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Section 7.3 Multiplying and Simplifying Radical Expressions Copyright © 2013, 2009, 2006 Pearson Education, Inc. 1 Objective #1 Use the product rule to multiply radicals. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 2 Multiplying Radicals The Product Rule for Radicals If n a and n b are real numbers, then n a ⋅ n b = n ab . The product of two nth roots is the nth root of the product of the radicands. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 3 Multiplying Radicals EXAMPLE 4 Multiply: (a) 3 5 ⋅ 3 4 (b) 6 x − 5 ⋅ 6 (x − 5) . SOLUTION In each problem, the indices are the same. Thus, we multiply the radicals by multiplying the radicands. (a) 3 5 ⋅ 3 4 = 3 5 ⋅ 4 = 3 20 (b) 6 x − 5 ⋅ 6 ( x − 5) = 6 ( x − 5)( x − 5) = 6 ( x − 5) 4 4 5 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 4 Objective #1: Example 1a. Multiply: 5 ⋅ 11 5 ⋅ 11 = 5 ⋅11 = 55 1b. Multiply: x + 4 ⋅ x − 4= = x + 4⋅ x − 4 ( x + 4)( x − 4) x 2 − 16 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 5 Objective #1: Example 1a. Multiply: 5 ⋅ 11 5 ⋅ 11 = 5 ⋅11 = 55 1b. Multiply: x + 4 ⋅ x − 4= = x + 4⋅ x − 4 ( x + 4)( x − 4) x 2 − 16 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 6 Objective #1: Example 1c. Multiply: 7 7 7 7 2 x ⋅ 6 x3 7 2 x ⋅ 6 x3 = 12 x 4 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 7 Objective #1: Example 1c. Multiply: 7 7 7 7 2 x ⋅ 6 x3 7 2 x ⋅ 6 x3 = 12 x 4 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 8 Objective #2 Use factoring and the product rule to simplify radicals. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 9 Simplifying Radicals Simplifying Radical Expressions by Factoring A radical expression whose index is n is simplified when its radicand has no factors that are perfect nth powers. To simplify, use the following procedure: 1) Write the radicand as the product of two factors, one of which is the greatest perfect nth power. 2) Use the product rule to take the nth root of each factor. 3) Find the nth root of the perfect nth power. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 10 Simplifying Radicals EXAMPLE 2 3 Simplify by factoring: (a) 28 (b) 3 − 32 x y . SOLUTION (a) 28 = 4 ⋅ 7 = 4⋅ 7 =2 7 ( ) (b) 3 − 32 x 2 y 3 = 3 − 8 y 3 4 x 2 4 is the greatest perfect square that is a factor of 28. Take the square root of each factor. Write 4 as 2. − 8y 3 is the greatest perfect cube that is a factor of the radicand. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 11 Simplifying Radicals CONTINUED = 3 − 8 y3 ⋅ 3 4x2 Factor into two radicals. = −2 y 4 x Take the cube root of − 8 y 3 . 3 2 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 12 Simplifying Radicals EXAMPLE 3 If f (x ) = 3 48(x − 2) , express the function, f, in simplified form. SOLUTION Begin by factoring the radicand. There is no GCF. f (x ) = 3 48(x − 2 ) 3 This is the given function. = 3 6 ⋅ 8( x − 2 ) 3 Factor 48. = 6 ⋅ 2 (x − 2) 3 3 Rewrite 8 as 23. 3 = 3 6 ⋅ 3 23 ⋅ 3 ( x − 2 ) Take the cube root of each factor. = 2( x − 2 ) 3 6 Take the cube root of 23 and (x − 2)3 . 3 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 13 Simplifying Radicals Simplifying When Variables to Even Powers in a Radicand Are Nonnegative Quantities For any nonnegative real number a, n a n = a. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 14 Simplifying Radicals EXAMPLE Simplify: 40 x 3 . SOLUTION We write the radicand as the product of the greatest perfect square factor and another factor. Because the index of the radical is 2, variables that have exponents that are divisible by 2 are part of the perfect square factor. We use the greatest exponents that are divisible by 2. Use the greatest even power of 40 x 3 = 4 ⋅10 ⋅ x 2 ⋅ x each variable. = (4 ⋅ x )(10 x ) 2 = 4 x 2 ⋅ 10 x Group the perfect square factors. Factor into two radicals. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 15 Simplifying Radicals CONTINUED = 2 x 10 x Simplify the first radical. Remember – we take the principal root which is the positive root if there is a choice between a negative and a positive. Odd roots of a negative number are negative and we don’t have a choice. When we take the even root of a positive number – we could argue that we might get either a negative or a positive. But we take the positive, for that is the principal root. Since we don’t know the sign of the variable x in this problem and x could be either negative or positive – we put absolute value bars around the x to assure that we have chosen the positive root. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 16 Simplifying Radicals EXAMPLE Simplify: 4 96 x11 . SOLUTION We write the radicand as the product of the greatest 4th power and another factor. Because the index is 4, variables that have exponents that are divisible by 4 are part of the perfect 4th factor. We use the greatest exponents that are divisible by 4. 4 96 x11 = 4 16 ⋅ 6 ⋅ x 8 ⋅ x 3 ( )( ) Identify perfect 4th factors. = 4 16 x 8 6 x 3 Group the perfect 4th factors. = 4 16 x 8 ⋅ 4 6 x 3 Factor into two radicals. = 2 x 2 ⋅ 4 6 x3 Simplify the first radical. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 17 Objective #2: Example 2a. Simplify by factoring: 3 40 = 3 8⋅5 = 3 8⋅ 3 5 3 40 = 23 5 2b. Simplify by factoring: 200 = x2 y 200x 2 y 100 x 2 ⋅ 2 y = 10 x 2 y Copyright © 2013, 2009, 2006 Pearson Education, Inc. 18 Objective #2: Example 2a. Simplify by factoring: 3 40 = 3 8⋅5 = 3 8⋅ 3 5 3 40 = 23 5 2b. Simplify by factoring: 200 = x2 y 200x 2 y 100 x 2 ⋅ 2 y = 10 x 2 y Copyright © 2013, 2009, 2006 Pearson Education, Inc. 19 Objective #2: Example 2c. Express the function f ( x)= f ( x)= 3 x 2 − 12 x + 12 = 3( x 2 − 4 x + 4) = 3 x 2 − 12 x + 12 in simplified form. 3( x − 2) 2 = 3 ⋅ ( x − 2) 2 = 3⋅ x − 2 f ( x)= x − 2 3 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 20 Objective #2: Example 2c. Express the function f ( x)= f ( x)= 3 x 2 − 12 x + 12 = 3( x 2 − 4 x + 4) = 3 x 2 − 12 x + 12 in simplified form. 3( x − 2) 2 = 3 ⋅ ( x − 2) 2 = 3⋅ x − 2 f ( x)= x − 2 3 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 21 Simplifying Radicals For Examples 2d and 2e and the remainder of this chapter, in situations that do not involve functions, we will assume that no radicands involve negative quantities raised to even powers. Based upon this assumption, absolute value bars are not necessary when taking even roots. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 22 Objective #2: Example x9 y11z 3 2d. Simplify: = x9 y11z 3 x8 y10 z 2 ⋅ xyz = x 4 y 5 z xyz 2e. Simplify: 3 3 40 x10 y14 = 40x10 y14 3 8 ⋅ 5 ⋅ x9 ⋅ x ⋅ y12 ⋅ y 2 = 3 8 x9 y12 3 5 xy 2 = 2 x3 y 4 3 5 xy 2 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 23 Objective #2: Example x9 y11z 3 2d. Simplify: = x9 y11z 3 x8 y10 z 2 ⋅ xyz = x 4 y 5 z xyz 2e. Simplify: 3 3 40 x10 y14 = 40x10 y14 3 8 ⋅ 5 ⋅ x9 ⋅ x ⋅ y12 ⋅ y 2 = 3 8 x9 y12 3 5 xy 2 = 2 x3 y 4 3 5 xy 2 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 24 Objective #3 Multiply radicals and then simplify. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 25 Multiplying Radicals EXAMPLE Multiply and simplify: (a) 4 4 x 2 y 3 z 3 ⋅ 4 8 x 4 yz 6 (b) 5 8 x 4 y 3 z 3 ⋅ 5 8 xy 9 z 8 . SOLUTION (a) 4 4 x 2 y 3 z 3 ⋅ 4 8 x 4 yz 6 = 4 4 x 2 y 3 z 3 ⋅ 8 x 4 yz 6 Use the product rule. = 4 32 x 6 y 4 z 9 Multiply. = 4 16 ⋅ 2 x 4 x 2 y 4 z 8 z Identify perfect 4th factors. ( )( = 4 16 x 4 y 4 z 8 2 x 2 z ) = 4 16 x 4 y 4 z 8 ⋅ 4 2 x 2 z Group the perfect 4th factors. Factor into two radicals. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 26 Multiplying Radicals CONTINUED = 2 xyz 2 4 2 x 2 z Factor into two radicals. (b) 5 8 x 4 y 3 z 3 ⋅ 5 8 xy 9 z 8 = 5 8 x 4 y 3 z 3 ⋅ 8 xy 9 z 8 Use the product rule. = 5 64 x 5 y12 z11 Multiply. = 5 32 ⋅ 2 x 5 y10 y 2 z10 z Identify perfect 5th factors. ( )( = 5 32 x 5 y10 z10 2 y 2 z ) Group the perfect 5th factors. = 5 32 x 5 y10 z10 ⋅ 5 2 y 2 z Factor into two radicals. = 2 xy 2 z 2 5 2 y 2 z Simplify the first radical. Copyright © 2013, 2009, 2006 Pearson Education, Inc. 27 Objective #3: Example 3a. Multiply and simplify: 6⋅ 2 6⋅ 2 = 12 = 4⋅3 = 4⋅ 3 =2 3 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 28 Objective #3: Example 3a. Multiply and simplify: 6⋅ 2 6⋅ 2 = 12 = 4⋅3 = 4⋅ 3 =2 3 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 29 Objective #3: Example 3b. Multiply and simplify: 10 3 16 ⋅ 5 3 2 10 3 16 ⋅ 5 3 2= 50 3 16 ⋅ 2 = 50 3 32 = 50 3 8 ⋅ 4 = 50 3 8 ⋅ 3 4 = 50 ⋅ 2 ⋅ 3 4 = 100 3 4 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 30 Objective #3: Example 3b. Multiply and simplify: 10 3 16 ⋅ 5 3 2 10 3 16 ⋅ 5 3 2= 50 3 16 ⋅ 2 = 50 3 32 = 50 3 8 ⋅ 4 = 50 3 8 ⋅ 3 4 = 50 ⋅ 2 ⋅ 3 4 = 100 3 4 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 31 Objective #3: Example 3c. Multiply and simplify: 4 4 4 x 2 y ⋅ 4 8 x6 y3 4 4 x 2 y ⋅ 4 8 x6 y3 = 32 x8 y 4 = 4 16 x8 y 4 ⋅ 4 2 = 2 x2 y 4 2 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 32 Objective #3: Example 3c. Multiply and simplify: 4 4 4 x 2 y ⋅ 4 8 x6 y3 4 4 x 2 y ⋅ 4 8 x6 y3 = 32 x8 y 4 = 4 16 x8 y 4 ⋅ 4 2 = 2 x2 y 4 2 Copyright © 2013, 2009, 2006 Pearson Education, Inc. 33