Download Math 110 Practice Test rubrics - Los Angeles Southwest College

Los Angeles Southwest College
Mathematics Department
MATH 110 – Common Final Exam
Practice TEST (rubric)
Part A: No partial credit will be given to the problems 1 through 10
1.
 2
 9
Perform the indicated operation: 18    
(2 pts)
4
2.
Perform the indicated operation: 7  ( 10)
(2 pts)
3
3.
Simplify:
5 y 11y

16 16
(2 pts)
y
4.
Combine like terms: 3x  5  8x  9
(2 pts)
5x  4
5.
Perform the indicated operation: 22
(2 pts)
4
6.
Perform the indicated operation:  | 16 |
(2 pts)
16
7.
Perform the indicated operation: 2(4)(7)
(2 pts)
56
8.
Perform the indicated operation: 3 36
(2 pts)
18
9.
Simplify: 2(3x  4 y  5)
(2 pts)
6 x  8 y  10
10.
Divide: 0.58 0.7192
10.
(2 pts)
1.24
Part B: Partial credit will be given to the problems 11 through 40
11.
3  (3) 2  5(2  7)
52
Simplify:
(4 pts)
a) 2  7  5
b) (3)2  9 
1pt

1pt
 52  25
c)  5  (5)  25

 3  (9)  27 
27  25 2
2


25
25 25
d)
12.
1pt
1pt
Find LCM of the set of terms: 20 x 2 y 6 , 18 x3 y, 6 x5 y3
20 x y  2  5 x y
2
6
2
2
6
1pt
18x y  3  2 x y
6 x5 y 3  3  2 x5 y 3
3
2
3
1pt
1pt
LCM  22  32  5 x5 y 6  180 x 5 y 6
13.
1pt
Combine like terms: 7 xy  10 x 2  4 xy  x 2
(3 pts)
7 xy  4 xy  10 x 2  x 2
3xy
1pt
(4 pts)
1pt
 9x2
1pt
2
14.
Simplify:
a) LCD  12
1pt
11  8
10  6
1pt
d)
Simplify:
17.
1pt
Simplify: 9 
1pt
(3) 2  9
(4 pts)
1pt
2  3  6 

23  6 
7 2

12 3
7 2 7 3 7
   
12 3 12 2 8
2 pts
8 9 7 72 7 65
  
 
8 1 8 8 8
8
2 pts
 1
 3
Simplify:  1 
1pt
9  (5) 14

 undef
6  6
0
1pt
(4 pts)
1  2 1
3  
2  3 2
(4 pts)
1 1 4 1 4  2 1  3 8  3 11
1    



3 2 3 2 3 2 2 3
6
6
2 1 11 1 11  2 1  3 22  3 19
3    



3 2 3 2 3 2 2 3
6
6
11 19 209
 
6 6
36
18.
3
16
1pt
(3  6) 2  (7  12)
(4  6)3  2  3
3  6  3 

7  12  5
4  6  2 
16.
(4 pts)
 11 2 
12   
 12 3 
b)
5 1
12   
6 2
c)
15.
11 2

12 3
5 1

6 2
1.5 pts
1.5 pts
1pt
Evaluate: 2a3  a 2 for a  2
(4 pts)
2(2)3  (2) 2
2(8)  4
1pt
1pt
3
19.
16  4
1pt
20
1pt
Simplify: 2  3(4  3  2)2
(4 pts)
2  3(4  6) 2
2  3(10)2
2  3(100)
2  300  298
20.
21.
Simplify:
1pt
1pt
1pt
1pt
3 xy 35

25 12 x
(4 pts)
1 pt
1 pt
1pt
for canceling 3 with 12
for canceling 35 with 25
for canceling x with x
1 pt
for multiplication
1pt
1pt
1pt
7y
20
1pt
Combine like terms: 2 x 2 y3  5x3 y 2  11x 2 y3  9 x3 y 2  6 xy 2
2x2 y3 11x2 y3  5x3 y 2  9x3 y 2  6 xy2
13 x 2 y 3
1pt
22.
 4 x3 y 2
1pt
 6 xy 2
1pt
Multiply: 4 x(2 x3  6 x 2  7 x  3)
(4 pts)
4  2  x  x3  4(6) x  x2  4(7) x  x  4  3  x
8  x  x3  24 x  x 2  28 x  x 12 x
8 x 4  24 x3  28 x 2 12 x
1pt
23.
(3 pts)
Simplify: (2 x  5)  ( 5 x  3)
2 pts
1pt
(3 pts)
2 x  5  5x  3
2 x  5x  5  3
1pt
1pt
7x  2
1pt
4
24.
Evaluate: 10  2[5  23 (2)]
(4 pts)
10  2[5  8(2)]
10  2[5  16]
10  2[11]
10  22
1pt
1pt
1pt
0.5 pts
12
25.
0.5 pts
Evaluate the expression:
3x  4 y
z  2y
for
x  3, y  2 and
3(3)  4(2)
3  2(2)
9  (8)
3  4
1
3  4
1
1
1
26.
1pt
1pt
1pt
Perform the indicated operation: 
4
3
2
3
5
(4 pts)
2 pts
1pt
1pt
Evaluate: 3 16  2 49
(4 pts)
3  4  2  7
1pt
1pt
12 14
2
28.
1pt
1pt
Multiply: 2 y 5  (7 y 3 )  (3 y 2 )
2  7 y
(4 pts)
1pt
4 13
 
3 5
4 5

3 13
20

39
27.
z  3
5
 y  (3 y
3
2
(4 pts)
)
1pt
14 y 8  (3 y 2 )
14(3)  y
8
y
1pt
2
1pt
42 y10
1pt
5
29.
x 1
x


4 3
12
Solve the equation:
(5 pts)
x 1 x 
12    
 4 3 12 
3x  4  x
4 2 x

2 2
2x
30.
31.
2 pts
1pt
1pt
1pt
Solve the equation: 9( x  3)  13  5 x  12
(5 pts)
9 x  27 13  5x 12
9x  40  5x 12
9x  5x  40  12
9x  5x  40 12
1pt
1pt
1pt
1pt
4 x 52

4
4
1pt
x  13
Solve the equation: 6.9x  8.4  4.02
(4 pts)
100  (6.9 x  8.4  4.02)
690x  840  402
690x  840  402
690 x 1242

690
690
32.
1pt
1pt
1pt
x  1.8
1pt
Solve the equation: 2.9( x  8.1)  7.8 x  3.95
(5 pts)
2.9x  23.49  7.8x  3.95
100  (2.9 x  23.49  7.8 x  3.95)
290x  2349  780x  395
395  2349  780x  290x
2744 490 x

490
490
33.
5.6  x
Solve the equation:
5  14  2  x
1pt
1pt
1pt
1pt
1pt
5 x

2 14
(4 pts)
5  14 2  x

2
2
2 pts
35  x
2 pts
6
34.
What percent of 15 is 5 ?
What
percent
x
x  15 5

15
15
1
x  33 %
3
35.
of 15 is 5?
 15  5
1
x
3
2 pts
1pt
1pt
17 is 25% of what number?
17 is 25% of
17  .25

17 .25  x

.25
.25
68  x
36.
(4 pts)
(4 pts)
what number ?
x
2 pts
1pt
1pt
A piece of coaxial cable
3
m long is to be cut into 5 pieces of the same length. What is the length of
5
each piece?
x x x x x 
5x 
3
5
3 pts
3
5
1pt
31
1
  5x   
55
5
1pt
3
m
25
1pt
x
37.
(6 pts)
A recipe for muffins calls for
1
2
3
qt (quart) of buttermilk, qt of skin milk, and qt of oil. How many
6
3
4
quarts of liquid ingredients does the recipe call for?
(6 pts)
2 3 1
 
3 4 6
LCD  12
8 9 2
x  
12 12 12
19
x  qt
12
x
38.
A rectangular table top measures
3 pts
1pt
1pt
1pt
4
3
m long and m wide. Find the following: a) it's area and b) it's
5
5
perimeter.
(6 pts)
7
a)
A  Length  Width
A
12 2
m
25
A
4 3

5 5
2 pts
1pt
4
3
b) Perimeter  2  Length  2  Width P  2    2   2 pts
5
5
8 6
P 
5 5
39.
P
14
5
4
P2 m
5
1pt
An ocean liner traveled 408 km in 12 hr . At that rate, how far would the boat travel in 36 hr ?
408km x km

12h
36h
408  36  12x
40.
(6 pts)
3 pts
1pt
408  36 12 x

12
12
1pt
1224  x
1pt
x  1224 km
A lab technician has 850 ml of a solution of water and acid: 3% is acid. How many milliliters are acids?
water?
(6 pts)
# of milliliters of acid : x  850  (0.03)
3 pts
x  25.5 ml
1pt
# of milliliters of water :850  25.5  824.5 ml
2 pts
8