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Math 2315 - Calculus II Quiz #13 - 2007.11.28 Solutions 1. Find a power series representation for the function f (x) = x 4x+1 and determine the interval of convergence. x 4x + 1 1 =x· 1 + 4x 1 =x· 1 − (−4x) ∞ X =x· (−4x)n−1 f (x) = =x· n=1 ∞ X (−4)n−1 xn−1 n=1 = ∞ X 1 − (−4x)n−1 4 n=0 This series converges if |−4x| < 1 or − 14 < x < 14 . So the interval of convergence is − 41 , 14 . 2 2. Find a power series representation for the function f (x) = ln(x + 3) and determine the interval of convergence. So first, we notice that d 1 ln(x + 3) = dx x+3 where 1 1 1 = x+3 3 1 + x3 1 1 = 3 1 − (− x3 ) ∞ 1 X x n . − = 3 n=0 3 So we have ∞ 1 X x n − dx 3 n=0 3 n ∞ 1X 1 1 = xn+1 + D − 3 n=0 3 n+1 Z ln(x + 3) = = ∞ X (−1)n x n+1 +D n+1 3 n=0 Plugging in x = 0 gives that D = ln(3). Therefore ∞ X (−1)n x n+1 + ln(3). ln(x + 3) = n+1 3 n=0 The interval of convergence can be found from the sum ∞ 1 X x n − , 3 n=0 3 which requires that − x3 < 1 or −3 < x < 3. So the interval of convergence is (−3, 3).