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DOWEN COLLEGE LAGOS ONLINE SCHOOL ACTIVITY WEEK 2 LESSON JS2 Subject :mathematics Topic : standard form Definition: all numbers written in the form A x 10n where A is the number between 1 and 10 and n is a whole number are called numbers in standard form. Standard forms are sometimes called scientific notation. Numbers greater than 1 Example ( a ) 20000 = 2 x 10000 = 2 x 104 ( b ) 450 = 4.5 x 100 = 4.5 x 102 ( c ) 630000 = 6.3 x 100000 = 6.3 x 105 Task 1 Express the following numbers in standard form. ( I ) 8000 ( ii ) 170000 ( iii ) 950 ( iv ) 70 ( v ) 57 Numbers less than 1 Decimal fractions such as 0.001 and 0.000001 can be express as power of 10 for example. ( 1 ) 0.00001 = = = 10 – 5 ( 2 ) 0.0003 = = = = 3 x 10 – 4 DOWEN COLLEGE LAGOS ONLINE SCHOOL ACTIVITY ( 3 ) 0.0026 = = 2.6 x 10 – 3 = Task 2 Express the following in standard form. ( I ) 0.0006 ( ii ) 0.06 ( iii ) 0.4 ( iv ) 0.0052 ( v) 0,066 Expressing numbers in decimal fraction Example ( a ) 7 x 10 – 1 ( b ) 9.2 x 10 – 3 ( c ) 5.6 x 10 – 6 ( a ) 7 x 10 – 1 = ( b ) 9.2 x 10 – 3 = ( c ) 5.6 x 10 – 6 = = 0.7 = 0.0092 = 0.0000056 Addition and Subtraction in standard form In order to add or subtract expressions in standard form, the powers of 10 must be made equal. Example ( a ) 6.08 x 10 7 + 3.01 x 10 7 ( b ) 9.4 x 105 - 6.7 x 10 5 ( c ) 0.0065 + 0.003 ( d ) 0.000006 - 0.0000024 ( e ) 2.5 x106 +5.3 x 106 – 3.4 x 106 Solution DOWEN COLLEGE LAGOS ONLINE SCHOOL ACTIVITY ( a ) 6.08 x 10 7 + 3.01 x 10 7 = ( 6.08 + 3.01 ) x 107 = 9.09 x 107 Since 107 is common ( b ) 9.4 x 105 - 6.7 x 10 5 = ( 9.4 - 6.7 ) x 105 = 2.7 x 105 ( c ) 0.0065 + 0.003 = 6.5 x 103 + 3 x 103 = ( 6.5 + 3 ) x 103 = 9.5 x 103 (d ) 0.000006 - 0.0000024 = 6 x 10 – 6 - 2.4 x 10 – 6 = ( 6 – 2.4 ) x 10 – 6 ( e ) 2.5 x 10 6 + 5.3 x 106 – 3.4 x 10 6 = ( 2.5 + 5.3 – 3.4 ) x 10 6 Multiplication and Division in Standard form The process of multiplication and division follows similar rules as in operation of indices. e.g if P = A X 10x and Q = B x 10y PQ = A X 10x X B x 10y = AB X 10 x + y Also in division of P ÷ Q or = = X = 10 x – y Example ( a ) simplify ( 1.6 x 109 ) x ( 2.5 x 10 6 ) = ( 1.6 x 2.5 ) x 109 + 6 = 4 x 1015 ( b ) 5.8 x 10 16 ÷ 1.4 x 1011 = ( 5.8 ÷ 1.4 ) x 10 16 – 11 = 4.143 x 10 5 DOWEN COLLEGE LAGOS ONLINE SCHOOL ACTIVITY ASSIGNMENT 1 New General Mathematics Book 2 ( a ) Page 26 exercise 2e ( question 1, 8, 10, 21, 24 ) ( b ) Page 27 exercise 2f ( question 1, 5, 11, 20, 24 ) ( c ) Page 27/28 exercise 2g ( question 1, 2, 16, 17, 24 ) ( d ) Page 26 exercise 2e ( question 1, 8, 14, 22, 24 ) ASSIGNMENT 2 ( a ) simplify ( 2.5 x 109 ) x ( 3 x 104 ) ( b ) simplify ( 4.6 x 108 ) ÷ ( 1.5 x 103 ) ( c ) 4.2 x 106 + 2.1 x 106 ( d ) 3.1 x 104 + 1.2 x 104 – 3.2 x 104 Kindly solve the tasks and assignment and forward the solution to: [email protected] or [email protected] (08025949100) Submission should not be later than Wednesday 17th of September 2014. NOTE : these will form part of your continuous assessment for first term. DOWEN COLLEGE LAGOS ONLINE SCHOOL ACTIVITY