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TR1.1: PYTHAGORAS’ THEOREM Right-angled triangles A right-angled triangle has an angle of 90o. In a right-angled triangle the side opposite the right angle is called the hypotenuse. It is also the longest side. hypotenuse Right angle (90o) Pythagoras’ Theorem Pythagoras’ theorem states: In a right angled triangle the square of the length of the hypotenuse (h), is equal to the sum of the squares of the other two sides. h b 2 h= a 2 + b2 a Pythagoras’ Theorem can be used to find a side length of a right angled triangle given the other two side lengths. Example Finding the hypotenuse Find the length of the hypotenuse (h) in the following triangle. Use Pythagoras theorem h= a + b with a = 6cm. and b = 8 cm. 2 h 6 cm 2 2 h 2 = 62 + 82 ∴ h 2 = 36 + 64 ∴ h 2 = 100 ∴ h = 10 Note: Measurements must be in the same units and the unknown length will be in these same units - so h will be 10 cm. 8 cm TR1.1 - Trigonometry: Pythagoras’ Theorem Page 1 of 3 June 2012 Finding a shorter side Find the value of x in the triangle below. In this triangle, one of the shorter sides is to be calculated. 2 h= a 2 + b2 x 2.7 h = 4.2, a = 2.7 and b = x 2 = 4.2 2.7 2 + x 2 ∴ 4.22 − 2.7 2 = x2 ∴17.64 − 7.29 = x2 4.2 ∴10.35 = x2 ∴x = 3.22 or rearrange Pythagoras’ theorem from h= a + b 2 2 2 to 2 a= h2 − b2 where a is the unknown side. Using the above triangle x2 = 4.22 – 2.72 giving x = 3.22 as before. Pythagorean triples In some right-angled triangles all three sides have integer values. These three values form a Pythagorean triple. Some examples are triangles with sides: (3,4,5), (5,12,13), (7,24 25) and (8,15,17) Check! Multiples of these, such as (6,8,10) and (9,12,15) are also Pythagorean triples. Exercises Find the missing sides in the following. (1) 9mm (2) a h 20.2 6.5 12mm TR1.1 - Trigonometry: Pythagoras’ Theorem Page 2 of 3 June 2012 (3) (4) 7cm 4.8 cm a c (5) 14 cm 6.2 cm (6) 25 37 b 34 a 12 Answers (1) 15mm. (2) 19.13 (3) 7.84 cm. (4) 12.12 cm. TR1.1 - Trigonometry: Pythagoras’ Theorem (5) 42.2 (6) 35 Page 3 of 3 June 2012