Download Geometry EOC Review Packet (1

Geometry EOC Review
Packet (1-59) answer key
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distance formula
converse- flip
supplementary=180
use order of letters and graph
x(y)=w(z) chords
(apothem x perimeter)/2
vertices
similar proportions (cross multiply)
45-45-90 rt triangles
midpoint formula, finding end point
logically equivalent= if ~q, then ~p
remote int angles = ext angle
diagonals bisect each other
find radius, c=2piR
find height pyth theo, area of trapezoid
SA of cone
proportions, find perimeter
45-45-90 rt triangles
midpoint formula, finding end point
inverse= not, not (~p ~q)
alt int, vert, triangle=180
[(n-2)180]/n
diagonals bisect each other
find radius using C, arc length formula
incsribed angles = 1/2 arc
diameter=side, perimeter
SA of pyramid
proportions
Trig Ratios (SOHCAHTOA)
Trig Ratios (SOHCAHTOA)
Trig Ratios (SOHCAHTOA)
types of angles = on each line
reg ext angle = 360/n
draw givens, ASA, SAS,SSS, AAS???
draw givens, ASA, SAS,SSS, AAS???
inscribed angles = 1/2 arc
Area of trapezoid + area 1/2 circle
V of cone
SA= Ph + 2(bh/2 of triangle)
proportions
proportions
Trig Ratios (SOHCAHTOA)
Trig Ratios (SOHCAHTOA)
bigger side is opp bigger angle
sum of 2 sides > third side of triangle
bigger side is opp bigger angle
arc length
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(add arcs )/2
find area of 4 rectangles and add
ratio of perimeter and area (square sides)
square (sides=), bigger square x2
V of cylinder + V of cone
V of rect, divided by 144
proportions, perimeter
Angles in similar figures are =
use letters and corresponding sides
30-60-90=AD, pyth theo = DB, AD+DB=AB
30-60-90
30-60-90