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Linear Equations EXAMPLES: 1. Solve the equation 7x − 4 = 3x + 8. Solution: We have 7x − 4 = 3x + 8 7x − 4 + 4 = 3x + 8 + 4 7x − 4 = 3x + 8 7x = 3x + 12 7x − 3x = 8 + 4 7x − 3x = 3x + 12 − 3x or, in short, 4x = 12 4x = 12 x= 4x 12 = 4 4 x=3 12 =3 4 2. Solve the equation −5(x − 4) + 2 = 2(x + 7) − 3. Solution: We have −5(x − 4) + 2 = 2(x + 7) − 3 −5x + 20 + 2 = 2x + 14 − 3 −5x + 22 = 2x + 11 −5(x − 4) + 2 = 2(x + 7) − 3 −5x + 22 − 2x = 2x + 11 − 2x −5x + 20 + 2 = 2x + 14 − 3 −7x + 22 = 11 or, in short, −7x + 22 − 22 = 11 − 22 −7x = −11 −7x = −11 x= −11 −7x = −7 −7 x= −5x − 2x = 14 − 3 − 20 − 2 11 7 1 11 7 3. Solve the equation y+7 y+5 y−2 − = + 1. 2 4 3 Solution: We have y+7 y+5 y−2 − = +1 2 4 3 y+5 y−2 y+7 12 · = 12 · − +1 2 4 3 12 · y−2 y+7 y+5 − 12 · = 12 · + 12 · 1 2 4 3 6(y + 5) − 3(y − 2) = 4(y + 7) + 12 6y + 30 − 3y + 6 = 4y + 28 + 12 3y + 36 = 4y + 40 3y + 36 − 4y = 4y + 40 − 4y −y + 36 = 40 −y + 36 − 36 = 40 − 36 −y = 4 −y(−1) = 4(−1) y = −4 In short, y+5 y−2 y+7 − = +1 2 4 3 y+5 y−2 y+7 12 · = 12 · − +1 2 4 3 6(y + 5) − 3(y − 2) = 4(y + 7) + 12 6y + 30 − 3y + 6 = 4y + 28 + 12 30 + 6 − 28 − 12 = 4y − 6y + 3y y = −4 7. Solve for M the equation F = G Solution: We have Gm M F = r2 The solution is M = =⇒ mM . r2 r2 Gm F = r2 F . Gm 2 r2 Gm Gm r2 M =⇒ r2 F =M Gm 8. The surface area A of the closed rectangular box can be calculated from the length l, the width w, and the height h according to the formula A = 2lw + 2wh + 2lh Solve for w in terms of the other variables in this equation. Solution: We have A = 2lw + 2wh + 2lh A = (2l + 2h)w + 2lh A − 2lh = (2l + 2h)w A − 2lh =w 2l + 2h The solution is w = A − 2lh . 2l + 2h Linear Inequalities An inequality is linear if each term is constant or a multiple of the variable. EXAMPLE: Solve the inequality 3x < 9x + 4 and sketch the solution set. Solution: We have 3x < 9x + 4 3x − 9x < 9x + 4 − 9x −6x < 4 −6x 4 > −6 −6 x>− 2 3 2 The solution set consists of all numbers greater than − . In other words the solution of the 3 2 inequality is the interval − , ∞ . 3 EXAMPLE: Solve the inequalities 4 ≤ 3x − 2 < 13 and sketch the solution set. 3 EXAMPLE: Solve the inequalities 4 ≤ 3x − 2 < 13 and sketch the solution set. Solution: We have 4 ≤ 3x − 2 < 13 4 + 2 ≤ 3x − 2 + 2 < 13 + 2 6 ≤ 3x < 15 6 3x 15 ≤ < 3 3 3 2≤x<5 Therefore, the solution set is [2, 5). EXAMPLE: Solve the inequalities −4 < 5 − 3x ≤ 17 and sketch the solution set. Solution: We have −4 < 5 − 3x ≤ 17 −4 − 5 < 5 − 3x − 5 ≤ 17 − 5 −9 < −3x ≤ 12 −9 −3x 12 > ≥ −3 −3 −3 3 > x ≥ −4 −4 ≤ x < 3 Therefore, the solution set is [−4, 3). 4