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Scholarship Algebra II 1-4: Solving Inequalities Day 1 Properties of Inequalities Let a, b, and c represent real numbers. Transitive Property If a " b and b " c , then a " c . Addition Property If a " b , then a + c " b + c . Subtraction Property If a " b , then a " c # b " c . Multiplication Property If a " b and c > 0 , then ac " bc . ! ! ! If a " b and c < 0 , then ac " bc . ! ! a b Division Property If a!" b and c > 0 , then " . ! c c ! ! ! a b ! < 0 , then " . a " b and c ! If ! c c ! ! ! Ex. 1: ! ! Solve and graph the inequality. ! 14 " 4 y # 38 -7 -6 -5 -4 -3 -2 -1 0 1 2 Ex. 2: Solve and graph the inequality. 2(m " 3) + 7 < 21 2(m " 3) < 21" 7 3 14 m"3< 2 m < 7+ 3 m < 10 4 5 6 7 8 9 10 11 12 "4 y # 38 "14 24 y$ "4 y $ "6 ! ! Ex. 3: Solve and graph the inequality. 9( x + 2) > 9( x " 3) x+2> x"3 2 > "3 All real numbers are solutions. ! Ex. 4: Solve and graph the inequality. "6(2x "10) + 12x # 180 "12x + 60 + 12x # 180 60 # 180 No real solutions. ! Ex. 5: Solve and graph the inequality. 2 ( x "12) < x + 8 3 2(x "12) < 3(x + 8) 2x " 24 < 3x + 24 "48 < x ! -54 -52 -50 -48 -46 Ex. 6: The length of a picture frame is 3 in. greater than the width. The perimeter is less than 52 in. Describe the possible dimensions. x 2x + 2( x + 3) < 52 x+3 ! 2x + 2x + 6 < 52 4 x < 46 x < 11.5 The width is less than 11.5 in. and greater than 0 in. The length is 3 in. longer than the width, so it is between 3 in. and 14.5 in. Ex. 7: Find the lesser of two consecutive integers whose sum is greater than 16. x + (x + 1) > 16 2x + 1 > 16 2x > 15 x > 7.5 ! The smallest pair of consecutive integers that meets the condition is 8, 9. There are many other possibilities (any integer equal to or greater than 8).