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Chapter 3 Complex numbers 129 remember remember 1. The magnitude (or modulus or absolute value) of z = x + yi is the length of the line segment from (0, 0) to z and is denoted by ⏐z⏐, ⏐x + yi⏐ or mod z. 2. ⏐z⏐ = 3. 4. 5. 6. x 2 + y 2 and zz = z 2 . y arg z = θ where tan θ = -- . x n z × i , n ∈ N produces an anticlockwise rotation of 90n degrees. z = r cos θ + r sin θ i = r cis θ in polar form. Arg z is the angle θ in the range −π < θ ≤ π. 3D Complex numbers in polar form In the following exercise give arg z or Arg z correct to three decimal places where it is not easily expressed as a multiple of π. Example xample 17 2 Find the modulus of each of the following. a z = 5 + 12i b z = 5 – 2i d z = −3 − 6i WORKED ORKED Example xample 18 WORKED ORKED Example xample 19 e z= 3 + 2i c z = −4 + 7i f z = (2 + i)2 3 If z = 3 + i, w = 4 − 3i and u = −2 + 5i then: i represent each of the following on an Argand diagram ii calculate the magnitude in each case. a z−w b u+z c d w+z e z+w−u f w−u z2 4 a Show the points z1 = −3 + 0i, z2 = 2 + 5i, z3 = 7 + 5i and z4 = 9 + 0i on the complex number plane. b Calculate the area of the shape formed when the four points are connected by straight line segments in the order z1 to z2 to z3 to z4 and back to z1. 5 a Show the points z = −1 + 3i, u = 3 and w = 3 + 12i on the complex number plane. b Calculate the area of the triangle produced by joining the three points with straight line segments. WORKED ORKED Example xample 20 6 Find the argument of z for each of the following in the interval [0, 2π ]. (Give exact answers where possible.) a z = 3 + 2i b z= e z = −2 − 2 3i i z = −6i f z = 6 − 10i j z = 55 3+i c z = 5 − 5i g z = 3i cad Complex 1 1 a Represent z = 4 + 8i on an Argand diagram. b Calculate the exact distance of z from the origin. WORKED ORKED Math d z = −4 + 8i h z= – 7 130 WORKED ORKED Example xample 21 WORKED ORKED Example xample 22 Maths Quest 12 Specialist Mathematics 7 Convert each of the following into Arguments. 3π 11 π 15 π a -----b − --------c --------2 6 8 19 π 20 π 18 π e --------f --------g − --------6 7 5 8 Find the modulus and Argument of each of the following complex numbers. a 3 − 3i b −5 + 5i c −1 − 3i d 4 3 + 4i e −7 − 10i WORKED ORKED Example xample 23 f Example xample 24 6i − 2 g ( 3 + i )2 9 Express each of the following in polar form z = r cis θ where θ = Arg z. a z = −1 + i b z = 6 + 2i c z = – 5 – 5i d z = 5 – 15i 3 1 e z = − --- – ------- i 2 2 WORKED ORKED 5π d − -----4 13 π h − --------12 f 1 1 z = − --- + --- i 4 4 10 Express each of the following complex numbers in Cartesian form. 2π a 2 cis -----3 e π b 3 cis --4 7π 7 cis ⎛ – ------⎞ ⎝ 4⎠ f π 8 cis --2 c 5π 5 cis -----6 g 3 cis π π d 4 cis ⎛ – ---⎞ ⎝ 3⎠ 11 multiple ultiple choice If z = 3 − 50i and w = 5 + 65i the value of ⏐z + w⏐ is: A 64 B 15 C 17 D 225 E 289 12 multiple ultiple choice The perimeter of the triangle formed by the line segments connecting the points 2 − 4i, 14 − 4i and 2 + i is: A 13 B 30 C 10 D 17 E 25 13 multiple ultiple choice The Argument of 4 π A --B 6 3 – 4i is: π --3 14 multiple ultiple choice In polar form, 5i is: π A cis --B cis 5π 2 5π C -----6 π D – --6 π E – --3 5π C cis -----2 D 5 cis 5π π E 5 cis --2 –3 3 D ------ + ------- i 2 2 – 3 1 E ---------- – --- i 2 2 15 multiple ultiple choice Work ET SHE 3.1 The Cartesian form of 1 3 A --- + ------- i 2 2 7π 3 cis ⎛ – ------⎞ is: ⎝ 6⎠ –1 3 B ------ + ------- i 2 2 – 3 1 C ---------- + --- i 2 2 Chapter 3 3E Example xample Example xample Power of a complex number 2 Express the resultant complex numbers in question 1 in Cartesian form. Power of a complex number program GC 26 WORKED ORKED Example xample 27 WORKED ORKED Example xample 28 WORKED ORKED Example xample 29 WORKED ORKED Example xample 30 WORKED ORKED Example xample 31 3 Express the following products in polar form. a (2 + 2i)( 3 + i) b ( 3 − 3i)(2 3 − 2i) c (−4 + 4 3 i)(−1 − i) 4 Express each of the following in the form r cis θ where θ ∈ (−π, π ]. 5π π 3π π a 12 cis ------ ÷ 4 cis --b 36 cis ------ ÷ 9 cis ⎛ – ---⎞ ⎝ 6⎠ 6 3 4 4π 11 π π π d 4 3 cis ------ ÷ 6 cis --------c 20 cis ⎛ – ---⎞ ÷ 5 cis ⎛ – ---⎞ ⎝ 2⎠ ⎝ 5⎠ 7 14 5π 7π e 3 5 cis ⎛ – ------⎞ ÷ 2 10 cis -----⎝ 12 ⎠ 6 3π π 3 cis ------ and w = 2 cis ⎛ – ---⎞ then express each of the following in: ⎝ 4⎠ 4 i polar form ii Cartesian form. b w4 c z4 d w5 a z3 5 If z = 6 If z = 1 − i and w = – 3 + i , write the following in Cartesian form. z3 e -----4a z−4 b w−3 c z−3 d w−5 w f z2w3 7 Determine ( 2 + 2i ) 2 ( 1 – 3i ) 4 in Cartesian form. ( 3 – i )6 8 Write ----------------------------3 in the form x + yi. ( 2 – 2 3i ) 9 multiple ultiple choice π π a 5 cis ⎛ – ---⎞ × 8 cis ⎛ – ---⎞ is equal to: ⎝ 3⎠ ⎝ 6⎠ B – 2 10i A 6 2i C –6 3 b If z = ( A 1+i D −6i E 6 6 6 + 2 ) + ( 6 – 2 ) i then 64 2z –3 is: B 2i C 1−i D 2+i w4 c If z = –1 – 3i and w = 2 + 2i then -----3- is equal to: z A −4 + 4i C 2 D −4i B 2 3 E –1 – 2i E −8 am progr –C asio WORKED ORKED 1 Express each of the following in the form r cis θ where θ ∈ (−π, π ]. π π 2π π a 2 cis --- × 3 cis --b 5 cis ------ × 4 cis ⎛ – ---⎞ ⎝ 3⎠ 4 2 3 3π 5π π d 6 cis ------ × 5 cis π c 3 cis ⎛ – ------⎞ × 2 cis ⎛ – ---⎞ ⎝ 6⎠ ⎝ 2⎠ 4 5π 7π e 7 cis ⎛ – ------⎞ × 2 cis -----⎝ 12 ⎠ 12 –TI 25 Basic operations on complex numbers in polar form GC WORKED ORKED 139 Complex numbers 140 Maths Quest 12 Specialist Mathematics π z6 3π 2 cis ------ and w = 3 cis --- , find the modulus and the argument of -----4- . Example xample 4 6 w 32 11 If z = 4 + i and w = −3 − 2i, determine (z + w)9. WORKED ORKED 10 If z = 12 Find z6 + w4, if z = 13 If z 1 = 2 – 2i and w = 2 − 2i. 3π 2π 5 cis ⎛– ------ ⎞ , z 2 = 2 cis------ and z 3 = ⎝ 5⎠ 8 π 10 cis ------ , find the modulus and the 12 z 12 × z 23 argument of ------------------. 4 z3 14 By finding z4 if z = cis θ, show that cos 4θ = cos4θ − 6 cos2θ sin2θ + sin4θ and that sin 4θ = 4 cos3θ sin θ − 4 cos θ sin3θ. 33 15 Using z = r cis θ, verify that zz = z 2 . WORKED ORKED Example xample 16 If zn = (1 + i)n, determine the smallest value of n ∈ N so that zn is equal to: a ( 2 )n b –( 2 ) n c ( 2 )n i n d –( 2 ) i . Factorisation of polynomials in C A polynomial in z is an expression of the form P(z) = an zn + an − 1 zn − 1 + an − 2 zn − 2 + . . . + a1z + a0, where n ∈ N is the degree (highest power) of P(z) and an (with an ≠ 0) are the coefficients. If an ∈ R, that is, all the coefficients are real, then P(z) is said to be a polynomial over R. Similarly, if at least one of the an is complex, P(z) is said to be a polynomial over C. For example, P(z) = 3z4 − 5z2 + 6 is a polynomial of degree 4 over R and P(z) = 2iz3 + 3z2 − 8i is a polynomial of degree 3 over C. The fundamental theorem of algebra Firstly recall that R ⊂ C and the factor theorem, which states: If (x − a) is a factor of the polynomial P(x), then P(a) = 0. In 1799 the German mathematician Carl Friedrich Gauss proved that every polynomial over C has a solution that is a complex number. That is, if Pn(z) is a polynomial of degree n over C, then there exists a z0 ∈ C such that Pn(z0) = 0. This important result can be used to show that a polynomial of degree n, with n ∈ N, has n solutions. The proof relies on a repeated application of the fundamental theorem of algebra and the factor theorem. Firstly, the fundamental theorem of algebra guarantees that there is a z0 ∈ C such that Pn(z0) = 0. The factor theorem states that if Pn(z0) = 0 for some z0 then (z − z0) is a factor of Pn(z) so that Pn(z) = (z − z0)Pn − 1(z), where Pn − 1(z) is a polynomial of degree n − 1. Now by applying the fundamental theorem of algebra to Pn − 1(z) there is a z1 ∈ C such that Pn − 1(z1) = 0 and the factor theorem ensures that Pn − 1(z) = (z − z1)Pn − 2(z). 146 Maths Quest 12 Specialist Mathematics 12 Find the values of a and b (a, b ∈ R) if: a (z + 1) is a factor of z3 − 2iz2 + aiz + b 39 b (z − i) is a factor of az3 − 3z2 + biz + 12i c (z + 2i) is a factor of z3 + aiz2 + 2iz + (1 + i)b. WORKED ORKED Example xample 13 Explain why at least one of the zeros of a polynomial of degree n (where n is an odd natural number) is a real number. 14 Write down a polynomial of degree 3, whose coefficients are all real, that has 4i and 2 as two of its zeros. 15 Find the values of a, (a ∈ R) for which ai is a solution to: a P(z) = z3 + 3z2 + 36z + 108 b P(z) = z3 + 6iz2 − 11z − 6i. 16 Factorise z3 + i over C. 17 a Show that P(1) = 0 for P(z) = z4 − (1 + 3i)z3 + 3(i − 1)z2 + (7 + i)z − 4 − i. b Find the polynomial Q(z) if P(z) = (z − 1)Q(z). c Determine the values of a ∈ C, b ∈ R if Q(z) is of the form Q(z) = (z − a)3 + b. 18 Factorise z4 + 2z3 + 8z2 + 10z + 15 over C given that z + 5 i is a factor. 19 Factorise P(z) = 9z3 + (9i − 12)z2 + (5 − 12i)z + 5i over C if P(−i) = 0. a – 11 -. 20 Determine the value of a ∈ R if – 3i is to be a zero of a + z 2 = -------------z2 Graphics Calculator tip! Roots of complex numbers Casio tip removed. 1. To select complex number mode, press MODE and select Radian mode; scroll down and select a+bi and press ENTER . 2. To find the cube roots of z = –2 – 2i, start by finding one of the roots as follows. Press MATH , select 4: 3 , enter (–2 – 2i) and press ENTER . So one cube root is z1 = 1 – i. 2π 3. Since cube roots occur at angles of ------ , the second cube root can be found by multi3 2π plying z1 by cis ------ . Scrolling shows that this root is 0.366 + 1.366i. 3 4π 4. The third cube root is found by multiplying z1 by cis ------ . Scrolling shows that this root 3 is –1.366 – 0.366i. Note that the cube root was recalled using 2nd [ENTRY] twice; 2π 4π cis ------ was also recalled using 2nd [ENTRY] twice and then edited to make it cis ------ . 3 3 Chapter 3 3G WORKED ORKED Example xample 40 WORKED ORKED Example xample 41 Complex numbers 153 Solving equations in C 1 Solve the following quadratic equations over C. a x2 + 2x + 5 = 0 b x2 − 8x + 25 = 0 d 4x2 − 12x + 13 = 0 e 4x2 − 32 x + 4 = 0 c 2 Solve the following equations over C. a z3 − z2 − z + 10 = 0 b z3 − 2z2 + 3z − 2 = 0 c 3 2 d 3z − 13z + 5z − 4 = 0 e 4z3 − 20z2 + 34z − 20 = 0 x2 − 14x + 149 = 0 2z3 − 7z2 + 10z − 8 = 0 3 For f(z) = z − 4, g(z) = z2 − z + 1 and h(z) = z3 − 5z2 + 5z − 4 show that f(z) × g(z) = h(z) and hence determine the values of z such that h(z) = 0. WORKED ORKED Example xample 42 4 Solve these equations over C. a x4 + 25x2 + 144 = 0 c 9z4 + 35z2 − 4 = 0 b z4 − 3z2 − 4 = 0 d 4x4 + 12x2 + 9 = 0 5 multiple ultiple choice The solutions to the equation (z − 3)2 + 4 = 0 are: A z = 2 + 3i, z = 2 − 3i B z = 3 − 2i, z = 3 + 2i C z = 3 + 4i, z = 3 − 4i D z = 4 − 3i, z = 4 + 3i E z = 9 + 16i, z = 9 − 16i WORKED ORKED Example xample a 1+ 7 Find b 11 + 60i 3i c 16 + 63i i in Cartesian form. program GC –TI 43 6 Find the square roots of each of the following in Cartesian form. Roots of a complex number WORKED ORKED Example xample 44 am progr –C asio π If one of the square roots of a(1 + i) is a cis --- , the other square root is: 8 7π 7π 7π B – a cis -----C a cis – -----A a cis -----8 8 8 9π 9π E – a cis -----D a cis -----8 8 GC 8 multiple ultiple choice Roots of a complex number 9 Use De Moivre’s theorem to solve the following equations, in polar form. b z2 = 4 + 4i c z3 = −4 + 4 3 i a z2 = 3 – i 3 3 d z =i e z = −1 − i f z6 + i = 0 1 --- 10 Find ( – 125i ) 3 and determine the value of the sum of the roots. 11 a Find the cube root of 64. b Show the results on an Argand diagram. 12 Solve the following equations in Cartesian form. b z4 = 25 c z6 = 64 a z4 = 16 45 13 Find all z satisfying a z5 = 1 b z8 + 1 = 0. WORKED ORKED Express your answers in polar form. d z6 = 27 ET SHE Work Example xample 3.2