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Math 2345 EXAM # 2 Formula Sheet
Interval Estimation:
eq8.1: 100(1 − α)% Confidence Interval (CI) for
σ
Mean (σ known): X ± Zα/2 √
n
Sampling Distribution:
eq7.1: Expected Value of X: E(X) = µ
σ
eq7.2 Standard Deviation of X: σX = √
n
eq8.2: 100(1 − α)% CI for Mean (σ unknown):
S
X ± tα/2 √
n
eq7.4: Expected Value of p: E(p) = p
r
eq7.6: Standard Deviation of p: σp =
eq8.6: 100(1 − α)% CI for Proportion:
r
p (1 − p)
p ± Zα/2
n
p(1 − p)
n
Testing:
eq9.1: The test statistic for mean µ (σ know): Zcal =
X − µ0
√σ
n
eq9.2: The test statistic for Mean µ (σ unknown):
X̄ − µ0
tcal =
with (n-1) degrees of freedom.
S
√
n
p − p0
eq9.4: The test statistic for proportion p: Zcal = q
p0 (1−p0 )
n
eq10.5: Test statistic for mean difference µ1 − µ2 (σ1 , σ2 known): Zcal =
(X1 − X2 ) − D0
q 2
σ1
σ22
n1 + n2
eq10.8: Test statistic for Mean difference µ1 − µ2 (σ1 , σ2 unknown): tcal =
s2
(with eq10.7: df =
( n11 +
s21 2
1
n1 −1 ( n1 )
+
s22 2
n2 )
s22 2
1
n2 −1 ( n2 )
)
eq10.9: Test statistic for mean difference (matched samples): tcal =
d − µd
Sd
√
n
(with (n − 1) degrees of freedom)
eq11.7: Test statistic for the difference between two proportions p1 − p2 :
(p1 − p2 )
n1 p1 + n2 p2
Zcal = q
, where eq 11.6: p =
1
1
n1 + n2
p(1 − p)( n1 + n2 )
Note:
two-tailed test: p − value = 2P (Z > |Zcal |);
upper,one-tail test: p − value = P (Z > Zcal );
lower, one-tail test: p − value = P (Z < Zcal ).
Z0.05 = 1.645, Z0.025 = 1.96, Z0.005 = 2.58.
(X1 − X2 ) − D0
q 2
s1
s22
n1 + n2
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