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Problem 18.9 The combined mass of the motorcycle and rider is 160 kg. The rear wheel exerts a 400-N horizontal force on the road, and you can neglect the horizontal force exerted by the front wheel. Modeling the motorcycle and its wheels as a rigid body, determine (a) the motorcycle’s acceleration and (b) the normal forces exerted on the road by the rear and front wheels. 660 mm A B 660 mm 1500 mm Solution: The friction force on the rear wheel is F = 400 N. From Newton’s second law, the acceleration is a= F 400 = = 2.5 m/s2 . m 160 The sum of the forces in the y direction is 660 mm Fy = NA + NB − mg = 0. 660 mm 1500 mm The moment about the center of mass is MCM = −0.66NA + (1.5 − 0.66)NB + 0.66(400) = 0. Solve these two equations in two unknowns: NA = 1055 N , NB = 514.6 N F mg NA NB