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Name ______Mr. Perfect______________________________________ Date ____F 16_____________ 1. Balance the following redox reactions using the half-reaction method. (10 pts) a. Cr + NO3- → Cr3+ + NO [acidic] Cr → Cr3+ + 3e3e- + 4H+ + NO3- → NO + 2H2O 4H+ + Cr + NO3- → Cr3+ + NO + 2H2O b. CrO42- + SO32- → Cr(OH)3 + SO42- [basic] 2 x (3e- + 5H+ + CrO42- → Cr(OH)3 + H2O) 3 x (H2O + SO32- → SO42- + 2H+ + 2e-) 10H+ + 2CrO42- + 3H2O + 3SO32- → 2Cr(OH)3 + 2H2O + 3SO42- + 6H+ 4 10H+ + 2CrO42- + 3H2O + 3SO32- → 2Cr(OH)3 + 2H2O + 3SO42- + 6H+ 4OH4OH2CrO42- + 5H2O + 3SO32- → 2Cr(OH)3 + 3SO42- + 4OH2. Calculate Ecell and ΔG for the following voltaic cell under non-standard conditions: [Cu2+] = 0.10 M and [Zn2+] = 1.90 M. (10 pts) Cu2+(aq) + Zn(s) → Cu(s) + Zn2+(aq) Nernst Equation 0.0592 𝑉 ° 𝐸𝑐𝑒𝑙𝑙 = 𝐸𝑐𝑒𝑙𝑙 − 𝑙𝑜𝑔𝑄 𝑛 F = 96500 J/Vmol Standard Reduction Potentials E° 2+ 2e- + Cu → Cu 0.342 V 2+ 2e- + Zn → Zn -0.762 V E°cell = Ecat – Ean = 0.342 V – (-0.762 V) = 1.104 V ° 𝐸𝑐𝑒𝑙𝑙 = 𝐸𝑐𝑒𝑙𝑙 − 0.0592 𝑉 0.0592 𝑉 (1.9) 𝑙𝑜𝑔𝑄 = 1.104 𝑉 − 𝑙𝑜𝑔 = 𝟏. 𝟎𝟔𝟔 𝑽 𝑛 2 (0.1) ΔG = -nFE = -(2 mol e-)(96500 J/V mol)(1.066 V) = -205767 J or -205.8 kJ Chemistry 102 Exam 3 Name ______Mr. Perfect______________________________________ Date ____F 16_____________ 3. Complete the following nuclear reactions. Clearly state the nuclear decay mode to receive full credit. (10 pts) Negatron Emission Electron Capture 97 60 0 0 a) 27 Co 1 e + 60 b) 43Tc + −10𝑒 97 28𝑁𝑖 42 Mo + 0𝛾 c) 226 88 Alpha Particle Decay Ra 42 He + 222 86𝑅𝑛 Positron Emission d) Bi 01 e + 205 82𝑃𝑏 205 83 4. Using the spectrochemical series, fill the electrons in the following crystal field diagram for the following diamagnetic transition metal complex. Is this the ligand a strong field ligand or a weak field ligand? Also predict if the compound is square planar or tetrahedral. (10 pts) Spectrochemical Series I <Br <Cl <F <OH-<H2O//<NH3<en< NO2-<CN-<CO Weak Field ligands (High Spin) Strong Field Ligands (Low Spin) Tetrahedral Square Planar - - - - [Ni(CO)4]2+ CO gives low spin = strong field Ni2+ d8 ion __↑↓__ ___↑__ __↑___ dxy dyz dxz _____ dx2-y2 __↑↓__ dxy __↑↓__ dz2 __↑↓__ __↑↓__ dz2 dx2-y2 Paramagnetic __↑↓__ __↑↓__ dxz dyz Compound is Square planar. Diamagnetic 5. Using the short-hand notation (Noble Gas Configuration), write the ground-state electron configuration for the following transition metals: (10 pts) a. Fe2+ b. Re7+ c. Cu1+ d. Pd2+ [Ar]3d6 [Xe]4f14 [Ar]3d10 [Kr]4d8 Chemistry 102 Exam 3 Name ______Mr. Perfect______________________________________ Date ____F 16_____________ 6. Draw the following transition metal complexes in their correct molecular geometry and state the hybrid orbital involved in the bonding. Name the molecular geometry shape and label the bond angles to receive full credit. (10 pts) * Some of the charges and ligands and metals may be incorrect due to the drawing program used. a) FeCl3 b) K3[Fe(CN)6] N C N N C C 4- Cl Fe N Cl C C - Fe C Cl N N Trigonal Planar Octahedral 2 sp sp3d2 all bond angles are 120° all bond angles are 90° 7. Draw the isomers for the following compounds: (10 pts) a. Optical Isomers Co(en)2Cl2 NH NH Cl 4- Cl Co NH NH b. Coordination Isomers [Fe(H2O)5Cl]Br HN NH 4- HO Co Cl Cl HN NH OH Cl 4- HO Fe HO OH OH Br 4- Fe OH HO OH OH mirror images 8. State the oxidation number and coordination number of the following transition metals for each of the following compounds: (10 pts) a) K4[PtCl6] b) [Cu(NH3)4]SO4 Oxidation Number = +2 Oxidation Number = +2 Coordination Number = 6 Coordination Number = 4 c) [Co(H2O)6]I3 d) K2[CoCl4] Oxidation Number = +3 Oxidation Number = +2 Coordination Number = 6 Coordination Number = 4 Chemistry 102 Exam 3 Name ______Mr. Perfect______________________________________ Date ____F 16_____________ 9. The complex ion [Ti(H2O)6]3+ is violet in solution. Calculate the crystal field splitting energy in kJ/mol for this ion. (10 pts) h = 6.626 x 10-34 Js c = 3.00 x 108 m/s Absorbed wavelength (nm) Observed Color 6.02 x 1023 ions/mol 400 violet greenish-yellow 450 blue yellow 1 nm = 10-9 m 490 blue-green red 570 yellow-green violet 580 yellow dark-blue 600 orange blue 650 red green 3.00𝑥108 𝑚 (6.626𝑥10−34 𝐽 𝑠)( ) 6.02𝑥1023 𝑖𝑜𝑛/𝑚𝑜𝑙 ℎ𝑐 𝑠 ∆=𝐸 = = × = 𝟐𝟏𝟎 𝒌𝑱/𝒎𝒐𝒍 10−9 𝑚 𝜆 1000 𝐽/𝑘𝐽 (570 𝑛𝑚)( ) 𝑛𝑚 10. Write a partial decay series for Ra-226 undergoing the following sequential decays. (10pts) Alpha → Alpha → negatron → alpha Alpha Decay 226 4 222 88𝑅𝑎 → 2𝐻𝑒 + 86𝑅𝑛 Alpha Decay → 42𝐻𝑒 + 218 84𝑃𝑜 222 86𝑅𝑛 Negatron Emission → −10𝑒 + 218 85𝐴𝑡 218 84𝑃𝑜 218 85𝐴𝑡 Alpha Decay → 42𝐻𝑒 + 214 83𝐵𝑖 11. Extra Credit. The following solutions of nickel absorb light in the following regions of the electromagnetic spectrum: NiCl42-(702 nm) and NiBr42-(756 nm). Which ion has the greater crystal field splitting energy? (5 pts) ℎ𝑐 𝐶𝑟𝑦𝑠𝑡𝑎𝑙 𝐹𝑖𝑒𝑙𝑑 𝑆𝑝𝑙𝑖𝑡𝑡𝑖𝑛𝑔 𝐸𝑛𝑒𝑟𝑔𝑦 = ∆= 𝐸 = 𝜆 E702 nm > E756 nm Chemistry 102 Exam 3