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Math 34B 2012 Quiz 2 Answers 1. Integrate the functions (a) Z x −4 x−3 +C, dx = − 3 (5 points) (b) Z cos(x)dx = sin(x) +C, (5 points) (c) Z 1 1 1 (3x5 − 2x3 + x − 1)dx = x6 − x4 + x2 − x +C, 2 2 2 (5 points) 2. Compute the indefinite integrals (a) Z 1 (2x + 4)3 dx = (2x + 4)4 +C, 8 (5 points) (b) Z x + 1/3 1p 2 √ dx = 3x + 2x + 4 +C, 3 3x2 + 2x + 4 (5 points) (c) Z sin2 (x)dx = Z 1 1 1 (1−cos(2x))dx = x− sin(2x)+C, 2 2 4 (d) Z 2x exp(x2 )dx = exp(x2 ) +C, 1 (5 points) (5 points) 3. Compute the definite integrals (a) (5 points) Z π/2 π/2 −π/2 sin(x)dx = − cos(x)|−π/2 = − cos(π/2) + cos(−π/2) = 0. (b) (5 points) Z 1 x + 1/3 0 3x2 + 2x + 4 dx = 1 1 ln(3x2 + 2x + 4)|10 = [ln(9) − ln(4)] 6 6 (c) (5 points) √ 1 1 1 1 [√ − e6x ]dx = [2 x + 1 − e6x ]|1−1 = 23/2 − e6 + e−6 6 6 6 x+1 −1 Z 1 (d) (5 points) Z 1 0 1 1 (3x2 + 2)(x3 + 2x + 5)3 dx = (x3 + 2x + 5)4 |10 = [84 − 54 ] 4 4 4. (6 points) Solve the differential equation 1 dF = e4x , F(x) = e4x +C dx 4 Find the solution F(x) that satisfies the initial condition F(0) = 14 . 1 F(x) = e4x , C = 0 4 5. (6 points) Draw the graph of the oscillatory function f (t) = e−t [cos(t) + sin(2t)] over the interval 0 ≤ t ≤ π. Notice that sin and cos have different frequency and the exponential function is decaying so the amplitude of the oscillation decays. 2 6. (6 points) Solve the differential equation dF 1 1 = , F(x) = ln(2x + 1) +C dx 2x + 1 2 Find the solution F(x) that satisfies the initial condition F(0) = 0. F(x) = 1 ln(2x + 1), C = 0 2 7. (6 points) Compute the left Riemann integral of f (x) = x, over the interval x ∈ [0, 1], by using 5 subintervals. 4 AL = 4 f (xk )∆x = ∑ k=1 ∑ k∆x · ∆x = [1 + 2 + 3 + 4]/25 = 10/25 = 2/5 k=1 Draw your approximation to the area. 8. (7 points) Find the area of the region between the graph of the function f (x) = x2 and the x axis, over the interval [0, 1] Z 1 A= x2 dx = 0 x3 1 1 | = 3 0 3 Draw the region. 9. (7 points) Find the area under the graph of f (x) = cos(x) and the x axis, over the interval [−π/2, π/2]. Z π/2 A= −π/2 π/2 cos dx = sin(x)|−π/2 = sin(π/2) − sin(−π/2) = 2 Draw the region. 10. (7 points) Find the area under the graph of f (t) = over the interval [0, 1]. A= Z 1√ 0 √ t − √1t and the t axis, 1 2 4 2 [ t − √ ]dx = [ t 3/2 − 2t 1/2 ]|10 = − 2 = − 3 3 3 t Draw the region. 3