Survey
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
Unit 1: Solving Equations Lesson 4: Solving Multiplication Equations In order to solve multiplication equations, we will use the opposite operation: ________________ Example 1 Example 3 Copyright© 2009 Algebra-class.com Example 2 A Few Notes About Fractions: Example 4 Unit 1: Solving Equations Lesson 4: Solving Multiplication Equations Directions: Solve each equation on your own paper. If your answer is a decimal, round to the nearest hundredth. 1. 10x = 80 2. -12x = 36 3. -9x = - 81 4. -2x = 17 5. .5x = 1.2 6. -4.4x = -9.2 7. -2/3x = 109 8. 4/7x = -6/7 9. -8/9x = 16 10. .8y = 8 11. ¾ = -2/3x 12. 1/2x = 5.5 13. -19 = -3j 14. 14k = -45 15. 9.3p = 82.1 16. -6/7 = 3/7a BONUS: 17. 140 people registered for a volleyball tournament. How many 6 person teams can be formed? Number of people on a team • Number of teams = Total number of registrants 6 • t 6t = 140 = 140 (Solve for t) 18. John makes $12.45 an hour at his part-time job. Last week he made $174.30. How many hours did John work? Pay rate • Number of hours worked = Total Pay check Copyright© 2009 Algebra-class.com Unit 1: Solving Equations Directions: Solve each equation. Show every step. (2 points each) 1. -6r = 84 2. -2/3x = -14 3. .7x = 8.4 4. 3/4y = -3/5 5. -135 = -9y Copyright© 2009 Algebra-class.com Unit 1: Solving Equations Lesson 4: Solving Multiplication Equations Answer Key Directions: Solve each equation. If your answer is a decimal, round to the nearest hundredth. 1. 10x = 80 2. -12x = 36 10x = 80 10 10 2. -12x = 36 -12 -12 x=8 x = -3 3. -9x = - 81 4. -2x = 17 9x = - 81 -9 -9 -2x = 17 -2 -2 x=9 x = -17/2 or -8.5 5. .5x = 1.2 6. -4.4x = -9.2 5x = 1.2 .5 .5 -4.4x = -9.2 -4.4 -4.4 x = 2.4 x = 2.09 7. -2/3x = 109 ∙ 8. 4/7x = -6/7 = 109 ∙ x = -163.5 ∙ = 16 ∙ ∙ x = -3/2 or -1.5 9. -8/9x = 16 ∙ = 10. .8y = 8 .8y = 8 .8 .8 x = -18 y = 10 Copyright© 2009 Algebra-class.com Unit 1: Solving Equations 11. ¾ = -2/3x 12. 1/2x = 5.5 -2/3x = ¾ (2) 1/2x = 5.5(2) (-3/2) -2/3x = ¾(-3/2) x = 11 x = -9/8 13. -19 = -3j 14. 14k = -45 -3j = -19 -3 -3 14k = -45 14 14 j = 19/3 k = -45/14 15. 9.3p = 82.1 16. -6/7 = 3/7a 9.3p = 82.1 9.3 9.3 (7/3) 3/7a = -6/7 (7/3) a = -2 p = 8.83 BONUS: 17. 140 people registered for a volleyball tournament. How many 6 person teams can be formed? Number of people on a team • Number of teams = Total number of registrants 6 • t = 140 6t = 140 (Solve for t) 6t = 140 6 6 t = 23.3 (23 6 person teams can be formed. 18. John makes $12.45 an hour at his part-time job. Last week he made $174.30. How many hours did John work? Pay rate • Number of hours worked = Total Pay check 12.45 • h = 174.30 12.45h = 174.30 12.45 12.45 h = 14 (John worked 14 hours) Copyright© 2009 Algebra-class.com Unit 1: Solving Equations 1. -6r = 84 -6r/-6 = 84/-6 Divide by -6 on both sides r = -14 Simplify: 84/-6 = -14 2. -2/3x = -14 (-3/2)-2/3x = -14(-3/2) x = 21 Multiply both sides by (-3/2) (the reciprocal of 2/3 Simplify: -14(-3/2) = 21 3. .7x = 8.4 .7x/.7 = 8.4/.7 Divide both sides by .7 x = 12 Simplify: 8.4/.7 4. 3/4y = -3/5 (4/3)3/4y = -3/5(4/3) Multiply by the reciprocal: 4/3 on both sides y = -8/10 Simplify: (-3/5)(4/3) = -8/10 5. -135 = -9y -135/-9 = 9y/-9 Divide both sides by -9 15 = y Simplify: -135/-9 = 15 Copyright© 2009 Algebra-class.com Solving Equations Lesson 4A: Writing and Solving Multiplication Equations Example 1 A local college is sponsoring a volleyball tournament. 96 people signed up to play in the tournament. How many 6 person teams can be formed? Example 2- Distance Formula D = rt Julia drove at an average rate of 62 mph on her trip to the ocean. Her total distance was 375 miles. About how many hours did Julia drive? Copyright© 2009-2014 Algebra-class.com Solving Equations Lesson 4A: Writing and Solving One-Step Multiplication Equations Directions: Write a verbal model and an algebraic equation for each problem. Then solve. 1. Lori drove for 4.5 hours while on a business trip. She traveled at total of 306 miles. At what rate did Lori travel? 2. Ashton must buy 18 gifts and he has a budget of $216. How much should each gift cost in order for Ashton to meet his budget? Over the course of a month, James earned $135 mowing 9 lawns. How much did he charge per lawn? Copyright© 2009-2014 Algebra-class.com Solving Equations Lesson 4A: Writing and Solving One-Step Addition Multiplication Answer Key Directions: Write a verbal model and an algebraic equation for each problem. Then solve. 1. Lori drove for 4.5 hours while on a business trip. She traveled at total of 306 miles. At what rate did Lori travel? This problem can utilize the distance formula. Distance – rate(time) D=rt D = 306 miles 306 = r(4.5) or T = 4.5 hours or D=rt R= ? 4.5r = 306 This is the equation 4.5/4.5r = 306/4.5 Divide both sides by 4.5 r = 68 miles/hour Lori drove at a rate of 68 miles/hour. 2. Ashton must buy 18 gifts and he has a budget of $216. How much should each gift cost in order for Ashton to meet his budget? Let’s first write a verbal model and identify our variable. 18 gifts · ( price of gifts) = total budget of 216 Let x = cost of each gift 18x = 216 Equation 18/18x = 216/18 Divide by 18 on both sides x = 12 Each gift should $12 in order for Ashton to meet his budget. Over the course of a month, James earned $135 mowing 9 lawns. How much did he charge per lawn? Let’s first write a verbal model and identify our variable. 9 lawns · (charge per lawn) = total earned Let x = amount charged per lawn 9x = 135 Equation 9/9x = 135/9 Divide by 9 on both sides x = 15 James charged $15 per lawn. Copyright© 2009-2014 Algebra-class.com