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ACT Practice
Elementary Algebra
Volume of a cylinder
V = πr2h
π ≈ 3.14 {rounded}
r = 12 ft {radius is half the diameter}
h = 5 ft {height of water is 5 ft}
V = πr2h {volume of a cylinder}
≈ 3.14(122)(5) {substituted given values in}
≈ 3.14(144)(5) {squared the 12}
≈ 2260.8 {multiplied}
Answer varies slightly because π was rounded
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ACT Practice
Plane Geometry
{distance around circle}
Circumference of circle
C = πd
π ≈ 3.14 {rounded}
d = 24 ft {diameter is all the way across circle}
C = πd {circumference of circle}
≈ 3.14(24) {substituted given values in}
≈ 75.36 {multiplied}
Zipper will go along 1 side of wedge (radius = 12 ft)
and around the arc (made by the 45° angle)
1
45° is 8 of a circle
45°
360°
=
1
8
1
Find 8 of the circumference, 75.36,
and that is the length of the arc:
= 75.36 ÷ 8
= 9.42 {approximate length of arc, π was rounded}
Add the 1 side of wedge and length of arc:
12 + 9.42 {wedge + arc equals zipper length}
≈ 21.42 {approximated because π was rounded}
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The rate of change (height over time),
should become more gradual (slow down)
once the faster hose quits working.
ACT Practice
Intermediate Algebra
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ACT Practice
Trigonometry
6 ft
75°
x
tan =
opposite
adjacent
6
tan 75° =
x
x tan75° = 6
𝐱=
{multiplied each side by x}
𝟔
{divided each side by tan 75°}
𝐭𝐚𝐧 𝟕𝟓°
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