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Geometry/Trig 2 Name: __________________________ Unit 4 Review Packet – page 1 Date: ___________________________ Part 1 – Polygons Review 1) Answer the following questions about a regular decagon. a) How many sides does the polygon have? 10 b) What is the sum of the measures of the interior angles? 1440 c) What is the measure of each interior angles? 144 d) What is the sum of the measures of the exterior angles? 360 e) What is the measure of each exterior angle? 36 f) How many diagonals can be drawn in the polygon? 35 2) Each exterior angle of a regular polygon is 90. Answer each question about the polygon. a) What is the sum of the exterior angles? 360 b) How many sides does the polygon have? 4 c) What is the name of the polygon? Quadrilateral d) What is the sum of the measures of the interior angles? 360 e) What is the measure of each interior angle? 90 f) How many diagonals can be drawn in the polygon? 2 3) The sum of the interior angles of a regular polygon is 540. Answer each question about the polygon. a) How many sides does the polygon have? 5 b) What is the name of the polygon? Pentagon c) What is the measure of each interior angle? 108 d) What is the sum of the measures of the exterior angles? 360 e) What is the measure of each exterior angle? 72 f) How many diagonals can be drawn in the polygon? 5 Part 2 – Segments in Triangles - Give the most specific name for each dotted segment. Altitude Perpendicular Bisector Angle Bisector Median Geometry/Trig 2 Name: __________________________ Unit 4 Review Packet – page 2 Date: ___________________________ Part 3 – Determine whether the triangles are congruent. If they are, name the congruent triangles and the postulate or theorem you used. If there is not enough information, write none. Mark your diagrams. D AC ^ DB L K H G A C B LM // PN LP // MN F KF // HJ G is the midpoint of FH DABD @ DCBD HL P J DKGF @ DJGH AAS or ASA Q N M DLPN @ DNML ASA X R F Y W T S G H J Z V S is the midpoint of RT A None DWXY @ DBZA SSS AD // BC D A FG // JH; FG @ JH B DFGH @ DHJF SAS D V C C T B S W VT bisects SVW A None None CB @ DA DDAC @ DBCA HL B Geometry/Trig 2 Name: __________________________ Unit 4 Review Packet – page 3 Date: ___________________________ Part 4 - Solve each algebra connection problem. Answer all questions. 2. 1. A 2x 3x - 19 B C 6x + 15 104° A B x = 19 Classify the triangle by its sides: Isosceles mA = 38 What two sides are congruent? AB = AC mC = 38 What two angles are congruent? mB = mC Classify the D by its sides: Isosceles x=8 Classify the D by its angles: Obtuse mC = 63 B 102° 48° C 6x + 15 = 9x – 9 24 = 3x x=8 2x + 3x – 19 + 104 = 180 5x = 95 x = 19 3. 9x - 9 C mB = 63 4. mA = 54 B 15x - 30 A A mA = 30 Are any of the angles congruent? No Therefore, are any of the sides congruent? No Classify the triangle by its sides: Scalene Classify the triangle by its angles: Obtuse Order the side lengths from longest to shortest: Longest: AC Middle: AB Shortest: BC 10x 3x + 42 C 15x – 30 + 10x + 3x + 42 = 180 28x + 12 = 180 x=6 x=6 mA = 60 mB = 60 mC = 60 Classify the D by its sides: Equilateral Classify the D by its angles: Equiangular Geometry/Trig 2 Name: __________________________ Unit 4 Review Packet – page 4 Date: ___________________________ NOTE: Many pieces of notation (such as segment bars and rays are missing). Given: B is the midpoint of CA; Statements Reasons DC @ DA 1) B is the midpoint of CA 1) Given 2) CB = BA 2) Definition of a Midpoint 3) DC = DA 3) Given 4) DB = DB 4) Reflexive 5) DCBD @ DABD 5) SSS 6) 5 @ 6 6) CPCTC Prove: 5 @ 6 D 5 6 1 2 C 3 4 B A C 1 Statements 2 Reasons 1) D is the midpoint of AB 1) Given 2) AD = DB 2) Definition of a Midpoint 3) CA = CB 3) Given 4) CD = CD 4) Reflexive 5) DADC @ DBDC 5) SSS 6) 1 @ 2 6) CPCTC 7) CD bisects ACB 7) Definition of a Angle Bisector A D B Given: D is the midpoint of AB; CA @ CB Prove: CD bisects ACB Geometry/Trig 2 Name: __________________________ Unit 4 Review Packet – page 5 Date: __________________________ Statements Given: AC @ DB; CD @ BA Reasons 1) AC = DB; CD = BA 1) Given 2) AD = AD 2) Reflexive 3) DACD @ DDBA 3) SSS 4) C @ B 4) CPCTC Prove: C @ B C A D B Given: AC @ DB; CAD @ BDA Statements Reasons 1) AC = DB; CAD @ BDA 1) Given 2) AD = AD 2) Reflexive 3) DACD @ DDBA 3) SAS 4) CD = BA 4) CPCTC Prove: CD @ BA C A D B Geometry/Trig 2 Name: __________________________ Unit 4 Review Packet – page 6 Date: __________________________ Statements Reasons Given: PR bisects QPS; PQ @ PS Prove: RP bisects QRS 1) PR bisects QPS 1) Given 2) QPR @ SPR 2) Definition of an Angle Bisector 3) PQ = PS 3) Given 4) PR = PR 4) Reflexive 5) DPQR @ DPSR 5) SAS 6) QRP @ SRP 6) CPCTC 7) RP bisects QRS 7) Definition of an Angle Bisector Q P R S Given: PR bisects QPS and QRS Statements Prove: RQ @ RS Reasons 1) PR bisects QPS 1) Given 2) QPR @ SPR 2) Definition of an Angle Bisector 3) RP bisects QRS 3) Given 4) QRP @ SRP 4) Definition of an Angle Bisector 5) PR = PR 5) Reflexive 6) DPQR @ DPSR 6) ASA 7) RQ = RS 7) CPCTC Q P R S Geometry/Trig 2 Name: __________________________ Unit 4 Review Packet – page 7 Date: __________________________ Statements Given: AB // DC; AD // BC Reasons Prove: DABC @ DCDA 1) AB // DC 1) Given 2) 1 @ 2 2) If lines are parallel, then alternate interior angles are congruent. 3) AD // BC 3) Given 4) 3 @ 4 4) If lines are parallel, then alternate interior angles are congruent. 5) AC = AC 5) Reflexive 6) DABC @ DCDA 6) ASA B A 4 1 2 D 3 C Given: JL ^ KM; L is the midpoint of KM Statements Prove: DJLK @ DJLM Reasons 1) JL ^ KM 1) Given 2) 2 and 3 are right angles 2) Definition of Perpendicular Lines 3) m2 = 90; m3 = 90 3) Definition of Right Angles 4) m2 = m3 4) Substitution 5) L is the midpoint of KM 5) Given 6) KL = ML 6) Definition of a Midpoint 7) JL = JL 7) Reflexive 8) DJLK @ DJLM 8) SAS J K 1 2 3 L 4 M Geometry/Trig 2 Name: __________________________ Unit 4 Review Packet – page 8 Date: __________________________ Statements Given: TM @ PR; TM // RP Reasons Prove: E is the midpoint of TP 1) TM = PR 1) Given 2) TM // RP 2) Given 3) T @ P; M @ R 3) If lines are parallel, then alternate interior angles are congruent. 4) DTEM @ DPER 4) ASA 5) TE = EP 5) CPCTC 6) E is the midpoint of TP 6) Definition of a Midpoint T E R M P Given: C & D are right angles; AD @ BC Statements Prove: DBAD @ DABC Reasons 1) C & D are right angles 1) Given 2) AD = BC 2) Given 3) AB = AB 3) Reflexive 4) DBAD @ DABC 4) HL D A C B