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LAHPA11FLCRB_c05_225-234.qxd LESSON 1/23/09 1:52 PM Page 229 Name Date 5.1 Review for Mastery For use with pages 221–226 GOAL Write fractions as decimals and vice versa. VOCABULARY EXAMPLE Lesson 5.1 A rational number is a number that can be written as a quotient of two integers. In a terminating decimal, the division ends because you obtain a final remainder of zero. In a repeating decimal, a digit or block of digits in the quotient repeats without end. 1 Identifying Rational Numbers Show that the number is rational by writing it as a quotient of two integers. 2 7 5 12 c. 8 b. 3 a. 9 Solution 9 1 a. Write the integer 9 as . 41 12 5 12 b. Write the mixed number 3 as the improper fraction . 2 7 2 7 2 7 58 7 c. Think of 8 as the opposite of 8 . First write 8 as . Then you can 2 7 58 7 58 7 write 8 as . To write as a quotient of two integers, you can assign the negative sign to either the numerator or the denominator. You can 58 7 58 7 write or . Exercises for Example 1 Show that the number is rational by writing it as a quotient of two integers. 1. 84 EXAMPLE 2. 12 8 17 2 9 4. 5 3. 2 2 Writing Fractions as Decimals 7 8 a. Write as a decimal. Solution a. 0.875 87.0 00 64 60 56 40 40 0 Copyright © Holt McDougal. All rights reserved. 4 11 b. Write as a decimal. b. The remainder is 0, so the decimal is a terminating decimal: 7 0.875. 8 0.3636. . . 114.0 000 33 70 66 40 33 70 Use a bar to show the repeating digits in the repeating decimal: 4 0.36 ww. 11 Pre-Algebra Chapter 5 Resource Book 229 LAHPA11FLCRB_c05_225-234.qxd LESSON 1/23/09 1:52 PM Page 230 Name Date 5.1 Review for Mastery Continued For use with pages 221–226 Exercises for Example 2 Write the fraction or mixed number as a decimal. 4 9 4 5 Lesson 5.1 5. EXAMPLE 8 11 8. 3 Writing Terminating Decimals as Fractions 9 10 a. 0.9 31 100 b. 0.31 EXAMPLE 9 16 7. 2 6. 1 Place value of 9 is tenths, so denominator is 10. Place value of 1 is hundredths, so denominator is 100. 4 Writing a Repeating Decimal as a Fraction To write 0.45 ww as a fraction, let x 0.45 ww. ww has 2 repeating digits, multiply each side of x 0.45 ww by 102, (1) Because 0.45 or 100. Then 100x 45.45 ww. ww 100x 45.45 (2) Subtract x from 100x. (x 0.45 ww ) 99x 45 (3) Solve for x and simplify. 99x 45 99 99 5 11 x 5 11 Answer: The decimal 0.45 ww is equivalent to the fraction . Exercises for Examples 3 and 4 Write the decimal as a fraction or mixed number. 9. 0.25 230 Pre-Algebra Chapter 5 Resource Book 10. 0.32 ww 11. 3.1w 12. 7.325 Copyright © Holt McDougal. All rights reserved. FOCUS ON Name Date 5.1 Review for Mastery For use with pages 227–228 GOAL Determine whether mathematical statements are true or false. VOCABULARY EXAMPLE 5.1 Focus On Reasoning When you make a conclusion based on several examples, you are using inductive reasoning. A conclusion reached using inductive reasoning is a conjecture. A conjecture is a statement that is thought to be true but not yet shown to be true. The process of starting with one or more given facts and using rules, definitions, or properties to reach a conclusion is called deductive reasoning. 1 Using Inductive Reasoning Consider fractions whose denominators are powers of 3, such as 3, 9, and 27. Make a conjecture about the decimal form of such fractions. Solution Find a pattern using a few examples. ⎯ ⎯ 1 1 0.3 0.1 3 9 ⎯⎯⎯ 1 0.037 27 Conjecture: The decimal form of any fraction whose denominator is a power of 3 is a repeating decimal. EXAMPLE 2 Using Deductive Reasoning Give a convincing argument to show that the conjecture in Example 1 is true. Solution The decimal system is based on powers of 10, and the decimal form of any fraction whose denominator is a power of 10 is a terminating decimal. A fraction whose denominator is a power of 3 cannot be rewritten as a fraction whose denominator is a power of 10. Powers of 10 and powers of 3 do not share common factors. So, no power of 10 is divisible by a power of 3. Thus, the decimal form of any fraction whose denominator is a power of 3 is a repeating decimal. 1 729 1 3 For instance, because 6 , its decimal form is repeating. Copyright © Holt McDougal. All rights reserved. Pre-Algebra Chapter 5 Resource Book 233 LAHPA11FLCRB_c05_225-234.qxd FOCUS ON 1/23/09 1:52 PM Page 234 Name Date 5.1 Review for Mastery Continued For use with pages 227–228 Exercise for Examples 1 and 2 5.1 Focus On Reasoning 1. Make a conjecture about the sum of two odd integers. Give a convincing argument to show that the conjecture is true. EXAMPLE 3 Using a Counterexample Show that a conjecture is false by finding a counterexample. Conjecture: The decimal form of any fraction whose denominator is a prime number is a repeating decimal. Solution Write fractions whose denominators are prime as decimals. ⎯ 1 1 0.3 0.2 3 5 Because a counterexample exists, the conjecture is false. Exercises for Example 3 Show that the conjecture is false by finding a counterexample. 2. All even numbers are composite. 3. The difference of any two positive numbers is positive. 4. All powers of 3 are divisible by 9. 234 Pre-Algebra Chapter 5 Resource Book Copyright © Holt McDougal. All rights reserved. Answers Answers 36. Decimal form. Using fractions, you would Lesson 5.1 have to change each fraction to an equivalent form with the same denominator before you could compare the values. Using decimals, you can just compare place values. Practice A 1. repeating decimal 2. terminating decimal 3. terminating decimal 4. repeating decimal 38 5 7 14 38 14 5. or 6. 7. 8. or 9 1 3 9 1 1 45 9 58 1 58 9. 10. or 11. or 1 100 20 1 10 9 9 12. or 13. 0.75 14. 0.8w 15. 7.6 14 14 16. 2.16w 11 25. 5 2 0 99 7 11 32. 27. 9 368 4. 15 24. 1 100 8 28. 33 29. > 1 1 33. 0.02, 5, 0.25, 2, 2 2 7 34. 3, 3.6, 2, 3, 0.3 w 2 5 7 Practice B 19. 23. 27. 30. 31. 32. 34. A32 6. 0.516 7. 8.28 w 10. 64.75 11. 5.84 ww 12. 17.325 13. 9.2w 14. 0.897 www 15. 10.111 16. 7.108 w 17. 200 18. 1 200 101 18 1 41 19. 143 9 31 21. 400 20. 99 22. 6 125 1 428 24. 9 495 23. 990 111 157 9 5 8 25. 2, 2 1 , , , , 2.8 0 4 2 3 1 11 26. 1 , 0, 0.19, 4, 0.25 ww, 4 0 0 22 7 25 3 27. 3, 6 8, 6.34, 4, 6, 5 4 28. 10 29. 2.5 30. 6 12. 8.15 16. 2.225 31. Sample answer: 2 5 69 10 121 32. Sample answer: 100 63 555 555 6. or 1 1 33. 0.8631; 8 ; 0.8631 is closer to 1. 1 0.32 10. 0.27 w Review for Mastery 13. 11.3 w 14. 7.25 17. 0.38 w 18. 1.5 1 5.93w 20. 10.194 w 22. 2 5 4 1 7 16 25. 8 26. 5 25 24. 14 9 200 99 23 27 6 2 15 28. 3 30 29. 0.5 w, 0.55, 11 , 50 1 13 17 , 0.6, , , 0.69 2 20 25 11 7 8 6, 4, 1.7, 5, 1.5, 0.8 w 1 17 43 4.02, 4.1, 4 5, 4, 10, 4.41 33. Monday 7 2 0.28, terminating; 0.4, terminating; 25 5 1 0.07, terminating; 12 0.083 w, repeating; 7 100 1 6 133 133 3. or 9 9 92 86 273 86 1. 2. or 3. 1 1 1 3400 109 109 4. or 5. 1 12 12 47 47 67 7. or 8. 9. 20 20 14 15. 6.37 9. 21.2 1 35. 3 0.6 w, 8 0.625, 10 0.7; Sam lives the farthest from school. 36. chemistry book 11. 3.18 ww 5. 0.7625 8. 3.483 w 43 4 23. 3 5 100 100 2. or 1 1 3691 1. 1 19. 1.53 w 22. 50 26. 100 31. < 18. 2.5 19 3 21. 2 0 20. 4.05 30. > 17. 3.6 Practice C 13 21. 2 0 0.16 w, repeating 35. banana Pre-Algebra Chapter 5 Resource Book 84 84 1. or 1 1 5. 0.4 w 1 9. 4 6. 1.8 32 12 2. 1 42 3. 17 7. 2.5625 1 10. 9 9 11. 3 9 47 47 4. or 9 9 8. 0.72 ww 13 12. 7 4 0 Challenge Practice 8 1. 9 54 2. 2 9 9 1.13w, 1.03 ww, 1.3 6. > 7. < 901 4 4. , 1.30 3. 6 ww, 999 3 5. 0.06, 0.06 w, 0.60 ww, 0.606 www, 0.6 w 8. < 2 9. Sample answer: 3 234 10. Sample answer: 100 Focus On Reasoning 5.1 Practice 1. The product of two prime numbers is a composite number; A composite number is divisible by at least one number other than itself Copyright © Holt McDougal. All rights reserved. Lesson 5.1 continued 5. 1 centimeter = 100 millimeters. To a convert a length in centimeters to a length in millimeters, the centimeter length is multiplied by 100. Any whole number multiplied by 100 is a whole number. (x 1) = 7 and (x 3) = 9. Their sum is 2x 4, or 16, which is an even integer. 2. 2 3. 1 2 1 4. 30 9 0.1 Lesson 5.2 Practice A 1. 12 2. 4 1 7 8. 3 4 4 12. 1 1 1 1 4 Practice B 11 7. 2 3 5 6. 25 4 13 2. 5 1 3. 1 6 21 3 2 5 11. 4 3 12. 11 9 5 15. 2 16. 5 17. 8 7 20. x 21. 22. x 5 3 8. 40 7. 5 3 2 5. 15 4. 1 4 3 1 10. 1 7 9. 12 5 3 6 13. 8 1 14. 4 5 1 4 6x 5x 18. 19. 7x 5 7 1 4 3 23. 24. 12x 3x x 1 27. 14 1 31. 3 1 4 12 7 12 7 3; 2 26. 1 8 1 4 28. 1 7 12. (3)3 27 25. 1 1 2 13. 27 6 4.5 29. 1 9 14. 1 because 7 3 < 7 4, you have enough wood. 15. (1)5 1 32. 2 sec faster 16. no; 1 0 1 0 Review for Mastery 1. The sum of two odd integers is an even integer; For any even integer x, the integers (x 1) and (x 3) are consecutive odd integers. The sum of (x 1) and (x 3) = (2x 4). The integer (2x 4) is even: 2x is even because any multiple of 2 is even; adding 4 is the same as adding 2 2, so 2x 4 is a multiple of 2. For instance, if x 6, Copyright © Holt McDougal. All rights reserved. 5 7. 7 14. 4 2 15. 5 16. 10 7 17. 5 3 x 1 2x 18. 9 19. 5 20. 1 21. 22. 2 5 5 x 5 4x 10 4 23. 24. 25. 26. 27. 5 3x 9 x x 15 3 1 28. 29. ft 30. 4 mi 31. 1 mi 8x 4 2 13. 8 5 6. (2)(2) 4 11. 3 p 1 3 3 6. 5 11. 1 1 3 10. 1 4 1 1 5. 2 4. 4 3 9. 8 1. 1 13 8. 10 4 2.5 2 9. 2 10. 3 p 4 12 3. 7 4 30. 4 2 7 1 8 2 3 1 3 33. 3 1 lb 6 Practice C 12 2 1 3. 1 4. 2. 125 29 1 13 14 6. 51 7. 8. 33 5 50 33 4x 4 11. 0 12. 13. 14. 19 3x 1. 5 2 25 18. 28 17. 5 16. 0 1 21. 5 5 4 22. 9 2 32 125 9. 3 2x 13 19. 40 8 19 5. 4 25 x 2x 10. 10 3 17 15. 5x 29 20. 33 2 24. 1 25. 7 3 Pre-Algebra A33 Chapter 5 Resource Book 23. 5 Answers and 1. Suppose p is the product of two prime numbers m and n. Besides being divisible by itself and 1, p must also be divisible by m and n. 2. The product of two even numbers is always even; The product of an even number and any number will contain 2 as part of its prime factorization and thus be divisible by 2, or even. 3. The factors of an odd product must both be odd; Every even number is a multiple of 2. The product of an even number and any number will contain 2 as part of its prime factorization and thus be divisible by 2, or even. So, the factors of an odd product must both be odd. 1 2 3 4 4. The decimal forms of , , , and form 8 8 8 8 an arithmetic sequence with a common difference of 0.125. This is because the decimal form of 18 is 0.125, and each successive number in the sequence is 18 more than the number before it.