. Making sharp flakes; 3. Used bones to sharpen edges; MP 1 & 2 - Accept knapping of flints 3(b)(iii) Accept one suitable example of use, e.g. 1 2 max 1 max 1. To cut/scrape meat (off bones)/cleaver; 2. For hand-axes/spearheads; 3. Killing animals; Total 6 5 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question 4(a) 4(b)(i) Additional Comments/Guidance Answers 1. Deoxyribose; 2. Phosphate/PO43-; AUGAAU; Mark 2 2. Reject phosphorus/P 2. Accept Pi Ignore reference to bases If read from the right accept GUUCAU 1 Ignore bases after first 6 4(b)(ii) 4(c) 5; 1 1. Different genes; 2. Different (DNA) base sequences; 2 OR 3. Mutations; 4. Cause differential survival/selective advantage; Total 6 6 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question Additional Comments/Guidance Answers Mark 5(a)(i) Metaphase; 1 5(a)(ii) 4.8 hours/4 hours 48 minutes/288 minutes;; Allow one mark for 68 x 24 340 2 5(b) DNA replication; Accept synthesis of protein/of ATP/of cytoplasm/of organelles. 1 5(c) 1. To attach to centromeres/chromosomes / align chromosome along the equator; 2. To pull chromatids/chromosomes apart/to opposite poles/ends (of the cell); 2 Total 6 7 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question Answers 6(a) 1. To allow comparison between the groups/male and female; 2. As there may have been different numbers in each group/different numbers of male and female; 6(b) Factor: Additional Comments/Guidance 1. Accept allows comparison with non-overweight people. 1. Neutral easier to compare 1. Ignore unqualified comparisons Mark 2 2 Waist-to-hip ratio; Explanation: It shows the highest relative risk in both males and females; 6(c) (i) Men at a (significantly) higher risk; 6(c) (ii) 1. Increased (relative) risk in all categories; 2. Sample size unknown; 3. (however,) other factors can cause colon cancer / (table shows) risk (which) is not a certainty; 1 Accept no SD values, so do not know if differences between overweight and non-overweight people are real. Total 3 8 8 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question 7(a) Answers Statement 7ai 7aii 7aiii ;;; Additional Comments/Guidance Mark 3 Number from Figure X 4 2 3 7(b) (i) 1. Aortic body; 2. Carotid body/sinus; 3. Medulla; 1. Neutral aorta. 2. Neutral carotid artery. 2 max 7(b) (ii) 1. Lack of oxygen increases anaerobic respiration/ production of blood lactate; 2. (Chemoreceptors) detect fall in pH; 3. Send increased frequency of impulses to respiratory centre; 4. Increased frequency of impulses to intercostals/diaphragm; Accept hypoxia / low pO2 detected by carotid bodies for MP1 and 2. 3 max 3 & 4 Reject signals/messages/information. 3 & 4 Must have idea of increase/more. Total 8 9 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Additional Comments/Guidance Question Answers 8(a) Letter Q placed on or near where larvae penetrate the skin; 1 8(b) 1. Travel up the airways/trachea / coughed up (to the pharynx/throat); 2. (And) are swallowed/move down oesophagus; 2 8(c) 1. (Put sample on slide and) use microscope; 2. (to) look for eggs; 2 8(d) (i) Attaching to (host) small intestine; 1 8(d) (ii) The hookworm feeds on the hosts blood; Accept the hookworm attached with hooks which damages the lining of the small intestine Mark 1 Q Reject feeds ‘off’ the hosts blood 8(d) (iii) Increased chance that eggs will survive / infect new human / to allow eggs to reach new hosts / more chance of completing life cycle; 1 Total 8 10 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question 9 (a) (i) 9 (a) (ii) Additional Comments/Guidance Answers 1. As the farm size increases, the number of species of butterflies decreases; 2. Due to fewer plant species/types of plant for them to feed on / less variety of food sources; 2. Ignore less food for butterflies. 1.78:1; Accept 1.8:1 or 1. 7̇: 1 Mark 2 1 Reject 1.7:1 9 (a) (iii) Yes (no mark) 1. Small farms do have more species; 2. No overlap of SDs between small and large farms (so) differences are significant/real; 2 max 2. Accept suitable use of data No (no mark) 3. No idea of numbers of each species; 4. Accept suitable economic argument, e.g. government money could be better spent elsewhere; 5. May not be true in countries other than Italy 9 (b) (i) Negative correlation/description; Accept (they are) inversely proportional /description of inverse proportionality. 11 1 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question 9 (b) (ii) Additional Comments/Guidance Answers 1. To reduce the number of species; 2. Which might compete with their crop/the hay in the meadow; Mark 2 max OR 3. To get more hay/increase yield of hay; 4. Frequent cutting stimulates growth; OR 5. To get more hay/increase yield of hay; 6. To feed animals (and make more profit); Total 8 12 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question 10 (a) 10 (b) Additional Comments/Guidance Answers 1. (Determine) the base sequence (of genes/and look for similarities/differences); 1. Immunological; 2. Anatomical; Mark 1 Accept fossil evidence/examples of fossil evidence for one mark 2 Neutral behavioural and embryological 10 (c) (i) Blocks/absorbs/dissipates UV (light) / lower risk of mutation/(skin) cancer/burning; 1 10 (c) (ii) 1. The sun is weaker/less UV (light) (in more northern latitudes); 2. (Lighter skin means) more UV (light) can be absorbed; 3. To make more vitamin D; 3 10 (c) (iii) 10 (d) 1. Enough vitamin D from diet/fish; 2.and 3. Reject ideas relating to absorbing vitamin D from sunlight Accept (in summer) high levels of UV are reflected by snow, (dark skin) protects them (from this reflected light); The results of preference/(sexual) attraction (when choosing mating partner); 1 1 13 MARK SCHEME – A-LEVEL HUMAN BIOLOGY – HBIO2 – JUNE 2016 Question Answers Additional Comments/Guidance 10 (e) (i) 1. More food/more regular food supply/food sources; 2. Can store food in times of plenty/for times of shortages/in winter 3. Do not have to move to new areas to find food / follow animals; 4. Larger populations/communities form/settle / increased reproduction; 5. Develop social structures/different roles/specialists 6. Develop the use of tools/skills; 7. Allow development of culture/trade; 10 (e) (ii) 1. Relevant reference to small population size; 2. Relevant reference to inbreeding/gene flow; 10 (e) (iii) 1. Small samples might not be reliable/representative (of all (European humans); 2. Trend not followed with Greenlanders/humans living coastal regions; 3. Does not show that evolution is happening now; 4. No fossils/skeletons showing transitions between dark and light/changes in pigmentation mentioned/hair/skin/eyes; Mark 6 max 2 Total 3 max 20 14