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ACT Practice Elementary Algebra Volume of a cylinder V = πr2h π ≈ 3.14 {rounded} r = 12 ft {radius is half the diameter} h = 5 ft {height of water is 5 ft} V = πr2h {volume of a cylinder} ≈ 3.14(122)(5) {substituted given values in} ≈ 3.14(144)(5) {squared the 12} ≈ 2260.8 {multiplied} Answer varies slightly because π was rounded © Mr. Sims ACT Practice Plane Geometry {distance around circle} Circumference of circle C = πd π ≈ 3.14 {rounded} d = 24 ft {diameter is all the way across circle} C = πd {circumference of circle} ≈ 3.14(24) {substituted given values in} ≈ 75.36 {multiplied} Zipper will go along 1 side of wedge (radius = 12 ft) and around the arc (made by the 45° angle) 1 45° is 8 of a circle 45° 360° = 1 8 1 Find 8 of the circumference, 75.36, and that is the length of the arc: = 75.36 ÷ 8 = 9.42 {approximate length of arc, π was rounded} Add the 1 side of wedge and length of arc: 12 + 9.42 {wedge + arc equals zipper length} ≈ 21.42 {approximated because π was rounded} © Mr. Sims The rate of change (height over time), should become more gradual (slow down) once the faster hose quits working. ACT Practice Intermediate Algebra © Mr. Sims ACT Practice Trigonometry 6 ft 75° x tan = opposite adjacent 6 tan 75° = x x tan75° = 6 𝐱= {multiplied each side by x} 𝟔 {divided each side by tan 75°} 𝐭𝐚𝐧 𝟕𝟓° © Mr. Sims Any rebroadcast, reproduction, modification or other use of the work, presentations, and materials from this site without the express written consent of Mr. Sims, is prohibited. © Mr. Sims. All rights reserved. © Mr. Sims