Survey
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
PHYS 1111 Exam 1 Formula Sheet Displacement: ∆x = xf – xi Average speed = distance/time Average velocity: vav = ∆x/∆t Average acceleration: aav = ∆v/∆t 1-dimensional motion with constant acceleration: v = v0 + at vav = 1/2 (v0 + v ) x = x0 + 1/2 (v0 + v ) t x = x0 + v0 t + 1/2 at2 v2 = v02 + 2a(x – x0) Acceleration due to gravity: g = 9.81 m/s2 Components of a vector: x component of vector A: Ax = A cos θ, where θ is measured relative to the x-axis. y component of vector A: Ay = A sin θ, where θ is measured relative to the x-axis. Magnitude of vector A: A = √(Ax2 + Ay2 ) Direction angle of vector A: θ = tan-1 (Ay / Ax ) Unit vectors, vector addition: A + B = (Ax + Bx) x + (Ay + By) y Relative motion: v13 = v12 + v23 Projectile motion: ax = 0 ay = – g General launch angle from origin (x0 = y0 = 0) with initial speed v0 at an angle θ with respect to the horizontal: x = (v0 cos θ) t y = (v0 sin θ) t – 1/2 gt2 vx = v0 cos θ vy = v0 sin θ – gt vx 2 = v02 cos2 θ vy 2 = v02 sin2 θ – 2 g ∆y Range: R = (v02/g) sin 2θ Maximum Height: ymax = (v02 sin2 θ)/2g Other info: Volume = Area × depth = 4πR3/3 1 in = 0.0254 m 1 µm = 10−6 m